Test: Standing Waves
5 Questions MCQ Test Physics Class 11 | Test: Standing Waves
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A node is a point along the medium of no displacement. The point is not displaced because destructive interference occurs at this point.
A cylindrical tube, open at both ends, has a fundamental frequency f in air. The tube is dipped vertically in water so that half of it is in water. The fundamental frequency of the air-column is now:
As we know, f=v/2l
Now, it will act as one end and one end closed.
So, f0=v/2l’=v/4½=v/2l=f
Fundamental note in open pipe (v1 = ν/2L) has _________ the frequency of the fundamental note in closed organ pipe (v2 = ν/4L).
Let L be a length of the pipe,
The fundamental frequency of closed pipe is
v2=ν/4L .....(i)
where ν is the speed of sound in air.
Fundamental frequency of open pipe of same length is
v1=ν/2L .....(ii)
After dividing v1 with v2,
v1/v2= ν/2L/ ν/4L
v1=2v2
In an experiment to find the speed of waves in a rope, a standing wave pattern is established as shown in diagram below. The vibrating end of rope makes 90 vibrations per minute. The speed of the waves is
If there are exactly 90 vibrations in 60.0 seconds, then there is a frequency of 1.5 Hz. The diagram shows 1.5 waves in 6.0-meters of rope; thus, the wavelength is 4.0 meters. Now use the equation v=f*w to calculate the speed of the wave. Proper substitution yields 6.0 m/s.
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