Test: Bearing Capacity & Shallow Foundation - Civil Engineering (CE) MCQ

Test: Bearing Capacity & Shallow Foundation - Civil Engineering (CE) MCQ

Test Description

10 Questions MCQ Test GATE Civil Engineering (CE) 2025 Mock Test Series - Test: Bearing Capacity & Shallow Foundation

Test: Bearing Capacity & Shallow Foundation for Civil Engineering (CE) 2024 is part of GATE Civil Engineering (CE) 2025 Mock Test Series preparation. The Test: Bearing Capacity & Shallow Foundation questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Test: Bearing Capacity & Shallow Foundation MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Bearing Capacity & Shallow Foundation below.
Solutions of Test: Bearing Capacity & Shallow Foundation questions in English are available as part of our GATE Civil Engineering (CE) 2025 Mock Test Series for Civil Engineering (CE) & Test: Bearing Capacity & Shallow Foundation solutions in Hindi for GATE Civil Engineering (CE) 2025 Mock Test Series course. Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free. Attempt Test: Bearing Capacity & Shallow Foundation | 10 questions in 30 minutes | Mock test for Civil Engineering (CE) preparation | Free important questions MCQ to study GATE Civil Engineering (CE) 2025 Mock Test Series for Civil Engineering (CE) Exam | Download free PDF with solutions
Test: Bearing Capacity & Shallow Foundation - Question 1

The net ultimate bearing capacity of a purely cohesive soil

Detailed Solution for Test: Bearing Capacity & Shallow Foundation - Question 1

As per Terzaghi's bearing capacity equation,
qult = cNc + γDf Nq + 0.5 γBNγ
For a purely cohesive soil,
Nq = 1 and Nγ = 0
∴ qult = cNc + γDf
But qnet,ult = qult - γDf
⇒ qnet,ult = cNc + γDf - γFf ⇒ qnet,ult = cNc

Test: Bearing Capacity & Shallow Foundation - Question 2

Consider the following statements: increasing width of footing results in 1. Increase in settlement of a consolidating clay layer 2. Increase in bearing capacity of sandy soils 3. Decrease in bearing capacity of clays Which of these statements is/are correct?

Detailed Solution for Test: Bearing Capacity & Shallow Foundation - Question 2

Changing the width of footing does not affect the bearing capacity of clays.

 1 Crore+ students have signed up on EduRev. Have you?
Test: Bearing Capacity & Shallow Foundation - Question 3

If an SPT test gave the average blow count of 32 in fine sand below water table, then what is the corrected value of blow count?

Detailed Solution for Test: Bearing Capacity & Shallow Foundation - Question 3

Corrected SPT value

Test: Bearing Capacity & Shallow Foundation - Question 4

Which factors influence the bearing capacity of a purely cohesionless soil?
1. Relative density of soil
2. Width and depth of footing
3. Unit weight of soil
Select the correct answer using the codes given below:

Test: Bearing Capacity & Shallow Foundation - Question 5

Match List-I (Types of foundation) with List-ll (Suitability) and select the correct answer using the codes given below the lists:
List-I
B. Under reamed piles
C. Raft foundation
D. Deep foundation
List-ll
1. Soft clay for 20 m followed by hard rock stratum
2. Up to 3 m black cotton soil followed by medium dense sand
3. Compact sand deposit extending to great depth
4. Loose sand extending to great depth

Detailed Solution for Test: Bearing Capacity & Shallow Foundation - Question 5

In the case of loose sand there may be loose pockets causing differential settlements. Raft foundations reduce the differential settlements and higher, allowable soil pressure may be used for design of rafts on loose sands.
Under-reamed piles are suitable to bear the swelling pressure caused by black cotton soil.

Test: Bearing Capacity & Shallow Foundation - Question 6

A test plate 30 cm square, settles by 12 mm under a load of 4.5 kN in a sandy soil. By how much will a footing 2 m x 2 m subjected to a load of 200 kN settle?

Detailed Solution for Test: Bearing Capacity & Shallow Foundation - Question 6

Load intensity for 4.5 kN load on 30 cm square plate will be,

Load intensity for 200 kN load on 2 m x 2 m footing will be,

Since load intensity is same so,

Test: Bearing Capacity & Shallow Foundation - Question 7

In which one of the following zones is a logarithmic spiral shape of failure surface assumed in the case of bearing capacity analysis of c-ϕ soils?

Detailed Solution for Test: Bearing Capacity & Shallow Foundation - Question 7

According to Terzaghi there are three zones:

Zone-1: Elastic zone of wedge shape located beneath the loaded strip wherein the major principal stress are vertical. This remains in elastic equilibrium and behaves as if it were a part of footing itself and ∠CAB = ∠CBA = ϕ.
Zone-2: Radial shear zone where arc CD is logarithmic spiral. (Circular when ϕ = 0).
Zone-3: It is called Rankine passive zone. An overburden pressure q = γDf acts as a surcharge on this zone.

Test: Bearing Capacity & Shallow Foundation - Question 8

The bearing capacity factors Nc, Nq and Nare functions of

Detailed Solution for Test: Bearing Capacity & Shallow Foundation - Question 8

Terzaghi’s bearing capacity factors Nc, Nq and Nγ are function of angle of friction only.

Test: Bearing Capacity & Shallow Foundation - Question 9

When a load test was conducted by putting a 60 cm square plate on top of a sandy deposit, the ultimate bearing capacity was observed as 60 kN/m2. What is the ultimate bearing capacity for a strip footing of 1.2 m width to be placed on the surface of the same soil?

Detailed Solution for Test: Bearing Capacity & Shallow Foundation - Question 9

According to Terzaghi,
qnu = 0.5 γB Nγ for strip footing
= 0.4 γB Nγ for square footing Using the above equations,

For strip footing,
qnu = 0.5 x 1.2 x 250 = 150 kN/m2

Test: Bearing Capacity & Shallow Foundation - Question 10

The ultimate bearing capacity of a square footing on surface of a saturated clay having unconfined compression strength of 50 kN/m2 (using Skempton’s equation) is

Detailed Solution for Test: Bearing Capacity & Shallow Foundation - Question 10

qnu = cuNc
where cu = 50/2 = 25 kN/m2
Nc = 6(1 + 0.2 Df/B)
for Df = 0, we get Nc = 6
∴ qnu = 25 x 6 = 150 kN/m2

GATE Civil Engineering (CE) 2025 Mock Test Series

31 docs|280 tests
Information about Test: Bearing Capacity & Shallow Foundation Page
In this test you can find the Exam questions for Test: Bearing Capacity & Shallow Foundation solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Bearing Capacity & Shallow Foundation, EduRev gives you an ample number of Online tests for practice

GATE Civil Engineering (CE) 2025 Mock Test Series

31 docs|280 tests