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What is the product obtained when a fraction is multiplied by its reciprocal?
The product of a fraction and its reciprocal is 1.
Reciprocals of 9 and 2 / 9 are 1 / 9 and 9 / 2 respectively.
Their sum =
Observe the number line given.
Q. Which fraction represented on the number line is in a wrong place?
1 / 8 < 1 / 4. So, it should lie between 0 and 1.
NO part os shaded hance correct answer will be 0/8=0
Hence, there are 28 tenths in
Convert all fractions to those with the same denominators and compare their numerators.
∴ The fraction greater than 7 / 8 is 11 / 12.
Observe the given equation.
Q. Identify the missing number in the box.
On cancelling the factors common to numerator and denominator on both the sides,
Hence the missing number is 5.
The sum of the numerator and the denominator of a fraction is 67. When 31 is added to the denominator, the fraction becomes 3 / 11. What was the original fraction?
Numerator + Denominator = 67
After adding 31 to the denominator, the numerator is 3 units and denominator is 11 units.
3 + 11 = 14 units = 67 + 31 = 98
∴ 1 unit = 98 ÷ 14 = 7
3 units = 3 × 7 = 21 and 11 units = 11 × 7 = 77
New fraction = 21 / 77
Hence, the original fraction
2 boys took a test. Pavan scored 4 / 5 of what Prateek had scored. If Pavan scored 76 marks, what was their total marks?
Score of Pavan = 76 = 4 / 5 of score of Prateek 4 / 5 → 76,
5 / 5 → 76 × 5 / 4
= 19 × 5 = 95
∴ Their total marks = 76 + 95 = 171.
Manish had Rs.45. He spent 3 / 5 of it on a birthday present. How much had he left?
Amount Manish had = Rs.45
Fraction of the amount spent = 35
∴ Amount left =
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