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[Dividing and multiplying by (4−3√3) ]
Hence, the correct option is (B).
In △ABC,O is the incentre and ∠BOC= 135^{°}. The measure of ∠BAC is:
In △ABC,O is the incentre and ∠BOC= 135^{°}.
Incentre of a triangle: The point of intersection of all three angle bisectors of a triangle is called its in  centre.
The distance between In  centre and its all three sides is always equal and its called inradius.
∠BOC is the incentre of △ABC.
Hence, the correct option is (C).
A man sells an article on Rs. 280 and gets 40% profit. Then find the cost price of the article.
Given:
The selling price of the article = Rs. 280
The profit obtained = 40%
Selling price = cost price ×(100+ profit) %
Let the cost price be CP.
∴ The cost price of the article is Rs. 200.
Hence, the correct option is (B).
The product of two numbers is x/y If one of the numbers is x/y^{2} then the other number is:
Given:
The product of two numbers is y/x.
One of the number is x/y^{2}
Let the other number be M.
Then,
Therefore, the other number is y^{3}/x^{2}.
Hence, the correct option is (A).
A car travels a certain distance at 70 km/h and comes back at 30 km/h. Find the average speed for total journey.
Given:
The Car goes with the speed (S_{1}) = 70 km/hr
The car comes back with the speed (S_{2}) = 30 km/hr
We know that, Average speed
Hence, the correct option is (A).
At what rate of interest will a sum of Rs. 4,500 amount to Rs. 6,525 at simple interest for 5 years?
Given
Principal = Rs. 4500
Amount = Rs. 6525
We know that, Interest =Amount  Principal
⇒ Interest =6525−4500
=2025
According to Condition,
∴ The rate of interest is 9%.
Hence, the correct option is (B).
Choose the odd numerical pair/group in the following options.
All except 55  62 have difference of nine between them.
(A) 55 – 62 = difference is 7
(B) 34 – 43 = difference is 9
(C) 62 –71 = difference is 9
(C) 83 – 92 = difference is 9
Hence, the correct option is (A).
In the given matrix which option will replace the question mark.
The logic follows here is :
From the first row :
From second row :
From Third row :
So, that Third column third row is "289".
Hence, the correct option is (C).
Four letter clusters have been given, out of which three are alike in some manner, while one is different. Select the odd letter cluster.
The pattern followed here is:
All follow the same pattern except “GIMT”.
Hence, the correct option is (C).
Given
[∵ sin (90^{0}  ?) = cos ? and cos (90^{0}  ?) = sin ? ]
= 1/1 = 1 [∵ sin^{2}? + cos^{2}? = 1]
Two numbers are respectively 20% and 50% of a third number. What percent is the first number of the second?
Given:
Two numbers are respectively 20% and 50% of a third number.
Let the third number be x.
According to the question; First number
∴ The correct answer is 40%.
Hence, the correct option is (D).
11 $ 11 = 99, 45 $ 15 = 615, 44 $ 12 = 472, then find the value of 32 $ 11 = ?
The pattern/logic followed here is:
11 $ 11 = 99 → (11 × 11)  (11 + 11) = 121  22 = 99;
45 $ 15 = 615 → (45 × 15)  (45 + 15) = 675  60 = 615;
44 $ 12 = 472 → (44 × 12)  (44 + 12) = 528  56 = 472;
Similarly,
32 $ 11 = ? → (32 × 11)  (32 + 11) = 352  43 = 309
Hence, the correct option is (D).
In triangle ABC, rightangled at B, if tan A = 1/√3, find the value of:
SinA cos C + cos A sin C
Let us draw a triangle ABC,
tan A = 1/√3
Where, BC=1 and AB = √3
In △ABC,
Hence, the correct option is (A).
The LCM of two numbers is 90 times their HCF. The sum of LCM and HCF is 1456 . If one of the number is 160 , then what is the other number?
Let the HCF of two numbers be x.
∴ LCM of two numbers be 90x.
According to the question,
∴ HCF of two numbers =16
and LCM of two numbers =90×16
= 1440
We know that, LCM ×HCF= Product of two numbers
⇒ 1440 x 16 = 160 x second number
Hence, the correct option is (C).
In the following question, select the related letters from the given alternatives.
OPEN : PRHR : : CLOSE : ?
The pattern followed here is:
So,
Hence, the correct option is (A).
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