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Test: Cross Product - JEE


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5 Questions MCQ Test Mathematics (Maths) Class 12 - Test: Cross Product

Test: Cross Product for JEE 2023 is part of Mathematics (Maths) Class 12 preparation. The Test: Cross Product questions and answers have been prepared according to the JEE exam syllabus.The Test: Cross Product MCQs are made for JEE 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Cross Product below.
Solutions of Test: Cross Product questions in English are available as part of our Mathematics (Maths) Class 12 for JEE & Test: Cross Product solutions in Hindi for Mathematics (Maths) Class 12 course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: Cross Product | 5 questions in 10 minutes | Mock test for JEE preparation | Free important questions MCQ to study Mathematics (Maths) Class 12 for JEE Exam | Download free PDF with solutions
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Test: Cross Product - Question 1
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If | a | = 2, | b | = 5 and | a × b | = 8, thencan be equal to

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Test: Cross Product - Question 2
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If  are unit vectors along X-axis, Y-axis and Z-axis respectively, then

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As we know that,

Test: Cross Product - Question 3
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The area of triangle whose adjacent sides are is :

Detailed Solution for Test: Cross Product - Question 3

Area of triangle = ½(a * b)
a = (1, 0, -2)   b = (2, 3, 1)
= i(0 + 6) + j(-4 - 1) + k(3 - 0)
= 6i - 5j + 3k
|a * b| = (36 + 25 + 9)½
|a * b| = (70)½
Area of triangle = ½(a * b)
= [(70)½]/2

Test: Cross Product - Question 4
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The value of  is:
Detailed Solution for Test: Cross Product - Question 4

 i.(j * k) + j.(k * i) + k(i * j)
= i.(i) + j.(j) + k.(k)
= 1 + 1 + 1 
= 3

Test: Cross Product - Question 5
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The area of parallelogram whose sides areis:​
Detailed Solution for Test: Cross Product - Question 5

A = {(1, -3, 4)}    B = {(3, 1, -2)}
A * B = {(i^(6-4) - j^(-2 -12) + k^ (1+9)} 
= 2i^ + 14j^ + 10k^
Area = [(2)2 + (14)2 + (10)2]½
= (300)½
= 10(3)½ sq unit

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