Area & Perimeter - 2

There are 6×4=24 squares and each square has an area of = 1cm². So, the area of rectangle =6×4×1=24cm².

Area of square=side×side=10×10=100m².

Given figure is a rectangle. Also, given I = length = 8m Let b be the breadth of the rectangle. Perimeter of rectangle = 2(1 + b) = 28 ⇒   l + b = 28 / 2 ⇒   l + b = 14 ⇒ b = 14 ? 8 = 6m.

Perimeter = 2[3a + 2 + 2a - 1] = 2[5a + 1]

Base ofΔ = 12 cm Height ofΔ=2×12=24cm Area ofΔ=1/2×12×24=144sq.cm.

We are given the following in the question:

The breadth of a rectangle is increased by 2 units.

Let l be the original length and b be the original breadth.

New breadth = b + 2

The perimeter of rectangle =

The perimeter of new rectangle =

Hence, the perimeter of rectangle increases by 4 units. 

Volume occupied by one cube of 2 cm = 2*2*2=8cm³

Volume occupied by one cube of 6 cm = 6*6*6=216cm³

 No. of cubes of side 2 cm can be put in a cubical box of sides 6 cm = 216/8 = 27 cubes

side × side

Given each block is of 2m²,so there should be 12 blocks in a figure to get an area of 24m². In option (c), there are 2×6=12 blocks in figure.

No. of shaded boxes = 28, No. of unshaded boxes = 60 Area of 1 unshaded box =3m² So, area of unshaded region = 60×3=180m².