Percentage - MCQ 1 - Mechanical Engineering MCQ

Assume Total no of students = 100
60% of the students are boys. so Boys=60,Girls=40
No. of girls who scored more than 40 marks = 80% of girls = 80% of 40 = 32.
No. of students who scored more than 40 marks = 60% of Total Students = 60
Therefore No. of boys who scored more than 40 marks = 60-32=28
No. of boys who scored less= Total boys – Boys(scored more) = 60-28=32
Fraction=(scored less)/Total boys = 32/60 =8/15

Let total number of voters= x
People who voted for the winner are = 0.47x
People who voted for the loser are = 0.47x-308
People who cast blanks are = 60
and people who did not vote are = 0.1x
solve the following equation
0.47x + 0.47x - 308 + 60 + 0.1x = x =>  x = 6200

Assume Deepak’s salary =10000
original hike(50%) amount = 5000 ; Revised salary =15000
Wrongly typed(80%) hike amount = 8000
Diff = 3000; For three months = 9000
Fourth Month Salary = 15000-9000=6000
15000*x/100 = 6000 => x=40%

Let the price of two articles are 3X and 4X.
After increment the ratio will be:
110% of 3x/(4X+4) = 3/4
x=10
Thus the CP of second article = 4X = 4*10 = Rs. 40.

Consider Total no of students = 100
Ratio is 3:2 i.e Boys=60 and Girls=40
20% of boys who get scholarship = 60*20/100=12%
25% of girls who get scholarship = 40*25/100 =10%
Therefore % of students who do not get scholarship =100-(12+10) = 78%

Total amount = x
Savings(%)
[100 – (23 + 33 + 19 + 16 )]% = 9 %
9% of x = 504
=> x = 504 * 100/9 = 5600
Amount spend on food and insurance policy together = 56% of 5600 = Rs.3136

Assume Total amount = Rs.100
Auto fare= 15% of Total amount i.e Rs.15
Now the amount is Rs.85
Price of 70 oranges = Rs.85
Price of 35 oranges = (85/70)*35 = Rs. 42.50
Remaining amount to buy apples is =Rs. 42.50
Price of 40 apples = Rs.85
Price of X apples = Rs.42.50
X=(85/42.5)*40 = 20 Apples

4,50,000*(80/100)*(90/100)= 324000 450000 – 324000 = Rs.1,26,000

Assume – Arun’s motorcycle uses 1L per day and therefore tank’s Capacity = 10L.
25% increased per day= 1+(25/100) = 5/4 ie. 1.25L per day
Days = 10/1.25 = 8

Total students=60
Failed in both=5% of 60=3
Passed in both=20% of 60=12
Passed in reasoning=40% of 60=24
Those passed only in reasoning =24-12=12 students.
Passed only in Quants=60-(12+12+3)=33

40*1/100  : 60*2/100 : 35*3/100 = 0.4:1.2:1.05
Overall % =100* [0.4+1.2+1.05]/1+2+3 = 265/6 = 44.16 = 44%

passed in science = 50%
passed in social = 75%
20% students failed in both the subjects and 80% passed in at least one subject
No of students passed in both subjects = 50+75−x=80  x=45% 45% of x = 270  x = 270*100/45 = 600
Total number of students =600

Quantity of water in 300 kg dry fruits, = (20 /100) *300 = 60 kg
Quantity of fruit alone= 300-60 =240 kg
25 kg fruit piece in 100 kg fresh fruits
For 240 = (100 *240)/25 = 960 kg.

Let the number of individuals involved in election be x.
Percentage of those who were not vote = 100-(35+42) = 23%
The difference between those who voted
42% of x – 23% of x = 570
19% of x = 570
x=570*100/19 = 3000

(20*0.97)+(15*0.93)+(32*0.98) = 19.4+13.95+31.36
= 64.71

Total students are 100% = 500
Boys = 65% of 500 = 325,
Girls = 35% =35*500/100 =175
Girls failed in the exam= 175*80/100 = 140
Boys failed in the exam =40/100x 325 = 195
Total = 140+195 = 335

Total increase = 6+2 = 8%
% increase = 8+8+(8*8/100)  = 16+0.64 = 16.64%

7% increases 30000 = Rs 2100 =30000+2100 = Rs 32,100
But the actual increase in salary = 31800
Difference =32100 – 31800 = 300
2% = 300
Gugan’s salary =300/2 x 100 = 15000
Harish’s salary =30000 – 15000 = Rs 15000

Students passed in Prelims = 70%
Students passed in Mains = 55%
Students passed in both  = 62%
No of students passed in at least one subject = (70+55)-62 = 63%.
students failed in both subjects = 100-63 = 37%.