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Complex Number MSQ - Physics MCQ


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10 Questions MCQ Test Topic wise Tests for IIT JAM Physics - Complex Number MSQ

Complex Number MSQ for Physics 2024 is part of Topic wise Tests for IIT JAM Physics preparation. The Complex Number MSQ questions and answers have been prepared according to the Physics exam syllabus.The Complex Number MSQ MCQs are made for Physics 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Complex Number MSQ below.
Solutions of Complex Number MSQ questions in English are available as part of our Topic wise Tests for IIT JAM Physics for Physics & Complex Number MSQ solutions in Hindi for Topic wise Tests for IIT JAM Physics course. Download more important topics, notes, lectures and mock test series for Physics Exam by signing up for free. Attempt Complex Number MSQ | 10 questions in 45 minutes | Mock test for Physics preparation | Free important questions MCQ to study Topic wise Tests for IIT JAM Physics for Physics Exam | Download free PDF with solutions
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Complex Number MSQ - Question 1

Detailed Solution for Complex Number MSQ - Question 1

*Multiple options can be correct
Complex Number MSQ - Question 2

If α,β be the roots o f the equation μ2 - 2μ + 2 = 0 and if cot θ = x + 1, then is equal to :

Detailed Solution for Complex Number MSQ - Question 2



The correct answers are: 

*Multiple options can be correct
Complex Number MSQ - Question 3

The complex numbers associated with the vertices A, B, C of Δ ABC are e, ω,ωrespectively, where ω is imaginary cube root of unity and cos θ > Re (ω), then the complex number representing the point where angle bisector of ∠ A meets the circumcircle of triangle, is :

Detailed Solution for Complex Number MSQ - Question 3



⇒ A lies on major are BC

∴ angle subtended by are  at O

The correct answers are: ω + ω2,-1

Complex Number MSQ - Question 4

If ω  is an imaginary cube root of unity, then (1+ω−ω2)7 equals

Detailed Solution for Complex Number MSQ - Question 4

Correct option is D)

Since w is the imaginary cube root of unity
w3=1 and
1+w+w2=0 ...(i)
Hence
 (1+w−w2)7
= ((1+w)−w2)7
= (−w2−w2)7 ...from i
= (−2w2)7
= −128w14
= −128w12.w2
= −128(w3)4.w2
= −128w2 ...since w3=1.

*Multiple options can be correct
Complex Number MSQ - Question 5

Which of the following statement are true.

Detailed Solution for Complex Number MSQ - Question 5


S3 : Since z1 z2 are 8th roots of unity


∴ product of all the roots = (-1)5 . 1 = -1
The correct answers are: S2 : If ω is an imaginary fifth root of unity, then   If z1 and z2 are two of the 8th roots o f unity, such that  is least positive, then  S4 : The product of all the fifth roots of-1 is equal to-1

*Multiple options can be correct
Complex Number MSQ - Question 6

If z1 lies on |z| = 1 and  z2  lies on |z| = 2, then :

Detailed Solution for Complex Number MSQ - Question 6


The correct answers are: ,,

*Multiple options can be correct
Complex Number MSQ - Question 7

lf  then roots of the equation  are:

Detailed Solution for Complex Number MSQ - Question 7


The correct answers are: z0,2,

*Multiple options can be correct
Complex Number MSQ - Question 8

Let z1,and z2 be non-zero complex numbers satisfying  Then the triangle made by points with vertices at origin, z1 and z2 is :

Detailed Solution for Complex Number MSQ - Question 8



The correct answers are: an isosceles triangle, a right angled isosceles triangle

*Multiple options can be correct
Complex Number MSQ - Question 9

If z is a complex number satisfying  then z lies on :

Detailed Solution for Complex Number MSQ - Question 9


The correct answers are: y = x, y = - x

*Multiple options can be correct
Complex Number MSQ - Question 10

If  z1 = 5 + 12i and |z2| = 4 then :

Detailed Solution for Complex Number MSQ - Question 10

z1 5 + 12i,|z2| = 4



The correct answers are: maximum   maximum

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