1 Crore+ students have signed up on EduRev. Have you? 
An Indian rubber cube of side 10 cm has one side fixed while a tangential force of 1800 N is applied to the opposite side. Find the shear strain produced. Take η = 2 x 10^{6} N/ m^{2}.
The length of the wire is increased by 1 mm on the application of a given load. In a wire of the same material but of length and radius twice that of the first, on application of the same force, extension produced is
Young's Modulus of elasticity =stress/strain
Y= [F/a/△l/l] or Y= [Fl/a△l]
or △l= [Fl/aY] = Fl/ πr^{2}Y
In the given problem, △l∝ l/ r^{2}
When both l and r are doubled, △l is halved.
Young’s modulus is defined as the ratio of longitudinal stress to longitudinal strain. Which of the following is the unit of Young’s modulus?
Stress = Force per area and strain is unit less.
Therefore in CGS units dyne per cm square.
Hence A is correct.
The volume of a spherical body is decreased by 10^{3}% when it is subjected to pressure of 40 atmospheres. Find the bulk modulus of body.
(1 atm = 1.01 x 10^{3} N/m^{2}).
We know that magnitude of bulk modulus
K=[P/(dV/V)]
Now, percentage change in volume is. 10^{3} %
Therefore, (dV/V)x100=10^{3}
So, dV/V=10^{5}
Hence, k is,
K=40atm/10^{5}=40x1.01x10^{5} /10^{5} =4.04x10^{11} N/m^{2 }
The materials which have the same elastic properties in all directions are called __________.
Same elastic properties in all direction is called the homogenity of a material.
As the temperature increases, the interatomic distance also increases. So, it results in an increase in the area (stress = force /area). As the area increases stress decreases, this results in a decrease in Young's modulus.
What type of stress is produced in a body when the deforming force produces sheer strain?
When the direction of the deforming force or external force is parallel to the crosssectional area, the stress experienced by the object is called shearing stress or tangential stress. This results in the change in the shape of the body.
Modulus of rigidity is defined as the ratio of Shear stress to shear strain.
E=stress/strain
Strain x E= Stress
An iron bar of length l cm and cross section A cm^{2} is pulled by a force F dynes from the ends so as to produce an elongation l cm. Which of the following statements is correct?
F =AYΔl/L
Δl = FL/AY
126 videos449 docs210 tests

Use Code STAYHOME200 and get INR 200 additional OFF

Use Coupon Code 
126 videos449 docs210 tests









