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UGEE SUPR Mock Test- 6 - JEE MCQ


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30 Questions MCQ Test UGEE Mock Test Series 2026 - UGEE SUPR Mock Test- 6

UGEE SUPR Mock Test- 6 for JEE 2025 is part of UGEE Mock Test Series 2026 preparation. The UGEE SUPR Mock Test- 6 questions and answers have been prepared according to the JEE exam syllabus.The UGEE SUPR Mock Test- 6 MCQs are made for JEE 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for UGEE SUPR Mock Test- 6 below.
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UGEE SUPR Mock Test- 6 - Question 1

If the vector equation of the line  is   then  p is equal to 

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 1

Given the line:

The parametric form is:

Convert to vector form:

Comparing with:

We get:
p = 1
So, the value of p is [1].

UGEE SUPR Mock Test- 6 - Question 2

The Solution of sin x =  is 

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 2

We have, sin x = 
Hence, sin x = sin 4π/3 , which gives
x = nπ + (-1)n 4π/3 , Where n ∈ Z

UGEE SUPR Mock Test- 6 - Question 3

The equation y2 + 3 = 2(2x+y) represents a parabola with the vertex at

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 3

The given equation can be rewritten as 
 which is a parabola
with its vertex  , axis along the line
y = 1, hence axis parallel tox-axis.
Its focus is 

UGEE SUPR Mock Test- 6 - Question 4

If siny = x sin(a + y), then dy/dx is equal to:

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 4

UGEE SUPR Mock Test- 6 - Question 5

∫ (27e9x + e12x)1/3 dx is equal to

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 5


UGEE SUPR Mock Test- 6 - Question 6

The area under the curve y = |cos x − sin x|, , and above the x-axis is:

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 6





UGEE SUPR Mock Test- 6 - Question 7

The conic represented by x = 2(cos t + sin t), y = 5(cos t − sin t) is

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 7

From given equation
x/2 = cos t + sin t  ....(i) 
y/5 = cos t - sin t   ....(ii)
Eliminating t from (i) and (ii), we have
 which is an ellipse.

UGEE SUPR Mock Test- 6 - Question 8

A Fischer projection of (2R, 3S)-2,3-butanediol is: -

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 8

Hint: Fischer projection is a two-dimension (2D) representation of a three-dimension (3D) organic molecule with the help of projection. These are mainly used in biochemistry and organic chemistry to represent monosaccharides.

Complete step by step solution:
Stereoisomers are the isomers having similar bonding patterns but differ in the arrangement of atoms or groups in three-dimensional space. There are two different stereoisomers for a molecule that has a centre of chirality in such cases it is expressed in terms of R and S configuration. For any pair of enantiomers with a chirality centre, one will have R configuration and the other will have the S configuration.
R stands for Rectus which is a Latin word with the meaning right, R is given to the isomer when the sequence is left to right.
S stands for Sinister another Latin word with left, S is given to the isomer if the sequence is right to left.
Also if the sequence follows the clockwise pattern it is known to be R configuration while for anticlockwise it follows S configuration. Priority sequence is decided by the sequence rules also called CIP rules.
In the case of 2,3-butanediol, the preference order according to CIP rules is:
OH>CH3>H
Now if we see the option B

seo images


In case of 2nd carbon priority of atoms is started from left to right so it follows R-configuration or on 3rd carbon priority of atoms is started from right to left so it follows S-configuration.

Thus, Fischer projection of (2R,3S)-2,3-butanediol is option (B).

Note: Chiral molecules are those molecules which are not superimposable on their mirror images. Chiral carbon is the carbon which is bonded to different atoms or groups also known by asymmetric carbon.

UGEE SUPR Mock Test- 6 - Question 9

Arrange the following particles in increasing order of values of e/m ratio: electron (e), proton (p), neutron (n) and α-particle (α) -

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 9

UGEE SUPR Mock Test- 6 - Question 10

For the reaction N2 + 3H2 → 2NH3 
if  mol L−1 s−1, then value of  would be

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 10



UGEE SUPR Mock Test- 6 - Question 11

Tautomerism is not exhibited by

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 11


UGEE SUPR Mock Test- 6 - Question 12

The electrode potentials for
Cu²⁺(aq) + e⁻ → Cu⁺(aq)
and Cu⁺(aq) + e⁻ → Cu(s)
are +0.15 V and +0.50 V, respectively.
The value of E°Cu²⁺/Cu will be:

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 12





UGEE SUPR Mock Test- 6 - Question 13

The wavelengths of two photons are 2000Å and 4000Å respectively. What is the ratio of their energies?

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 13

UGEE SUPR Mock Test- 6 - Question 14

Ethylene glycol, on oxidation with per-iodic acid, gives

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UGEE SUPR Mock Test- 6 - Question 15

What is X in the following change?

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 15

[Assuming esterification, as the reaction is unspecified]:
For a carboxylic acid converted to a methyl ester:

X is CH3 OH, H2 SO4

UGEE SUPR Mock Test- 6 - Question 16

In a closed insulated container, a liquid is stirred with a paddle to increase its temperature. In this process, which of the following is true?

