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Test: Carbohydrates - JEE MCQ


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20 Questions MCQ Test Chemistry for JEE Main & Advanced - Test: Carbohydrates

Test: Carbohydrates for JEE 2024 is part of Chemistry for JEE Main & Advanced preparation. The Test: Carbohydrates questions and answers have been prepared according to the JEE exam syllabus.The Test: Carbohydrates MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Carbohydrates below.
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Test: Carbohydrates - Question 1

In fructose, the possible optical isomers are

Detailed Solution for Test: Carbohydrates - Question 1
Fructose has 3 chiral centres and hence number of optical isomers are
Test: Carbohydrates - Question 2

Which of the following compounds is a recipient of the one carbon fragments that tetra hydro folate receives and transfers?

Detailed Solution for Test: Carbohydrates - Question 2

Formaldehyde  is a recipient of the one carbon fragments that tetra hydro folate receives and transfers 

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Test: Carbohydrates - Question 3

The term anomers of glucose refers to

Detailed Solution for Test: Carbohydrates - Question 3

defination of anomers ; cyclic carbohydrate which is equlibrium with it's open chain structure and different configration of H and OH at one chiral carbon is known as anomers.

Due to cyclic hemiacetal or cyclic hemiketal structures, all the pentose and hexoses exit in two stereosiomeric forms i.e,from in which the OH at C1 in aldose and C2 in ketoses lies towards the right and form in which it lies towards left. Thus glucose,fructose,ribose,etc.,all exist and form. Glucose exists in two forms -D glucose and -D glucose
As a result of cyclization the anomeric (C-1) becomes asymmetric and the newly formed - OH group may be either on left or on a right in Fischer projections thus resulting in the formation of two isomers (anomers). The isomers having - OH group to the left of the C-1 is designsted and other having - OH group on the right as .

Test: Carbohydrates - Question 4

Fisher projection formula of L - glucose is

Detailed Solution for Test: Carbohydrates - Question 4


According to the position of group at (carbon) C-2, we give D and L configuration. For right side -glucose For left side L-(-)-glucose

Test: Carbohydrates - Question 5
An organic compound with the formula forms a yellow crystalline solid with phenylhydrazine and gives a mixture of sorbitol and mannitol when reduced with sodium. Which among the following could be the compound?
Detailed Solution for Test: Carbohydrates - Question 5
Since the compound forms a yellow crystalline solid, i.e. osazone with phenylhydrazine, it may be an aldohexose or a ketohexose. Further, since on reduction, compound forms a mixture of sorbitol and mannitol, it must be a ketohexose, i.e. fructose. Recall that glucose on reduction gives only one alcohol glucitol (Sorbitol)
Test: Carbohydrates - Question 6
When -D-glucose and -D-glucose are dissolved in water in two separate beakers I and II respectively and allowed to stand, then -
Detailed Solution for Test: Carbohydrates - Question 6
-D-glucose or -D-glucose when dissolved in water and allowed to stand, following equilibrium is established.
-D-glucose Open chain form -D-glucose

