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RRB JE Electrical (CBT II) Mock Test- 7 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test RRB JE Mock Test Series Electrical Engineering 2026 - RRB JE Electrical (CBT II) Mock Test- 7

RRB JE Electrical (CBT II) Mock Test- 7 for Electrical Engineering (EE) 2026 is part of RRB JE Mock Test Series Electrical Engineering 2026 preparation. The RRB JE Electrical (CBT II) Mock Test- 7 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The RRB JE Electrical (CBT II) Mock Test- 7 MCQs are made for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RRB JE Electrical (CBT II) Mock Test- 7 below.
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RRB JE Electrical (CBT II) Mock Test- 7 - Question 1

How does energy travel from the sun to the earth?

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 1

Radiation is the transfer of heat energy through space by electromagnetic radiation.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 2

What is the desired value of earthing resistance for large power stations?

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 2

- Maximum allowable Earth resistance for

Major power station = 0.5 Ohm, is the accepted norm.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 3

The voltage induced in an inductor is written as-

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 3

The instantaneous voltage across the inductor is expressed as the product of inductance and a rate of change of current through it as it doesn't allow any certain change of current through it.
V= L × (di/dt)

RRB JE Electrical (CBT II) Mock Test- 7 - Question 4

VIRUS stands for __________.

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 4

VIRUS stands for 'Vital Information Resource Under Seige'. It is a segment of self-replicating code planted illegally in a computer program, often to damage or shut down a system or network.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 5

Ferrite cores are used in high frequency transformer because it has:

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 5

Ferrite core is a type of magnetic core made of ferrite on which the windings of electric transformers and other wound components such as inductors are formed.

It is used for its properties of high magnetic permeability coupled with low electrical conductivity (high resistance)

It helps in preventing eddy currents

RRB JE Electrical (CBT II) Mock Test- 7 - Question 6

The curie temperature of iron is___________.

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 6

The μr value of a ferromagnetic material depends upon temperature, μr  decreases with increase in temperature and at critical temperature ‘curie temperature’ the ferromagnetic material becomes paramagnetic. The curie temperature of iron is 770 degree Celsius.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 7
Which of the following statements is true?
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 7
The TCP/IP model, which is realistically the Internet Model, came into existence about 10 years before the OSI model. The four-layer Internet model defines the Internet protocol suite, better known as the TCP/IP suite.
RRB JE Electrical (CBT II) Mock Test- 7 - Question 8
The distribution transformer is generally connected in__________.
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 8
Distribution transformers are connected in delta-star. This arrangement requires 3 conductors in the high voltage side and 4 in the low voltage side, as well as it provides the star point conductor as a neutral point. This can serve single phase as well as three phase loads.
RRB JE Electrical (CBT II) Mock Test- 7 - Question 9
The shape of Indifference curve indicates ________.
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 9
An indifference curve is a graph showing combination of two goods that give the consumer equal satisfaction and utility. Each point on an indifference curve indicates that a consumer is indifferent between the two and all points give him the same utility.
RRB JE Electrical (CBT II) Mock Test- 7 - Question 10

Three equal resistors are connected in series, across a source of emf, dissipate 10 W of power. What would be the power dissipated when they are connected in parallel across the same source.

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 10

Let the resistance of each resistor = R Ω
If three equal resistors are connected in series (R1) = 3R
Power dissipated in this case (P1) = 10 W
If three equal resistors are connected in parallel (R2) = R/3
Power dissipated in this case = P2
We know that, P = V2/R
For the same voltage, power is inversely proportional to resistance.
From the first case to the second case, the resistance decreases by 9 times. Hence the power will increase by 9 times.
Power in the second case (P2) = 90 W

RRB JE Electrical (CBT II) Mock Test- 7 - Question 11
Least suitable transducer for static pressure measurement is-
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 11

A pressure transducer is used to convert a certain value of pressure into its corresponding mechanical or electrical output.

