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Test: Equilibrium of a Particle (NCERT) - NEET MCQ


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5 Questions MCQ Test NCERTs at Fingertips: Textbooks, Tests & Solutions - Test: Equilibrium of a Particle (NCERT)

Test: Equilibrium of a Particle (NCERT) for NEET 2024 is part of NCERTs at Fingertips: Textbooks, Tests & Solutions preparation. The Test: Equilibrium of a Particle (NCERT) questions and answers have been prepared according to the NEET exam syllabus.The Test: Equilibrium of a Particle (NCERT) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Equilibrium of a Particle (NCERT) below.
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Test: Equilibrium of a Particle (NCERT) - Question 1

A body subiected to three concurrent forces is found to be in equilibrium. The resultant of any two force

Detailed Solution for Test: Equilibrium of a Particle (NCERT) - Question 1

For equilibnum under the effect of the three cuncurrent force all the properties mentioned are required.

Test: Equilibrium of a Particle (NCERT) - Question 2

Three concurrent co-planar forces 1 N, 2 N and 3 N acting along different directions on a body

Detailed Solution for Test: Equilibrium of a Particle (NCERT) - Question 2

If 1 N and 2 N act in same direction and 3 N acts in opposite direction, then equilibrium is possible.

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Test: Equilibrium of a Particle (NCERT) - Question 3


There are four forces acting at a point P produced by strings as shown in figure, which is at rest. The forces F1 and F2, are

Detailed Solution for Test: Equilibrium of a Particle (NCERT) - Question 3

image
Applying equilibrium conditions, ∑Fx = 0
⇒ F1 + 1sin45 − 2sin45 = 0
or F1 = 2sin45 − 1sin45

and ∑Fy= 0
⇒ 1cos45 + 2cos45− F2 = 0
F2

Test: Equilibrium of a Particle (NCERT) - Question 4

A body of mass 10 kg is acted upon by two perpendicular forces, 6 N and 8 N. The resultant acceleration of the body is

Detailed Solution for Test: Equilibrium of a Particle (NCERT) - Question 4

Here, m = 10 kg
The resultant force acting on the body is
F = √(8N)2 + (6N)2 = 10N
Let the resultant force F makes an angle θ w.r.t. 8N force.
From figure, tanθ = 6N/8N = 3/4
The resultant acceleration of the body is

The resulatnt acceleration is along the direction of the resulatnt force.

Hence, the resultant acceleration of the body is 1 ms−2 at an angle of tan−1(3/4) w.r.t. 8N force.

Test: Equilibrium of a Particle (NCERT) - Question 5

A body is moving under the action of two forces . Its velocity will become uniform under a third force F3 given by

Detailed Solution for Test: Equilibrium of a Particle (NCERT) - Question 5

For uniform velocity, acceleration is zero. Hence resultant force will be zero
∴   = 0

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