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RRB JE Electrical (CBT II) Mock Test- 2 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test RRB JE Mock Test Series Electrical Engineering 2025 - RRB JE Electrical (CBT II) Mock Test- 2

RRB JE Electrical (CBT II) Mock Test- 2 for Electrical Engineering (EE) 2024 is part of RRB JE Mock Test Series Electrical Engineering 2025 preparation. The RRB JE Electrical (CBT II) Mock Test- 2 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The RRB JE Electrical (CBT II) Mock Test- 2 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RRB JE Electrical (CBT II) Mock Test- 2 below.
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RRB JE Electrical (CBT II) Mock Test- 2 - Question 1

The process when the computer is switched on and the operating system gets loaded from hard disk to main memory is called ___________.

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 1

Booting is a startup sequence that starts the operating system of a computer when it is turned on. A boot sequence is the initial set of operations that the computer performs when it is switched on. Every computer has a boot sequence.

RRB JE Electrical (CBT II) Mock Test- 2 - Question 2

What is the capacitance of a capacitor which carries a charge of 0.5c at 10v.

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 2

The capacitance of a capacitor is Q/V, which implies 0.5/10 = 0.05c

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RRB JE Electrical (CBT II) Mock Test- 2 - Question 3

Which of the following statements is true with respect to ASCII?

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 3

A character encoding scheme is true with respect to ASCII. ASCII stands for American Standard Code for Information Interchange. Computers can only understand numbers, so an ASCII code is the numerical representation of a character such as 'a' or '@' or an action of some sort.

RRB JE Electrical (CBT II) Mock Test- 2 - Question 4

Which of the following is not a welding accessory-

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 4

Different welding accessories are-
1. Clamps & Jacks.
2. Earth Clamps & Cable.
3. Hazard Protection.
4. MIG Argon +5.
5. Plugs & Adaptors.
6. Welding Tables.
7. Hand screen.
8. Electrode holder
9. Gloves & Gauntlets.
10. Plugs / Sockets.

RRB JE Electrical (CBT II) Mock Test- 2 - Question 5
The load factor for domestic loads may be taken
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 5
RRB JE Electrical (CBT II) Mock Test- 2 - Question 6

A lamp of 100 W at 200 V is supplied current at 100 volts. It is equivalent to lamp of

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 6

Given that, Voltage (V1) = 200 V
Power (P1) = 100 W
We know that, P = V2/R
⇒ R = 2002/100 = 400Ω
Now it is connected to 100 V source.
P = 1002/100 = 25W

RRB JE Electrical (CBT II) Mock Test- 2 - Question 7

If the load current and flux of a DC motor are held constant, and voltage applied across its armature is increased by 10%, its speed will

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 7

We know that, in a dc motor


As voltage applied across its armature is increased by 10%, back emf also gets increased by 10%.
As flux is constant and speed is directly proportional to back emf, speed also gets increased by 10%.

RRB JE Electrical (CBT II) Mock Test- 2 - Question 8

Select the incorrect statement.

A single-phase induction motor

1. requires only 1 winding

2. can rotate in one direction only

3. is not self-starting
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 8

When single phase AC supply is given to stator winding, it produces alternating flux i.e. which alternates along one space axis only.

It is not synchronously revolving (or rotating) flux, thus it cannot produce any rotation. Hence single phase induction motor is not self-starting.

To overcome this problem and to make the motor self-starting, it is temporarily converted into two-phase motor during starting. For this purpose, the stator of a single phase motor is provided with extra winding known as starting winding in addition to the main winding. These two winding are placed across the single phase supply. It can rotate in both the directions.
RRB JE Electrical (CBT II) Mock Test- 2 - Question 9
The process of decomposing organic waste in the presence of air is termed as
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 9
Incineration is a waste treatment process that involves the combustion of organic substances contained in waste materials. Incineration and other high-temperature waste treatment systems are described as "thermal treatment". Incineration of waste materials converts the waste into ash, flue gas and heat means in the presence of air.
RRB JE Electrical (CBT II) Mock Test- 2 - Question 10
Which type of lamp holder from the following is fitted directly on the wooden board?
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 10

Batten Holder: This type of lamp holder is fitted directly on the wooden board, which itself is fixed on the wall. The lamp is then supported in the batten holder.

Pendant Holder: When the bulb is to be suspended from the ceiling rose, this type of holder has to be used for holding the lamp.

Angle Holder: Angle holders are used when the light of the lamp is needed at a certain angle. These are directly fixed to the walls.

Bracket Holders: These are used where direct light is needed in the room. These are also used on table lamps. Brackets used with such type of holders are made of brass material.