The transducers used for static pressure measurement are

Semi-conductor strain gauge
Variable capacitor for transducer
Piezoelectric transducer
Metal wire strain gauge is least suitable for static pressure measurement.
RRB JE Electrical (CBT II) Mock Test- 7 - Question 12

The source of a magnetic field is

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 12

According to Faraday's law, the current flowing through a coil produces the magnetic field. Hence the source of a magnetic field is the current loop.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 13

In balancing the following chemical reaction, what is the value of “b”?

aH2S+bO2→cH2O+dSO2

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 13

Hydrogen and Sulphur are already balanced

Start with the balancing of oxygen

Oxygen on RHS = 3

Oxygen on LHS = 2

H2S+3/2O2→H2O+SO2

To get an integer number of moles, multiply the equation by 2

2H2S+3O2→2H2O+2SO2

RRB JE Electrical (CBT II) Mock Test- 7 - Question 14

Find the work done (in J) when a charge of 10 C moves across a potential difference of 2 V.

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 14

The potential difference is defined as work done per unit charge.

This implied that, V = W/q

Where V is Potential Difference; W is Work Done; q is charge

Or, W= V× q

= 2×10

= 20 Joules.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 15

The motor used in ceiling fan is ________

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 15

RRB JE Electrical (CBT II) Mock Test- 7 - Question 16
The resistance of a wire is 2 Ω. If the diameter of the wire is reduced to half, keeping the same length, the resistance will be
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 16

1) Resistance is proportional to length: When wire length becomes half, the resistance becomes half

2) Resistance is inversely proportional to the cross-sectional area: Diameter, becomes half, area reduces by the square of diameter i.e. 1/4 times; Therefore, resistance becomes 4 times more

Keeping points 1 and 2 together, the resistance becomes 4 times.
RRB JE Electrical (CBT II) Mock Test- 7 - Question 17

Which of the following rays was used by Rutherford in his experiment ?

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 17

Rutherford designed an experiment in which fast-moving alpha (α)-particles were made to fall on a thin gold foil.

He selected a gold foil because he wanted as thin a layer as possible. This gold foil was about 1000 atoms thick.
α-particles are doubly-charged helium ions. Since they have a mass of 4µ, the fast-moving α-particles have a considerable amount of energy.

Rutherford’s prediction

Rutherford’s Observation

Observations and Conclusions:
Observation 1 :

Most alpha particles passed through the gold foil undeflected.
Conclusion 1:
Atom consists of mostly empty space
Observation 2.
Some alpha particles bounced off from the nucleus, while others were deflected through large and small angles
Conclusion 2 :
Atom consists of a dense center, called nucleus
Observation 3:
No alpha particle was sucked into the nucleus
Conclusion 3:
Using the fact that Alpha particles carry a positive charge, and like charges repel, while unlike charges attract he concluded atom consists of a positively charge nucleus

RRB JE Electrical (CBT II) Mock Test- 7 - Question 18

When a current of 2 amperes is passed in the primary of a transformer, the magnetic flux through one turn of the secondary is 8 × 10-5 weber. The number of turns in the secondary is 25. The mutual inductance of coils is:

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 18

Current (I) = 2 A
Flux (ϕ) = 8 × 10-5 weber
Number of turns (N) = 25
Mutual inductance = NØ/I = 25 x 8 x 10 -5/2 = 1 mH

RRB JE Electrical (CBT II) Mock Test- 7 - Question 19

If we arrange different gases in decreasing order of their percentage available in atmosphere. Which one of the option is correct?

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 19

The atmosphere is a thin layer of gases which stays above the earth due to the force of gravitation. Its air is colourless, odourless and tasteless.
Nitrogen and oxygen are two major gases of the atmosphere. Carbon dioxide (CO2), Helium, Ozone, Argon and hydrogen are found in lesser quantities. Apart from these gases, tiny dust particles are also present in the air.
The atmospheric composition of gases are as follow

RRB JE Electrical (CBT II) Mock Test- 7 - Question 20
The fuse blows off by
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 20

A fuse is an electrical safety device that operates to provide over current protection of an electrical circuit. Its essential component is a metal wire or strip that melts when too much current flows through it, thereby interrupting the current.

