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Solid State - 2 - JEE MCQ
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30 Questions MCQ Test Chemistry for JEE Main & Advanced - Solid State - 2
Solid State - 2 for JEE 2024 is part of Chemistry for JEE Main & Advanced preparation. The Solid State - 2 questions and answers have been
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Solid State - 2 - Question 1
If Z is the number of atoms in the unit cell that represents the closest packing sequence ABC ABC … , the number of tetrahedral voids in the unit cell is equal to -
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Solid State - 2 - Question 3
An element X (At. wt. = 80 g/mol) having fcc structure, calculate no. of unit cells in 8 gm of X :
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Solid State - 2 - Question 5
The radius of the Na+ is 95 pm and that of Cl– ion is 181 pm. Predict the co-ordination number of Na+
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Solid State - 2 - Question 8
If the distance between Na+ and Cl–1 ions in NaCl crystal is 265 pm, then edge length of the unit cell will be ?
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Solid State - 2 - Question 14
In a normal spinel types structure, the oxide ions are arranged in ccp whereas 1/8 tetrahedral holes are occupied by Zn2+ ions and 50% of octahedral holes are occupied by Fe3+ ions. The formula of the compound is –
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Solid State - 2 - Question 15
In an FCC crystal, which of the following shaded planes contains the following type of arrangement of atoms ?
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Solid State - 2 - Question 16
Element ‘B’ forms ccp structure and ‘A’ occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is -
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Solid State - 2 - Question 21
TlAl(SO4)2 . xH2O is bcc with 'a'= 1.22 nm. If the density of the solid is 2.32 g/cc, then the value of x is (Given : NA = 6 × 1023; at. wt. : Tl = 204, Al = 27, S = 32, O = 16, H = 1)
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Solid State - 2 - Question 26
A group IV A element with a density of 11.35 g/cm3 crystallise in a face centered cubic lattice whose unit cell edge length is 4.95Å. Calculate its atomic mass -
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