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Liquid state - 2 - JEE MCQ
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30 Questions MCQ Test Chemistry for JEE Main & Advanced - Liquid state - 2
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Liquid state - 2 - Question 3
Molal depression constant for a solvent is 4.0 K kg mol–1. The depression in the freezing point of the solvent for 0.03 mol kg–1 solution of K2OS4 is : (Assume complete dissociation of the electrolyte)
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Liquid state - 2 - Question 10
The vapour pressures of pure liquids A and B are 400 and 600 mmHg, respectively at 298 K. On mixing the two liquids, the sum of their initial volumes is equal to the volume of the final mixture. The mole fraction of liquid B is 0.5 in the mixture. The vapour pressure of the final solution, the mole fractions of components A and B in vapour phase, respectively are -
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Elevation of boiling point of 1 molar aqueous glucose solution (density = 1.2 g/ml) is
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