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ANSWER : c
Solution : [a×b b×c c×a]
= (a×b) . [(b×c) * (c×a)]
= (a×b) [(b×c) . a(c)  (b×c) . c]
= (a×b) [(b×c) . a(c)  0]
= [(a×b) . c] [(b×c) . a]
= [a b c] [(b c a]
=  [a b c] [(a c b]
= [a b c] [(a b c ] => [a b c]^2
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