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# Test: Introductory Vectors

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## 10 Questions MCQ Test Physics Class 11 | Test: Introductory Vectors

Test: Introductory Vectors for NEET 2022 is part of Physics Class 11 preparation. The Test: Introductory Vectors questions and answers have been prepared according to the NEET exam syllabus.The Test: Introductory Vectors MCQs are made for NEET 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Introductory Vectors below.
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Test: Introductory Vectors - Question 1

### Find the area of parallelogram formed by Detailed Solution for Test: Introductory Vectors - Question 1 Area of Parallelogram = breadth x height⟂ = |(A x B)|

Here, A = i - j + k

And,  B = -3i + 4j -k = i (1-4) -j (-3+1) +k (4-3)

=> (A x B) = -3i +2j +k Test: Introductory Vectors - Question 2

### A body is projected horizontally from the top of a cliff with a velocity of 9.8m/s. What time elapses before horizontal and vertical velocities become equal? Take g = 9.8m/s2

Detailed Solution for Test: Introductory Vectors - Question 2

Horizontal velocity at any instant, vx = u = 9.8m/s
Vertical velocity at any instant, vy = 0 + gt = 9.8t
9.8 = 9.8t
t = 1s

Test: Introductory Vectors - Question 3

### Two vectors are equal if and only if

Detailed Solution for Test: Introductory Vectors - Question 3

Two vectors are equal if and only if they have the same magnitude and the same direction.
Hence, Option D is correct

Test: Introductory Vectors - Question 4

A cyclist moves along a circular path of radius 70m. If he completes one round in 11s, calculate total length of path.

Detailed Solution for Test: Introductory Vectors - Question 4

Radius of the circular path, r = 70m
Time takes to complete one round, t = 11s
Total length of the path, s = 2πr = 2*22/7*70 = 440m

Test: Introductory Vectors - Question 5

Find the odd one out:

Detailed Solution for Test: Introductory Vectors - Question 5

Force, area and velocity all are a set of different or the same fundamental quantities multiplied or divided together while current itself is a fundamental quantity and can be expressed in terms of any other.

Test: Introductory Vectors - Question 6

An object thrown from an aeroplane is an example for

Detailed Solution for Test: Introductory Vectors - Question 6

A projectile is the name given to any body which once thrown into space with some initial velocity, moves thereafter under the influence of gravity alone without being propelled by an engine or fuel. The path followed by a projectile is called its trajectory.

Test: Introductory Vectors - Question 7

The vector product of parallel vectors is always:

Detailed Solution for Test: Introductory Vectors - Question 7

The vector product of two vectors depends upon the sine of the angle between the vectors and when the vectors are parallel the sine component would be zero hence the resultant is a null vector.

Test: Introductory Vectors - Question 8

Given, and . The unit vector of is

Detailed Solution for Test: Introductory Vectors - Question 8 Test: Introductory Vectors - Question 9

If what is the angle between and Detailed Solution for Test: Introductory Vectors - Question 9

We know that for two vectors P and Q
P.Q = |P||Q| cos a
And PxQ = |P||Q| sin a
Where a is angle between them
When P.Q = PxQ
We get sin a = cos a
Thus a = 450

Test: Introductory Vectors - Question 10

A particle of mass 10 g moves along a circle of radius 6.4 cm with a constant tangential acceleration. What is the magnitude of this acceleration, if the kinetic energy of the particle becomes equal to 8 x 10-4 J by the end of the second revolution after the beginning of the motion?

Detailed Solution for Test: Introductory Vectors - Question 10

kinetic energy =8×10−4J

or, (1/2)​​mv2=8×10−4

or, (1/2)​×10×10−3v²=8×10−4

or, v2=16×10−2

=>v=0.4m/s

initial velocity of particle,   u=0m/s

we have to find Tangential acceleration at the end of 2nd revolution.

total distance covered, s=2(2πr)=4πr

so, v2=2as ## Physics Class 11

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## Physics Class 11

126 videos|449 docs|210 tests

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