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At what point is the electric field intensity due to a uniformly charged spherical shell is maximum?
A charge q is placed at the centre of the open end of cylindrical vessel whose height is equal to its radius. The electric flux of electric field of charge q through the surface of the vessel is
If an excess charge is placed on an isolated conductor, then, that amount of charge
The charge enclosed by a spherical Gaussian surface is 8.85 X 10^{8} C.What will be the electric flux through the Surface?
If the electric field is given by; calculate the electric flux through as surface of area 10 units lying in yz plane.
The flux associated with a spherical surface is 10^{4} N m^{2}C^{1}. What will be the flux, if the radius of the spherical shell is doubled?
The electric field intensity due to a sphere (solid or hollow) at an external point varies as
105 videos425 docs114 tests

Irodov Solutions: Constant Electric Field in Vacuum Doc  29 pages 
Electric Charges & Fields in One Shot (NCERT) Video  132:00 min 
HC Verma Solutions: Chapter 30  Gauss Law Doc  6 pages 
DC Pandey Solutions: Electrostatics Doc  16 pages 
DPP for NEET: Daily Practice Problems, Ch 33: Electrostatics 2 Doc  4 pages 
105 videos425 docs114 tests

Irodov Solutions: Constant Electric Field in Vacuum Doc  29 pages 
Electric Charges & Fields in One Shot (NCERT) Video  132:00 min 
HC Verma Solutions: Chapter 30  Gauss Law Doc  6 pages 
DC Pandey Solutions: Electrostatics Doc  16 pages 
DPP for NEET: Daily Practice Problems, Ch 33: Electrostatics 2 Doc  4 pages 