WaterTight Bracket Holder: These are provided with tubular glasses with watertight covers. These are mainly used for street lighting. They are also used for supporting bulbs outside the house premises.
RRB JE Electrical (CBT II) Mock Test- 2 - Question 11
Identify the incorrect statement/option: The psychological effect of noise pollution is
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 11

Noise pollution may cause or contribute to the following adverse effects:

  • anxiety, stress, nervousness, nausea, headache,
  • emotional instability,
  • argumentativeness,
  • increase in social conflicts
  • depression and fatigue
  • Insomnia as a result of lack of undisturbed and refreshing sleep
RRB JE Electrical (CBT II) Mock Test- 2 - Question 12
Which of the following is used to retrieve the information through URL (e.g. http://XYZ.com) on the world wide web?
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 12
  • A web browser is a software application for accessing information on the World Wide Web
  • URL is an acronym for Uniform Resource Locator, It is a reference to the resource on the internet
  • A client is a computer that connects to and uses the resources of a remote computer, or server
  • The server handles the request from the web browser and sends back a response to build a connection to provide web services
  • Cookies are messages that web servers pass to the web browser when user visit Internet sites
RRB JE Electrical (CBT II) Mock Test- 2 - Question 13
What is the formula of Ethanoic acid?
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 13
  • Acetic acid, commonly named ethanoic acid, is a colorless liquid organic compound with the chemical formula CH3COOH.
  • When undiluted, it is sometimes called glacial acetic acid.
RRB JE Electrical (CBT II) Mock Test- 2 - Question 14
Fly ash is the environmental pollutant generated by
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 14

Fly ash, also known as "pulverised fuel ash" is a coal combustion product composed of fine particles that are driven out of the boiler with the flue gases in thermal power plant.

RRB JE Electrical (CBT II) Mock Test- 2 - Question 15

A voltage waveform V(t) = 12t2 is applied across 1 H inductor for t ≥ 0, with initial current through it being zero. The current through inductor for t ≥ 0 will be-

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 15

Given that, V(t) = 12t2

We know that,

I = 12t2dt = 4t3

RRB JE Electrical (CBT II) Mock Test- 2 - Question 16

Given unit A/m defines which terms of magnetic circuit.

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 16

RRB JE Electrical (CBT II) Mock Test- 2 - Question 17

What are the two relative quantities to be plotted for external characteristics curve for DC shunt generator?

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 17

No load saturation characteristics:

Open circuit characteristic is also known as a magnetic characteristic or no-load saturation characteristic.

This characteristic shows the relation between generated emf at no load (E0) and the field current (If) at a given fixed speed.

Internal or Total Characteristic (E/Ia):

The on-load generated emf (Eg) and the armature current (Ia).

External Characteristic (V/IL):

An external characteristic curve shows the relation between the terminal voltage (V) and the load current (IL).

RRB JE Electrical (CBT II) Mock Test- 2 - Question 18
________ Brushes are used for higher values of current density.
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 18
  • Metal graphite brushes are used for higher values of current density.
  • Metal graphite brushes are generally made from natural graphite and fine metal powders
  • It is ideal for a variety of applications because of their low resistivity.
  • It is used on commutators of plating generators where low voltage and high brush current densities are encountered
RRB JE Electrical (CBT II) Mock Test- 2 - Question 19

The phase relationship between primary and secondary terminal voltage of a transformer is:

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 19

If we apply a voltage at the primary terminals of a transformer then for this, we can get a voltage at the secondary. But they have 180-degree phase difference.

RRB JE Electrical (CBT II) Mock Test- 2 - Question 20

Assertion (A): If the voltages across R, L and C elements connected in series in an ac circuit are 300 V, 100 V and 500 V respectively, the total voltage applied will be 500 V.

Reason (R): The applied voltage in LCR series circuit is equal to the maximum voltage existing across any of these elements.

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 20

In a series RLC circuit, the applied voltage is phasor sum of voltage existing across all these elements
let the total applied voltage is V and the voltage applied across R, L and C are VR, VL, and VC respectively.

Now, 
Given that, VR = 300 V, VL = 100 V, VC = 500 V


Hence, A is true, but R is false.

