NCERT Based Test: The Moving Coil Galvanometer - NEET MCQ

NCERT Based Test: The Moving Coil Galvanometer - NEET MCQ

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15 Questions MCQ Test NCERTs at Fingertips: Textbooks, Tests & Solutions - NCERT Based Test: The Moving Coil Galvanometer

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NCERT Based Test: The Moving Coil Galvanometer - Question 1

In a moving coil galvanometer the deflection (ϕ) on the scale by a pointer attached to the spring is

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 1

Since magnetic torque on the coil,
τ = NIAB
This torque is balanced by counter torque
∴ kϕ =
where k is torsional constant. It is a scalar quantity having dimension of torque or energy i.e. [ML2T−2]

NCERT Based Test: The Moving Coil Galvanometer - Question 2

Two moving coil meters, M1 and M2 ave thhe following particulars: R1 = 10 Ω, N1 = 30, A1 = 3.6 × 10–3 m2, B1 = 0.25 T R2 = 14 Ω, N2 = 42, A2 = 1.8 × 10–3 m2, B2 = 0.50 T The spring constants are identical for the two meters. What is the ratio of  current sensitivity and voltage sensitivity of M2 and M1.

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 2

For meter M1, R1 = 10 Ω, N1 = 30, A1 = 3.6 × 10–3 m2, B1 = 0.25 T, k= k
For meter M2, R2 = 14 Ω, N2 = 42, A2 = 1.8 × 10–3 m2, B2 = 0.50 T, k2 = k
As, current sensitivity Is = NBA/k.

Voltage sensitivity Vs
So,

= 1

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NCERT Based Test: The Moving Coil Galvanometer - Question 3

If the current sensitivity of a galvanometer is doubled, then its voltage sensitivity will be

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 3

Current sensitivity of galvanometer is deflection per unit current i.e

Similarly voltage sensitivity is deflection per unit voltage
i.e.

From (i) and (ii)
Voltage sensitivity = current sensitivity × 1/resistance
Now if current sensitivity is doubled, then the resistance in the circuit will also be doubled since it is proportional to the length of the wire, then voltage sensitivity

= (current sensitivity) × 1 / (resistance)
Hence, voltage sensitivity will remain unchanged

NCERT Based Test: The Moving Coil Galvanometer - Question 4

A moving coil galvanometer can be converted into an ammeter by:

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 4

To utilise a galvanometer (G) as an ammeter, there is the difficulty in measurement of current due to the sensitivity of galvanometer and also the connection of galvanometer with a very large resistance in series that may change the value of current in the circuit.
To overcome these difficulties one attaches a small resistance rs called shunt resistance in parallel with the galvanometer coil as shown in the figure.

NCERT Based Test: The Moving Coil Galvanometer - Question 5

A galvanometer of resistance 70Ω, is converted to an ammeter by a shunt resistance rs = 0.03Ω. The value of its resistance will become

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 5

Here, RG = 70Ω, rs = 0.03Ω
∴ R =
= 0.02998
= 0.03Ω

NCERT Based Test: The Moving Coil Galvanometer - Question 6

If the galvanometer current is 10mA, resistance of the galvanometer is 40Ω and shunt of 2Ω is connected to the galvanometer, the maximum current which can be measured by this ammeter is

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 6

= 0.21A

NCERT Based Test: The Moving Coil Galvanometer - Question 7

A  galvanometer of resistance 40Ω gives a deflection of 5 divisions per mA. There are 50 divisions on the scale. The maximum current that can pass through it when a shunt resistance of 2Ω is connected is

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 7

IG = 50/5 = 10mA; R= 40Ω, Rs = 2Ω
Maximum current,
I =

= 210 mA

NCERT Based Test: The Moving Coil Galvanometer - Question 8

In the given circuit, a galvanometer with a resistance of 70Ω is converted to an ammeter by a shunt resistance of 0.05Ω total current measured by this device is

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 8

The equivalent circuit of given circuit is given by
Here,

∴ RS = 0.0499Ω = 0.05Ω
The total resistance in the circuit
R = RS + 5Ω = 0.05 + 5 = 5.05Ω
The current measured by the device

= 0.99 A

NCERT Based Test: The Moving Coil Galvanometer - Question 9

A galvanometer having a resistance of 50Ω, gives a full scale deflection for a current of 0.05A. The length (in metres) of a resistance wire of area of cross section 3 × 10−2cm2 that can be used to convert the galvanometer into an ammeter which can read a maximum of 5A current is
(Specific resistance of the wire ρ = 5 × 10−7Ωm)

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 9

∵ S =
∴ l  =
= 3.0m

NCERT Based Test: The Moving Coil Galvanometer - Question 10

The conversion of a moving coil galvanometer into a voltmeter is done by

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 10

Galvanometer is a very sensitive instrument, therefore it can not measure high potential difference.
In order to convert a Galvanometer into voltmeter, a very high resistance known as "series resistance" is connected in series with the galvanometer.

NCERT Based Test: The Moving Coil Galvanometer - Question 11

A galvanometer of resistance 10Ω gives full-scale deflection when 1mA current passes through it. The resistance required to convert it into a voltmeter reading upto 2.5V is

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 11

NCERT Based Test: The Moving Coil Galvanometer - Question 12

A  voltmeter which can measure 2V is constructed by using a galvanometer of resistance 12Ω and that produces maximum deflection for the current of 2mA, then the resistance R is

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 12

Putting V = 2V,
Ig = 2mA
= 2 × 10−3A,
G = 12 Ω,
∴ R= 2 / 2 × 10−3 −12 = 1000 − 12

= 988Ω

NCERT Based Test: The Moving Coil Galvanometer - Question 13

The value of current in the given circuit if the ammeter is a galvanometer with a resistance R= 50Ω is

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 13

Req = Rg +3 = 50 + 3 = 53Ω

NCERT Based Test: The Moving Coil Galvanometer - Question 14

A galvanometer coil has a resistance of 15Ω and the metre shows full scale deflection for a current of 4mA. To convert the meter into a voltmeter of range 0 to 18V, the required resistance is

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 14

The galvanometer can be transformed into a voltmeter by applying a high resistance in series. If the series resistance is R, then total resistance in circuit  = (15 + R)Ω
Now

= 4.5 × 10
∴ R  = 4500−15
= 4485Ω

NCERT Based Test: The Moving Coil Galvanometer - Question 15

A galvanometer of resistance 50Ω is connected to a battery of 3V along with a resistance of 2950Ω in series. A full-scale deflection of 30 divisions is obtained in the galvanometer. In order to reduce this deflection to 20 divisions, the resistance in series should be:

Detailed Solution for NCERT Based Test: The Moving Coil Galvanometer - Question 15

Total initial resistance
= G + R = 50Ω + 2950Ω = 3000Ω
Current,I =

= 1 × 10−3 A = 1mA
If the deflection has to be reduced to 20 divisions, then current

Let x be the effective resistance of the circuit,
3V = 3000Ω × 1mA =
or x =
∴  Resistance to be added =(4500Ω − 50Ω) = 4450Ω

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