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Redox Reaction - 1 - JEE MCQ


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30 Questions MCQ Test Chemistry for JEE Main & Advanced - Redox Reaction - 1

Redox Reaction - 1 for JEE 2024 is part of Chemistry for JEE Main & Advanced preparation. The Redox Reaction - 1 questions and answers have been prepared according to the JEE exam syllabus.The Redox Reaction - 1 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Redox Reaction - 1 below.
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Redox Reaction - 1 - Question 1

When a zinc rod is kept in a copper nitrate solution what happens?

Detailed Solution for Redox Reaction - 1 - Question 1

When zinc is placed in copper nitrate solution the intensity of the blue colour is produced and copper iron is deposited on zinc.

  • This is a Redox reaction between zinc and an aqueous solution of copper nitrate occurring in a beaker.
*Multiple options can be correct
Redox Reaction - 1 - Question 2

Which of the following electrodes will act as anodes, when connected to Standard Hydrogen Electrode?

Detailed Solution for Redox Reaction - 1 - Question 2

Determining Anodes when connected to the Standard Hydrogen Electrode

The Standard Hydrogen Electrode (SHE) is commonly used as a reference electrode in electrochemistry and has an electrode potential of 0V. The electrode with a lower reduction potential than the SHE will act as the anode (site of oxidation), while the electrode with a higher reduction potential than the SHE will act as the cathode (site of reduction).
A: Fe/Fe2+ E0= − 0.44
The reduction potential of this electrode is lower than that of the SHE, so it will act as the anode when connected to the SHE.
B: Al/Al3+ E0= - 1.66
The reduction potential of this electrode is lower than that of the SHE, so it will also act as the anode when connected to the SHE.
C: F2(g)/2F(aq) E0= + 2.87
The reduction potential of this electrode is higher than that of the SHE, so it will act as the cathode, not the anode, when connected to the SHE.
D: Cu/Cu2+ E0= + 0.34
The reduction potential of this electrode is higher than that of the SHE, so it will also act as the cathode, not the anode, when connected to the SHE.

Therefore, electrodes A: Fe/Fe2+ (E0= − 0.44) and B: Al/Al3+ (E0= - 1.66) will act as anodes when connected to the Standard Hydrogen Electrode.

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Redox Reaction - 1 - Question 3

In the reaction of metallic cobalt placed in nickel sulphate solution, therein is a competition for release of electrons At equilibrium, chemical tests reveal that both Ni+2 (aq) and Co+2 (aq) are present at moderate concentrations. The result is that:

Detailed Solution for Redox Reaction - 1 - Question 3

The reaction of metallic cobalt in a nickel sulfate solution involves a competition for the release of electrons. This means that the cobalt metal can react with the nickel ions in the solution, or the nickel can deposit on the cobalt metal.

At equilibrium, the reaction has balanced out with no net change in the concentration of the reactants and products. The fact that both Ni+2 (aq) and Co+2 (aq) are present at moderate concentrations at equilibrium signifies that neither forward nor reverse reactions are greatly favoured.

  • A: This option is incorrect because both reactants and products are present in moderate concentrations, indicating that neither is greatly favoured.
  • B: This statement is not correct either. Even though Co (s) and Ni+2 (aq) are part of the reaction, the fact that Co+2 (aq) is also present at moderate concentrations shows that they are not the only favoured species.
  • C: This option is also incorrect. Even though Co+2 (aq) and Ni (s) are part of the reaction, the fact that Ni+2 (aq) is also present at moderate concentrations shows that they are not the only favoured species.
  • D: This is the correct answer. When a reaction is at equilibrium, it means that the rate of the forward reaction equals the rate of the reverse reaction. Therefore, neither the reactants nor the products are greatly favoured. In other words, the concentrations of the reactants and products remain constant over time
Redox Reaction - 1 - Question 4

The highest value of oxidation number changes from 1 to 7

Detailed Solution for Redox Reaction - 1 - Question 4

Explanation of Highest Value of Oxidation Number Changes from 1 to 7

The highest value of oxidation number changes from 1 to 7 across the third period in the periodic table. This is due to the following reasons:

  • The Atoms of Transition Elements:Transition metals are those elements located in the d-block of the periodic table. They have varying oxidation states, but they do not usually reach an oxidation state of 7. Their oxidation states primarily range between +2 and +3, although some can reach states of +4 or +5.
  • The First Three Groups:The first three groups of the periodic table include alkali metals, alkaline earth metals, and boron group elements. These groups generally have oxidation states of +1, +2, and +3 respectively. They do not reach an oxidation state of 7.
  • In Alkaline Earth Metals:Alkaline earth metals are the elements in the second group of the periodic table. These elements generally have an oxidation state of +2 due to the presence of two valence electrons which are readily lost in chemical reactions.
  • Across the Third Period in the Periodic Table:The elements in the third period of the periodic table show a wider range of oxidation states, which can vary from +1 to +7. This is due to the presence of both s and p orbitals in their valence shell, which allows the elements to lose or gain more electrons in chemical reactions. Therefore, across the third period in the periodic table, the highest value of oxidation number changes from 1 to 7.
Redox Reaction - 1 - Question 5


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Redox Reaction - 1 - Question 7


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Redox Reaction - 1 - Question 8


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Redox Reaction - 1 - Question 9


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Redox Reaction - 1 - Question 10


Detailed Solution for Redox Reaction - 1 - Question 10


Redox Reaction - 1 - Question 11

Given balanced chemical equation for oxidation of phosphorus (III) sulfide by nitric acid. The products include NO and SO2. Find the value of a,b,c,d,e in the following equation.

a P4S6 + 44H+ b NO3 → cNO + dH3PO4 + e SO2 + 4H2O

Write your answer as (a + b + c + d + e)

Detailed Solution for Redox Reaction - 1 - Question 11


Redox Reaction - 1 - Question 12

In order to oxidise a mixture of one mole of each of FeC2O4, Fe2(C2O4)3, FeSO4 and Fe2(SO4)3 in acidic medium, the number of moles of KMnO4 required is -

Detailed Solution for Redox Reaction - 1 - Question 12


Redox Reaction - 1 - Question 13


Detailed Solution for Redox Reaction - 1 - Question 13


Redox Reaction - 1 - Question 14

4.08 g of a mixture of BaO and unknown carbonate MCO3 was heated strongly. The residue weighed 3.64 g.  This was dissolved in 100 mL of 1 M HCl.  The excess acid required 16 mL of 2.5 M  NaOH solution for complete neutralization.  Identify the metal M

Detailed Solution for Redox Reaction - 1 - Question 14

Redox Reaction - 1 - Question 15


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Redox Reaction - 1 - Question 16


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Redox Reaction - 1 - Question 17


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Redox Reaction - 1 - Question 18


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Redox Reaction - 1 - Question 19


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Redox Reaction - 1 - Question 20


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Redox Reaction - 1 - Question 21

How many grams of copper will be replaced in 2 L of a 1.50-M CuSO4 solution if the latter is made to react with 27.0 g of aluminium ? 

(Cu = 63.5, Al =27.0)

(3CuSO4 + 2Al ® Al2(SO4)3 + 3Cu)

Detailed Solution for Redox Reaction - 1 - Question 21


Redox Reaction - 1 - Question 22


Detailed Solution for Redox Reaction - 1 - Question 22


Redox Reaction - 1 - Question 23


Detailed Solution for Redox Reaction - 1 - Question 23


Redox Reaction - 1 - Question 24

In order to oxidise a mixture of one mole of each of FeC2O4, Fe2(C2O4)3, FeSO4 and Fe2(SO4)3 in acidic medium, the number of moles of KMnO4 required is -

Detailed Solution for Redox Reaction - 1 - Question 24


Redox Reaction - 1 - Question 25

4.08 g of a mixture of BaO and unknown carbonate MCO3 was heated strongly. The residue weighed 3.64 g.  This was dissolved in 100 mL of 1 M HCl.  The excess acid required 16 mL of 2.5 M  NaOH solution for complete neutralization.  Identify the metal M

Detailed Solution for Redox Reaction - 1 - Question 25

Redox Reaction - 1 - Question 26

A sample of Na2CO3. H2O weighing 1.24 g is added to 200 mL of a 0.1-N H2SO4 solution. The resulting solution becomes -

Detailed Solution for Redox Reaction - 1 - Question 26


Redox Reaction - 1 - Question 27


Detailed Solution for Redox Reaction - 1 - Question 27


Redox Reaction - 1 - Question 28


Detailed Solution for Redox Reaction - 1 - Question 28


Redox Reaction - 1 - Question 29

One mole of a mixture of CO and CO2 requires exactly 20 gram of NaOH in solution for complete conversion of all the CO2 into Na2CO3. How many grams more 

of NaOH would it require for conversion into Na2CO3 if the mixture (one mole) is completely oxidised to CO2 ?

Detailed Solution for Redox Reaction - 1 - Question 29

2NaOH + CO2 ® Na2CO3 + H2O


Redox Reaction - 1 - Question 30


Detailed Solution for Redox Reaction - 1 - Question 30


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