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Test: General Properties of Group-16 - JEE MCQ


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14 Questions MCQ Test Chemistry for JEE Main & Advanced - Test: General Properties of Group-16

Test: General Properties of Group-16 for JEE 2024 is part of Chemistry for JEE Main & Advanced preparation. The Test: General Properties of Group-16 questions and answers have been prepared according to the JEE exam syllabus.The Test: General Properties of Group-16 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: General Properties of Group-16 below.
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Test: General Properties of Group-16 - Question 1

Non-metals combine with oxygen to form usually

Detailed Solution for Test: General Properties of Group-16 - Question 1
Acidic oxides
Test: General Properties of Group-16 - Question 2

The product A in the following reaction:
is

Detailed Solution for Test: General Properties of Group-16 - Question 2
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Test: General Properties of Group-16 - Question 3

On heating ozone, its volume

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On heating ozone, we get:

∴ Volume increases to 3/2 times

Test: General Properties of Group-16 - Question 4
Which one of the following statements is not correct?
Detailed Solution for Test: General Properties of Group-16 - Question 4
In oxygen, the bond is pure double bond but in ozone, it is partial single and double bond.
Test: General Properties of Group-16 - Question 5
Tailing of mercury test can be used for which of the following gas?
Detailed Solution for Test: General Properties of Group-16 - Question 5
When ozone is passed through mercury, it loses its meniscus and sticks to the glass due to the formation of mercurous oxide So, mercury when starts moving on a Surface it leaves a tail and thes is what tailing of mercury is called.
Test: General Properties of Group-16 - Question 6

By which of the following methods, can't synthesized?

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is not peroxy compound)

At anode :
Peroxo sulphate on hydrolysis, produces .

Test: General Properties of Group-16 - Question 7
A green coloured solution of same salt changes its colour to light pink on passing ozone through it. Which of the following species represent pink and green colour respectively?
Detailed Solution for Test: General Properties of Group-16 - Question 7
Ozone is a strong oxidizing agent as it has a tendency to readily dewmpose on heating lo give a molecule of oxygen and nascent oxygen,
The green coloured solution can be potassium manganate solution having manganate ion .
The light pink solution can be Potassium permonganate having permangate ion ,
Ozone oxidizes (green in colour) to (Light pink in colour).
Test: General Properties of Group-16 - Question 8

Which of the following on thermal decomposition gives oxygen gas ?

Detailed Solution for Test: General Properties of Group-16 - Question 8

2Ag2O(s) ⟶ 4Ag(s)+O2( g)
2 Pb3O4(s) ⟶ 6PbO(s) + O2( g)
2PbO2(s) ⟶ 2PbO(s) + O2( g)

Test: General Properties of Group-16 - Question 9

Correct order of bond length (increasing) in and is

Detailed Solution for Test: General Properties of Group-16 - Question 9


Bond strength → Double bond > Partial double bond > single bond
Bond length → Double bond < < Single bond
So, Bond length (0−0) order is → O< O< H2O2 

Test: General Properties of Group-16 - Question 10
Which of the following statements regarding ozone is not correct?
Detailed Solution for Test: General Properties of Group-16 - Question 10
The bond length in ozone is intermediate between those of single and double bonds. The bond angle is is with distance .
Test: General Properties of Group-16 - Question 11
Which of the following oxidation state of oxygen is not observed in its compounds
Detailed Solution for Test: General Properties of Group-16 - Question 11
do not show oxidation state because its valency is only . electrons takes more energy to ionize.
Test: General Properties of Group-16 - Question 12
An organic compound containing sulphur is estimated by Carius method in which fuming is used to convert into :
Detailed Solution for Test: General Properties of Group-16 - Question 12
is converted to .
Test: General Properties of Group-16 - Question 13

Identify the correct statements from the following.
(i) Oxygen shows and +2 oxidation states.
(ii) The thermal stability of and follows the order  Se.
(iii) The reducing nature of and follows the order

Detailed Solution for Test: General Properties of Group-16 - Question 13

Oxygen shows and +2 oxidation states.
(i) Oxygen shows -2 oxidation states in most of its compound while it shows ( - 1) O.S. in peroxides (like ), +1 in and +2 in .
Thus, it show and +2 oxidation states.
(ii) The thermal stability of and follows the order This is because, on going down the group, the size of the central atom increases and therefore, its tendency to form stable covalent bond with hydrogen decreases. As a result, the bond strength decreases and therefore, thermal stability decreases.
(iii) The reducing nature of and Te follows the order

This is due to the decrease in thermal stability of the hydride greater the unstability of hydrides, the greater is its reducing character.

Test: General Properties of Group-16 - Question 14
Photochemical smog consists of excessive amount of , in addition to aldehydes, ketones, peroxy-acetyl nitrile (PAN), and so forth, is:
Detailed Solution for Test: General Properties of Group-16 - Question 14
Photochemical smong also contains .
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