Specific rotation of -form falls, while that of -form increases until a constant value of is reached at equilibrium. This phenomenon is known as mutarotation.
Test: Carbohydrates - Question 7
Which of the following pairs can be distinguished by Fehling's solution ?
Detailed Solution for Test: Carbohydrates - Question 7
Glucose is a hemiacetal, so in presence of a base (alkaline medium is provided by Fehling's solution) it can develop - CHO group in the form of open chain structure which responds Fehling's solution. Sucrose is a glycoside (acetal), i.e. its hemiacetal groups (one due to glucose and another due to fructose) are not free, so it can't attain -CHO group. Hence it will not respond Fehling's solution.
Test: Carbohydrates - Question 8
Identify the correct statements from the following:
When is hydrolysed, adenine and thymine are obtained in equal quantities.
When is hydrolysed, adenine and uracil are obtained in equal quantities.
Amylose is branched polymer with and glycosidic linkages.
Addison disease is due to the abnormal functioning of adrenal cortex.
Detailed Solution for Test: Carbohydrates - Question 8
Identify the correct statements from the following:
When is hydrolysed, adenine and thymine are obtained in equal quantities.
When is hydrolysed, adenine and uracil are obtained in equal quantities.
Amylose is branched polymer with and glycosidic linkages.
Addison disease is due to the abnormal functioning of adrenal cortex.
Test: Carbohydrates - Question 9
Observe the following statements.
I. Sucrose has glycosidic linkage.
II. Cellulose is present in both plants and animals.
III. Lactose contains D-galactose and D-glucose units.
Which of the following statements are correct?
Detailed Solution for Test: Carbohydrates - Question 9
Sucrose consists of glycosidic linkage
Lactose contains D-galactose and D-glucose units
Test: Carbohydrates - Question 10
Which of the following carbohydrates is not related to -glucose?
Detailed Solution for Test: Carbohydrates - Question 10
Inulin is a polysaccharide of fructose, while all others are polysaccharides of glucose ; although all the four has same molecular formula, .
Test: Carbohydrates - Question 11
Glucose-D has a great tendency to be converted into cyclic isomer. Which two carbon atoms get joined through ' ' to form this hemiacetal ?
Detailed Solution for Test: Carbohydrates - Question 11
Glucose exists as glucopyranose (a six membered ring structure) which is formed through and .
Test: Carbohydrates - Question 12

The enantiomer of -glucose is

Detailed Solution for Test: Carbohydrates - Question 12

In the D family the more dextrorotatory anomer is named In the family the more laevorotatory anomer is named

Test: Carbohydrates - Question 13


Compounds I and II may be grouped as

Detailed Solution for Test: Carbohydrates - Question 13

When structures I and II are epimers, it implies that these are epimers and diastereomers too.

Test: Carbohydrates - Question 14
Which of the following evolves carbon dioxide, on oxidation with periodate?
Detailed Solution for Test: Carbohydrates - Question 14
A ketonic group having group on both sides is removed as during oxidation with periodate.
Test: Carbohydrates - Question 15
Which of the following carbohydrates has a glycosidic linkage?
Detailed Solution for Test: Carbohydrates - Question 15

In maltose, two glucose residues are joined by a glycosidic linkage between the anomeric form of on one sugar and the hydroxyl oxygen atom on of the adjacent sugar. Such a linkage is called an glycosidic bond.

Test: Carbohydrates - Question 16
Number of chiral carbons in glucose is
Detailed Solution for Test: Carbohydrates - Question 16
As seen in image above, there are five chiral carbons in - -glucose.A chiral carbon has four different groups attached. -D-Glucose has no plane of symmetry, so all the carbon atoms are different. There are five chiral carbons.
Test: Carbohydrates - Question 17
A certain compound gives negative test with ninhydrin and positive test with Benedict's solution. The compound is
Detailed Solution for Test: Carbohydrates - Question 17
Protein gives blue-violet color with ninhydrin (2,2-dihydroxyindane-1,3-dione)
Carbohydrates gives brown red ppt.with benedict's solution (Alk. +Citrate ions)
A compound which gives a negative test with ninhydrin, it cannot be a protein or an amino acid. As, it gives a positive test with Benedict's solution. So, it must be a monosaccharide but not a lipid.
Test: Carbohydrates - Question 18
Glucose forms many derivatives. The derivative which will help to prove the furanose structure is
Detailed Solution for Test: Carbohydrates - Question 18
Glucose and fructose differ in the arrangement of atoms around the and carbon. When both of them react with three molecules of phenylhydrazine, the formation of osazone crystals makes the difference between the carbon atoms in their chain and hence, in such way it helps to prove the fructose structure.
Test: Carbohydrates - Question 19
The structure of Gly-Ala is
Detailed Solution for Test: Carbohydrates - Question 19

Test: Carbohydrates - Question 20
Glucose on oxidation with nitric acid yields
Detailed Solution for Test: Carbohydrates - Question 20
Glucose is oxidized by nitric acid and produce saccharic acid. Saccharic acid:- Saccharic acid, also called glucaric acid, is a chemical compound with the formula . It is derived by oxidizing a sugar such as glucose with nitric acid.
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