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 16

As the system is closed and insulated, no heat enters or leaves the system, i.e. Q = 0;
∴ ΔE = Q + W = W.

UGEE SUPR Mock Test- 6 - Question 17

At low pressure, the van der Waals equation is reduced to

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 17

UGEE SUPR Mock Test- 6 - Question 18

A direct current of 2A and an alternating current having a maximum value of 2A flow through two identical resistances. The ratio of heat produced in the two resistances will be

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 18

Heat = I2 Rt.
DC: I = 2A, HDC = 4Rt.

UGEE SUPR Mock Test- 6 - Question 19

A hydrogen atom emits green light when it changes from n = 4 energy level to the n = 2 level. Which colour of light would the atom emit when it changes from n = 5 level to the n = 2 level?

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 19





Hence, f₂ > f₁. Among the options, only violet is one which has frequency more than green. Hence, answer is violet.

UGEE SUPR Mock Test- 6 - Question 20

A 20 cm long capillary tube is dipped in water. The water rises up to 8 cm. If the entire arrangement is put in a freely falling elevator the length of water column in the capillary tube will be ______ cm.

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 20

In a freely falling elevator, the effective gravity is zero. This scenario leads to some intriguing effects:

  • Effective Gravity: When in free fall, there is no gravitational pull acting on the objects inside the elevator.
  • Capillary Action: Without this gravitational influence, capillary action can occur more freely.
  • Water in the Tube: As a result, water can fill the entire length of the tube, reaching its full length of 20 cm.
UGEE SUPR Mock Test- 6 - Question 21

How many degree of freedom the gas molecules have if under STP the gas density ρ = 1.3 kg/m3 and the velocity of sound propagation in it is 330 m/sec?

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 21


γ = 1.4 for diatomic gas molecules, so the degree of freedom is 5.

UGEE SUPR Mock Test- 6 - Question 22

A thin sheet of glass (μ = 1.5) of thickness 6 microns introduced in the path of one of interfering beams in a double slit experiment shifts the central fringe to a position previously occupied by the fifth bright fringe. Then the wavelength of the light used is _____ Å

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 22




UGEE SUPR Mock Test- 6 - Question 23

A block of mass 10 kg is kept on a rough inclined plane as shown in the figure. A force of 3 N is applied on the block. The coefficient of static friction between the plane and the block is 0.6. What should be the minimum value of force P (in newton), such that the block does not move downward? (Take g = 10 m/s2)

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 23


UGEE SUPR Mock Test- 6 - Question 24

Two concentric coplanar circular loops made of wire, with resistance per unit length 10 Ω/m have diameters 0.2 m and 2 m. A time varying potential difference (4 + 2.5 t) volt is applied to the larger loop. Calculate the current (in A) in the smaller loop.

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 24

The resistance of the loops, 

and 

Flux in the smaller loop, φ = B2A1

The induced current, 
After substituting the value and simplifying we get
i = 1.25 A.

UGEE SUPR Mock Test- 6 - Question 25

Derivative of  with respect to sin-1(3x - 4x3) is

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 25


and v = sin-1(3 sin θ - 4 sin3 θ)

⇒ u = tan-1(tan θ) and v = sin-1(sin 3θ)
⇒ u = θ and v = 3θ
⇒ u = sin-1 x and v = 3 sin-1 x.
On differentiating both sides w.r.t. x, we get

UGEE SUPR Mock Test- 6 - Question 26

The differential equation of the family of circles touching Y-axis at the origin is

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 26

Let centre of circle on X-axis be (K, 0).
∴ the radius of circle will be K.

The equation of circle having centre (K, 0)
and radius K is
(x - K)2 + (y - 0)2 = K2
⇒ x2 + K2 - 2Kx + y2 = K2
⇒ x2 - 2Kx + y2 = 0 ... (i)

On differentiating both sides w.r.t. x, we get:

 ... (ii)

From equations (i) & (ii) we get:

UGEE SUPR Mock Test- 6 - Question 27


a11A21 + a12A22 + a13A23 is equal to
Note: axy represents element whereas Axy represents Cofactor matrix.

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 27


Since, the sum of the product of elements other than the corresponding cofactor is zero.
∴ a11A21 + a12A22 + a13A23 = 0

UGEE SUPR Mock Test- 6 - Question 28

The joint equation of lines passing through the origin and trisecting the first quadrant is:

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 28

  • The lines trisecting the first quadrant through the origin will have angles of 0°, 30°, 60°, and 90° with the x-axis.
  • The lines at 30° and 60° have slopes of tan(30°) = 1/√3 and tan(60°) = √3, respectively.
  • The joint equation of these lines, y = (1/√3)x and y = √3x, is obtained by multiplying the equations: (y - (1/√3)x)(y - √3x) = 0, which simplifies to x2 + √3xy - y2 = 0.
UGEE SUPR Mock Test- 6 - Question 29

If 2 tan-1(cos x) = tan-1(2 cosec x), then sin x + cos x is equal to:

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 29

UGEE SUPR Mock Test- 6 - Question 30

Direction cosines of the line , z = -1 are

Detailed Solution for UGEE SUPR Mock Test- 6 - Question 30

Equation of given line is 


So, DR of given line are 

∴ DC of given line are 

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