The fuse wire should have low melting point so that it can get melt when current more than rated flows in the circuit
RRB JE Electrical (CBT II) Mock Test- 7 - Question 21
Which of the following is the optically readable media?
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 21
Using optically readable medium, data is recorded by making marks in a pattern that can be read back with the help of light
CD-ROM and DVD are optically readable media
Floppy disk is a type of disk storage composed of a disk of thin and flexible magnetic storage medium
A hard disk is an electromechanical data storage device that uses magnetic storage to store and retrieve digital information
Magnetic tape is a medium for magnetic recording, made of a thin, long, narrow strip of plastic film which has a magnetic coating
RRB JE Electrical (CBT II) Mock Test- 7 - Question 22

What is the SI unit for magnetic reluctance?

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 22

Magnetic Units:

RRB JE Electrical (CBT II) Mock Test- 7 - Question 23

The duration of second generation computers is generally accepted

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 23

RRB JE Electrical (CBT II) Mock Test- 7 - Question 24
Suitable value of flux density for design of 250 kV transformer is
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 24

The values of maximum flux density for different transformers are as follows:

For hot rolled silicon steel:

Distribution transformer – 1.1 to 1.35 T
Power transformer – 1.25 to 1.45 T

For CRGO core:

Up to 132 kV – 1.55 T
For 275 kV – 1.6 T
For 400 kV and generation transformer – 1.7 to 1.75 T
RRB JE Electrical (CBT II) Mock Test- 7 - Question 25
What happens when silver chloride is put under sunlight?
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 25

Concept:

Decomposition Reaction:

A single reactant breaks down to give simpler products. This type of reaction is called as decomposition reaction

Application:

When silver chloride is exposed to sunlight, white silver chloride turns grey in sunlight.

This is due to the decomposition of silver chloride into silver and chlorine by light

Underlying Reaction:

2AgCl(s) Sunlight → 2Ag(s) + Cl2(g)
RRB JE Electrical (CBT II) Mock Test- 7 - Question 26

A shunt resistor is connected across the contacts of a circuit breaker in order to:

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 26

Resistance switching:

It is a method adopted for dampening the over-voltage transients due to current chopping.
In this method, a shunt resistance is connected across the contacts of the circuit breaker.
It reduces the rate of rising of re-striking voltage and the peak value of re-striking voltage.
It helps to reduce the voltage transient surge during current chopping and capacitive current breaking.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 27

Approximate quantity of CO2 in the atmosphere in PPM (parts per million) is:

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 27

Approximate quantities of different gases in the atmosphere in PPM are given below.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 28

What will be the coefficient of self-induction (in H) of the coil, if the current changes from +4 A to -4 A in 0.10 seconds and the induced EMF is 16 V?

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 28

Given that, emf (V) = 16 V
di/dt = 4-(-4)/0.1 = 80
We know that, V L
⇒ L = 16/80 = 0.2 H

RRB JE Electrical (CBT II) Mock Test- 7 - Question 29
Five limb core construction is preferred over three limb construction because in this type of construction:
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 29
Five limb core construction is preferred over three limb construction because in this type of construction magnetic reluctance of the three phase can be balanced.
5 limbed transformer core offers low impedance to the flow of unbalanced load between the line and neutral.
This is because the flux finds its path from 4th and 5th limb. So, tertiary winding will not be needed in a star connected transformer operating in an unbalanced load.
RRB JE Electrical (CBT II) Mock Test- 7 - Question 30
In refrigerators the commonly used motors are
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 30

Capacitor start induction motors are used in refrigerators. The other applications of capacitor start induction motor are:

These motors are used for the loads of higher inertia where frequent starting is required
Used in pumps and compressors
Used in the refrigerator and air conditioner compressors
They are also used for conveyors and machine tools
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