RRB JE Electrical (CBT II) Mock Test- 2 - Question 21
Two windings provided on the stator of 1-phase induction motor, one main winding and the other auxiliary winding are connected
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 21
Single phase induction motor is not a self-starting motor. By splitting the single phase to two phase 90° to each other rotating magnetic field is produced. This concept is used to start the motor known as split phase technique. The starting winding also called as auxiliary or temporary winding is connected in parallel to main winding through centrifugal switch in order to get isolated under running condition.
RRB JE Electrical (CBT II) Mock Test- 2 - Question 22
Which one of the following is NOT an active element?
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 22
An active element is the one which can act as a source of power. On this basis, the current source,​Voltage-dependent current source, and ​the Voltage source is the active element. Resistance, inductance, and capacitance do not have the power of their own.
RRB JE Electrical (CBT II) Mock Test- 2 - Question 23
A synchronous motor can operate at______.
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 23
The power factor of synchronous motor depends on excitation. If we change excitation it can be made to operate at lagging, leading and unity power factor. This can be explained through V curves as shown below.
RRB JE Electrical (CBT II) Mock Test- 2 - Question 24

In the circuit shown in figure, the voltmeter reading would be

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 24

The voltmeter is connected in parallel with an ammeter
The ideal resistance of ammeter is zero, Hence voltage drop across it (IR=0)
Thus voltmeter shows 0 reading

RRB JE Electrical (CBT II) Mock Test- 2 - Question 25
_________ is cause of failure to build up voltage.
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 25

Conditions to build up the voltage in shunt generator:

  • The shunt winding should have a residual magnetic field
  • The direction of the shunt winding and armature winding should be in such a way that flux generated by them should aid together
  • The shunt winding should have critical winding resistance

Voltage building in shunt generator:

When the armature is rotated, the residual flux in the field winding will induce a small voltage in the armature. The induced voltage in armature generates a flux and it will aid with field flux and the net flux will increase further. This process will be repeating until the actual terminal voltage is reached.

This process is restricted by the saturation of the iron core. Once the terminal voltage is reached then the winding will get saturated and hence there won't be any further increase in flux, also the voltage gets constant.
RRB JE Electrical (CBT II) Mock Test- 2 - Question 26

What is the power factor of the circuit when a current of 8 A flows in the ac circuit when 100 V dc is applied to it whereas it takes 125 V ac to produce the same current?

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 26

Power Factor is a ratio of the real power and apparent power flowing in the circuit.

Power factor = Realmpower/Apparent power = R/Z = V R/V
cosϕ = 100/125 = 0.8
Important:
Active power
(measured in Watt) is actual power or true power which does the useful work. (so, most of the equipment’s which consume electricity or electric power are rated in terms of Watt or HP)
Reactive power (measured in Volt-Ampere- Reactive) is imaginary power which is required for the processes like energy conversion & energy storage. (so, the equipment’s which generate only reactive power are rated in terms of VAr. e.g. capacitor banks for pf correction)
Apparent power (measured in terms of Volt-Ampere) is total power. And is combination of active and reactive powers

RRB JE Electrical (CBT II) Mock Test- 2 - Question 27
Which country has unveiled its first underwater military museum off the coast of Aqaba?
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 27
  • Jordan has unveiled its first underwater military museum off the coast of Aqaba.
  • The vehicles, including tanks, troop carriers and a helicopter, imitating a battle formation, have been stationed at a coral reef in the Red Sea.
  • Aqaba is the lone port city of Jordan and is a popular destination for divers.
RRB JE Electrical (CBT II) Mock Test- 2 - Question 28

A battery had a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 Ω the power dissipated by the bulb is:

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 28

Given:
Open circuit voltage = VOC = 24 V, Short circuit current = ISC = 30 A
We know that
Resistance = VOC/ISC = 30/24 = 1.2 Ω

Current I = V/R = 24/3.2 = 7.5 A
The power dissipated by the bulb is = I2 x R = 7.52 X 2 = 112.5 W 

RRB JE Electrical (CBT II) Mock Test- 2 - Question 29
A 240 V, dc shunt motor draws 15 A while supplying the rated load at a speed of 100 rad/s. The armature resistance is 0.5 W and the field winding resistance is 80 W. The net voltage across the armature resistance at the time of plugging will be
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 29

Given Vt = 240 V, Line current (I) = 15 A, Armature resistance (Ra) = 0.5 Ω, Shunt resistance (Rsh) = 80 Ω

Shunt current = Ish = 240/100 = 2.4 A

Armature current = I = 15 - 2.4 = 12.6 A

Back emf = Eb = Vt - IaRa = 240 - 12.6 × 0.5 = 233.7 V

Vplugging = Vt + Eb = 240 + 233.7 = 473.7 V
RRB JE Electrical (CBT II) Mock Test- 2 - Question 30
A man is standing on a boat in still water. If he walks towards the shore, the boat will
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 2 - Question 30
A man is standing on a boat in still water. If he walks towards the shore, the boat will move away from the shore. This is according to Newton’s third law of motion - to every action there is equal and opposite reaction.
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