NCERT Based Test: Motion in a Magnetic Field - NEET MCQ

# NCERT Based Test: Motion in a Magnetic Field - NEET MCQ

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## 5 Questions MCQ Test Physics Class 12 - NCERT Based Test: Motion in a Magnetic Field

NCERT Based Test: Motion in a Magnetic Field for NEET 2024 is part of Physics Class 12 preparation. The NCERT Based Test: Motion in a Magnetic Field questions and answers have been prepared according to the NEET exam syllabus.The NCERT Based Test: Motion in a Magnetic Field MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NCERT Based Test: Motion in a Magnetic Field below.
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NCERT Based Test: Motion in a Magnetic Field - Question 1

### A charged particle is moving on circular path with velocity v in a uniform magnetic field B, if the velocity of the charged particle is doubled and strength of Magnetic field is halved, then radius becomes

Detailed Solution for NCERT Based Test: Motion in a Magnetic Field - Question 1

As
According to the question, v‘ = 2v and B' = B/2
∴

NCERT Based Test: Motion in a Magnetic Field - Question 2

### An electron of energy 1800 eV describes a circular path in magnetic field of flux density 0.4 T. The radius of path is (q = 1.6 x 10-19 C, me = 9.1 x 10-31 kg)

Detailed Solution for NCERT Based Test: Motion in a Magnetic Field - Question 2

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NCERT Based Test: Motion in a Magnetic Field - Question 3

### Two α-partides have the ratio of their velocities as 3 : 2 on entering the field. If they move in different circular paths, then the ratio of the radii of their paths is

Detailed Solution for NCERT Based Test: Motion in a Magnetic Field - Question 3

As qvB = mv2/r

NCERT Based Test: Motion in a Magnetic Field - Question 4

When a positively charged particle enters a uniform magnetic field with uniform velocity, its trajectory can be (i) a straight line (ii) a circle (iii) a helix.

NCERT Based Test: Motion in a Magnetic Field - Question 5

Two particles of equal charges after being accelerated through the same potential difference enter in a uniform transverse magnetic field and describe circular paths of radii Rand R2. Then the ratio of their respective masses (M1/M2) is

Detailed Solution for NCERT Based Test: Motion in a Magnetic Field - Question 5

And Bqv = Mv2/R Or  Using (i)
or
∴ M ∝ R2 (∵ B, q  and V are same for the given two particles)
Hence (M1/M2) = (R1/R2)2

## Physics Class 12

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## Physics Class 12

105 videos|425 docs|114 tests