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NCERT Based Test: Ampere's Circuital Law - NEET MCQ


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5 Questions MCQ Test Physics Class 12 - NCERT Based Test: Ampere's Circuital Law

NCERT Based Test: Ampere's Circuital Law for NEET 2024 is part of Physics Class 12 preparation. The NCERT Based Test: Ampere's Circuital Law questions and answers have been prepared according to the NEET exam syllabus.The NCERT Based Test: Ampere's Circuital Law MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NCERT Based Test: Ampere's Circuital Law below.
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NCERT Based Test: Ampere's Circuital Law - Question 1

Ampere's circuital law is given by

Detailed Solution for NCERT Based Test: Ampere's Circuital Law - Question 1

The line integral of the magnetic field of induction  around any closed path in free space is equal to absolute permeability of free space μ0 times the total current flowing through area bounded by the path.
Ampere's circuital law is given by: 

NCERT Based Test: Ampere's Circuital Law - Question 2

Two identical current carrying coaxial loops, carry current I in opposite sense. A simple amperian loop passes through both of them once. Calling the loop as C, then which statement is correct?

NCERT Based Test: Ampere's Circuital Law - Question 3

A long straight wire in the horizontal plane carries a current of 75 A in north to south direction, magnitude and direction of field B at a point 3 m east of the wire is

Detailed Solution for NCERT Based Test: Ampere's Circuital Law - Question 3

From Ampere circuital law

The direction of field at the given point will be vertical up determined by the screw rule or right hand rule.

NCERT Based Test: Ampere's Circuital Law - Question 4

If a long straight wire carries a current of 40 A, then the magnitude ol the field B at a point 15 cm away from the wire is 

Detailed Solution for NCERT Based Test: Ampere's Circuital Law - Question 4

I = 40A
r = 15 cm = 15 x 10-2 m
∴  = 5.34 x 10-5 T

NCERT Based Test: Ampere's Circuital Law - Question 5

The correct plot of the magnitude of magnetic field   vs distance r from centre of the wire is, if the radius of wire is R

Detailed Solution for NCERT Based Test: Ampere's Circuital Law - Question 5

The magnetic field from the centre of wire of radius R is given by
B = ((μ0I)/(2R2))r (r < R) ⇒ B ∝ r
and B = μ0I/2πr (r > R) ⇒ B ∝ 1/r
From this descriptions, we can say that the graph (b) is a correct representation.

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