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Test: Maxima and Minima - JEE MCQ


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5 Questions MCQ Test Physics for JEE Main & Advanced - Test: Maxima and Minima

Test: Maxima and Minima for JEE 2024 is part of Physics for JEE Main & Advanced preparation. The Test: Maxima and Minima questions and answers have been prepared according to the JEE exam syllabus.The Test: Maxima and Minima MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Maxima and Minima below.
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Test: Maxima and Minima - Question 1

What is the maximum or minimum point for the curve y = x2 − 4 ?

Detailed Solution for Test: Maxima and Minima - Question 1

First find the first and second derivatives:

This is positive, so we have a minimum
Therefore, there is a minimum at (0,-4)

Test: Maxima and Minima - Question 2

What is the maximum or minimum point for the curve y = -3x2 − 12x + 5 ?

Detailed Solution for Test: Maxima and Minima - Question 2

First find the first and second derivatives:

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Test: Maxima and Minima - Question 3

A ball is thrown in the air. Its height, h m, at any time t seconds is given by: h = 5t(4 − t)

What is the maximum height reached by the ball?

Detailed Solution for Test: Maxima and Minima - Question 3

h = 5t(4 − t) = 20t − 5t2

First find the first and second derivatives:

Test: Maxima and Minima - Question 4

What is the local minimum value of the function f(x) = x3(x + 4)

Detailed Solution for Test: Maxima and Minima - Question 4

First find the first and second derivatives:

to find the maximum or minimum, put f'(x)  = 0

Test: Maxima and Minima - Question 5

What is the local maximum value of the function f(x) = 2x3 − 24x − 32

Detailed Solution for Test: Maxima and Minima - Question 5

First find the first and second derivatives:

to find the maximum or minimum, put f'(x)  = 0


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