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Test: General Methods of Preparation


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10 Questions MCQ Test Chemistry Class 12 | Test: General Methods of Preparation

Test: General Methods of Preparation for NEET 2022 is part of Chemistry Class 12 preparation. The Test: General Methods of Preparation questions and answers have been prepared according to the NEET exam syllabus.The Test: General Methods of Preparation MCQs are made for NEET 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: General Methods of Preparation below.
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Test: General Methods of Preparation - Question 1

Chlorobenzene is prepared commercially by

Detailed Solution for Test: General Methods of Preparation - Question 1

The Raschig process is a chemical process for the production of hydroxylamine, developed by German chemist Friedrich Raschig. The main step in this process, patented by Raschig in 1887, is the reduction of nitrite with bisulfite towards hydroxylamine disulfonate, which is hydrolysed to hydroxylammonium sulfate.

Test: General Methods of Preparation - Question 2

 Which of the following is major product of following reaction?
CH3CH = CH2 + HBr 

Detailed Solution for Test: General Methods of Preparation - Question 2

The correct answer is Option D.
As HBr in the presence of a peroxide follows antimarkonikoff rule where the negative group should attach to the carbon having less no of hydrogen atoms.

Test: General Methods of Preparation - Question 3

Which of the following compound will not give addition reaction with bromine?

Detailed Solution for Test: General Methods of Preparation - Question 3

The correct answer is Option C.

For Addition reaction π bond is required .Iso butane has no pi Bond .

Test: General Methods of Preparation - Question 4

RCl + NaI   R-I+NaCl


This reaction is known as:

Detailed Solution for Test: General Methods of Preparation - Question 4

The correct answer is option D

where, X=Cl or Br.
This reaction is known as the Finkelstein reaction. Finkelstein's reaction is used to prepare alkyl iodides starting from alkyl chlorides and alkyl bromides.

Test: General Methods of Preparation - Question 5

 What is the order of reactivity of following halogen acids on alcohols?
HI, HBr, HCl

Detailed Solution for Test: General Methods of Preparation - Question 5

The correct answer is Option B.
Longer the bond length, lesser will be dissociation energy and hence, more reactivity. 
Among halogen acids, bond length increases from HCl to HI.
∴ Order of reactivity of halogen acids towards alcohol is
HI > HBr > HCl

Test: General Methods of Preparation - Question 6

Which of the following is formed by Swarts Reaction?

Detailed Solution for Test: General Methods of Preparation - Question 6

The correct answer is Option B.
When alkyl bromide or iodide are treated with metallic fluorides like AgF,HgF2, etc.They form alkyl fluoride. This reaction is called Swarts reaction and is an important method for the preparation of fluoro alkanes.

Test: General Methods of Preparation - Question 7

On reacting ethene with HCl we get:

Detailed Solution for Test: General Methods of Preparation - Question 7

hydrogen chloride adds to ethene to make chloroethane:

CH2=CH + HCl → CH3CH2Cl

Test: General Methods of Preparation - Question 8

 Which of the following is formed in reaction mechanism of halogenation of alkanes in presence of UV light?

Detailed Solution for Test: General Methods of Preparation - Question 8

Halogenation of alkanes in presence of UV light follows the free radical mechanis

Test: General Methods of Preparation - Question 9

 Which of the following is intermediate in Sandmeyer’s reaction?

Detailed Solution for Test: General Methods of Preparation - Question 9

The correct answer is option A
Diazonium salt
Aryl halides can be prepared by the decomposition of aryl diazonium salts in presence of copper halides solution dissolved in the corresponding halogen acid, the diazo group is replaced by a halogen atom. This reaction is known as the Sandmeyer reaction.

Test: General Methods of Preparation - Question 10

Which of the following is the major product of following reaction?
CH3CH = CH2 + HBr  in the presence of peroxide gives:

Detailed Solution for Test: General Methods of Preparation - Question 10

When 1-propene reacts with hydrogen bromide in the presence of peroxide, the more electronegative atom which is bromine gets attached to the carbon atom which has more number of hydrogen atoms. This reaction is named as Anti-Markovnikov's reaction.

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