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This mock test of Test: Strain Energy & Resilience Level - 2 for Mechanical Engineering helps you for every Mechanical Engineering entrance exam.
This contains 10 Multiple Choice Questions for Mechanical Engineering Test: Strain Energy & Resilience Level - 2 (mcq) to study with solutions a complete question bank.
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QUESTION: 1

Consider the following statements.

(P) Hardness is the resistance of a material to indentation.

(Q) Elastic modulus is a measure of ductility.

(R) Deflection depends on stiffness.

(S) The total area under the stress-strain curve is a measure of resilience.

Among the above statements, the correct ones are

Solution:
Percentage elongation is a measure of ductility. The total area under the stress-strain curve is a measure of modulus of toughness.

QUESTION: 2

Strain energy is used to find

Solution:

QUESTION: 3

Which one of the following statements is correct? The work done in stretching an elastic string varies

Solution:

QUESTION: 4

The maximum stress induced in a body if the load ‘P’ is applied with impact upon an area of cross section ‘A’ is (When h = Height through which the load falls, E = Modulus of rigidity, L = Length of the body)

Solution:

QUESTION: 5

Which of the following gives the correct expression for strain energy stored in a beam of length L and of uniform cross section having moment of inertia ‘I’ and subjected to constant bending moment M?

Solution:

QUESTION: 6

A bar having length L and uniform cross section with area A is subjected to both tensile force P and torque T. If G is the shear modulus and E is the Young’s modulus, the internal strain energy stored in the bar is

Solution:
Internal strain energy

=

=

QUESTION: 7

An axial load of 100kN is applied onto a bar of length 3 m and cross-sectional area of 100 mm2. If E = 200 kN/mm^{2} the total strain energy in the bar is equal to

Solution:
Axial load, P = 100 × 10^{3}N

Length, L = 3000 mm ^{2}

Cross section area, A = 100 mm E = 200 × 10^{3} N/mm^{2}

U =

=

=

= 750000 Nmm

QUESTION: 8

A circular bar L (long) in m and d (diameter) in m is subjected to tensile force of F in kN. Then the strain energy, U will be (Where, E is the modulus of elasticity in kN.m^{2})

Solution:

℧ =

=

=

QUESTION: 9

The strain energy in bar of 20 mm diameter, 1.0 m length, and young’s modulus 200.0 GPa under an axial force of 100.0 N is

Solution:
Diameter, d = 20 mm

Length, L = 1000 mm

E = 200 × 10^{3} MPa

P = 100N

U =

=

=

U = 0.0796 Nmm

QUESTION: 10

If σ and E for a body of volume 2 × 105 mm^{3} are 10 N/mm^{2} and 1 × 10^{5} N/mm^{2}, Resilience of the body is

Solution:
σ = 10N/mm^{2}

E = 1 × 105N/mm^{2}

V = 2 × 105N/mm3

U =

U =

= 100 Nmm

### Strain Energy

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### Strain Energy

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