The length of the semilatusrectum of an ellipse is one third of its major axis, its eccentricity would be
In the ellipse x^{2} + 3y^{2} = 9 the distance between the foci is
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The eccentricity of an ellipse, with its centre at the origin, is 1/2. If one of the directrix is x = 4, then the equation of the ellipse is:
The eccentricity of an ellipse whose latus rectum is equal to distance between foci is:
The foci of the ellipse 25 (x + 1)^{2} + 9(y + 2)^{2} = 225 are at:
The equation of the ellipse whose one focus is at (4, 0) and whose eccentricity is 4/5 is:
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209 videos443 docs143 tests
