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Test: Construction of Similar Figures


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15 Questions MCQ Test NCERT Mathematics for CAT Preparation | Test: Construction of Similar Figures

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Test: Construction of Similar Figures - Question 1

In the figure, DE is parallel to BC such that AE = one fourth of AC. If AB = 6cm, then AD is

Detailed Solution for Test: Construction of Similar Figures - Question 1 Let AC be x. then *(1÷4) + (3÷4)=x AC =1Now In ∆ABC . (by BPL)AD/AB = AE/ACAD=1/4×6AD=1.5 cm
Test: Construction of Similar Figures - Question 2

Which of the following relation would hold true for the sides of the similar triangles in the given diagram?

Test: Construction of Similar Figures - Question 3

The perimeters of two similar triangles are 25 cm and 15 cm respectively. If one side of first triangle is 9 cm, the corresponding side of the other triangle is

Detailed Solution for Test: Construction of Similar Figures - Question 3

In similar triangles, the perimeter of the triangles will be in the ratio of their corresponding sides.

Test: Construction of Similar Figures - Question 4

In the given figure, AC: CB is

Test: Construction of Similar Figures - Question 5

In the figure QA and PB are perpendiculars on AB. If AO = 10 cm, BO = 6 cm and PB = 9cm, then AQ is

Test: Construction of Similar Figures - Question 6

From the given figure, find out what is AC : AB.​

Test: Construction of Similar Figures - Question 7

Sides of two similar triangles are in the ratio 3:8. Areas of these triangles are in the ratio

Test: Construction of Similar Figures - Question 8

In the given figure, triangles ABC and DEF are similar. The area of triangle ABC is 9 sq. cm and the area of triangle DEF is 16 sq. cm. If BC = 2.1 cm find the length of EF.

Test: Construction of Similar Figures - Question 9

In the given figure, triangle ABC has been constructed similar to triangle A’BC’. What is the scale factor?

Test: Construction of Similar Figures - Question 10

In the figure, DE is parallel to BC such that AE = one fourth of AC. If AB = 6cm, then AD is

Test: Construction of Similar Figures - Question 11

In drawing triangle ABC, it is given that AB = 3 cm, BC = 2 cm and AC = 6 cm. It is not possible to draw the triangle as:​

Test: Construction of Similar Figures - Question 12

Identify the incorrect statement.​

Test: Construction of Similar Figures - Question 13

ABCD is a quadrilateral with BC = 8 cm. Quadrilateral AB’C’D’ is constructed with a scale factor 3/4. What will be the length of B’C’?​

Detailed Solution for Test: Construction of Similar Figures - Question 13

The quadrilateral is dilated by a scale factor of 3/4.The shape of image will be same as pre image but size will vary means it will be smaller .If Dilation factor is , means 0< Dilation factor<1, the image is be smaller than preimage.
So new length =k*original size=¾*8 = 6cm
So B’C’ = 6cm

Test: Construction of Similar Figures - Question 14

In the given figure, AB and DE are perpendiculars to BC. If AB = 9cm, DE = 3cm and AC = 24cm then AD is equal to

Detailed Solution for Test: Construction of Similar Figures - Question 14

Since AB||DE so Angle A= Angle D,Angle C is common
So by AA criterion, ΔABC - ΔDEC
So,the corresponding sides are in proportion

DC=8
AD=24-8=16cm

Test: Construction of Similar Figures - Question 15

If triangles PQR and DEF are similar, then which of the similarity criterion is true

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