1 Crore+ students have signed up on EduRev. Have you? 
x = 2, y = – 1 is a solution of the line equal to :
The straight line passing through the points (0, 0), (–1, 1) and (1, – 1) has the equation :
The graph of the equation 2x – 3 = 3x – 5 is parallel to :
The straight line 2x – 5y = 0 passes through the point :
The graph of the lines x + y = 7 and x – y = 3 meet at the point :
The graph of the equation y = x^{2} is :
In the graph of y = x^{2}, the point (0, 0) is called the vertex. The vertex is the minimum point in a parabola that opens upward. In a parabola that opens downward, the vertex is the maximum point. We can graph a parabola with a different vertex.
Which of the following equations is not linear equation :
If x = 1,y = 1 is a solution of equation 9ax + 12ay = 63 then, the value of a is :
The graph of the line 5x + 3y = 4 cuts yaxis at the point :
A linear equation in two variables has maximum :
If x = a, y = b is the solution of the pair of equation xy = 2 and x+y = 4 then what will be value of a and b
The solution of the equation x + y = 3, 3x – 2y = 4 is :
The value of x satisfying the equation x^{2} + p^{2} = (q – x)^{2} is :
Solution :
The correct option is Option B.
n² + p² = (q + n)²
n² + p² = q²  2qn + n²
Eliminating n² from both sides,
p² = q²  2qn
n = q²  p² / 2q
The sum of two digits and the number formed by interchanging its digit is 110. If ten is subtracted from the first number, the new number is 4 more than 5 times of the sum of the digits in the first number. Find the first number.
let the unit place digit be x and tens place digit be y
then the twodigit number will be 10y + x
and the number formed by interchanging the unit place and tens place digits will be 10x + y
according to the first condition given in the qs i.e, the sum of two numbers is 110 that is
10y + x + 10x + y = 110
=> 11x + 11y = 110
divide the above equation by 11 we get
x + y = 10
x = 10  y ....(i)
now according to the second equation,
if 10 is subtracted from the first number i.e, the new number is 10y + x  10
given that the new number is 4 more than 5 time the sum of its digits in the first number i.e
the sum of its digits in the first number is x + y, now 5 times of its, 5(x + y), and now 4 more that is, 4 + 5(x + y)
therefore new number = 4 + 5(x + y)
10y + x  10 = 4 +5(x + y)
10y  5y + x = 4 +10 +5x
5y = 14 + 4x.....(ii)
substitute the value of x from eq(i) to eq (ii)
we get , 5y = 14 + 4(10  y)
5y = 14 + 40  4y
y = 6
and from eq(i)
x = 4
then the first number 10y + x = 10x6 + 4 = 64
first number is 64.
The point of the form (a, a), where a ≠ 0, lies on
The point of the form (a, a), where a , 0 lies on
The point of the form (a, a), where a , 0 lies on
The graph of the linear equation 2x – 3y = 6, cuts the yaxis at the point
The graph of the linear equation 3x – 2y = 6, cuts the xaxis at the point
276 docs149 tests

Use Code STAYHOME200 and get INR 200 additional OFF

Use Coupon Code 
276 docs149 tests








