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Test: Hybridisation (NCERT) - NEET MCQ


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15 Questions MCQ Test NCERTs at Fingertips: Textbooks, Tests & Solutions - Test: Hybridisation (NCERT)

Test: Hybridisation (NCERT) for NEET 2024 is part of NCERTs at Fingertips: Textbooks, Tests & Solutions preparation. The Test: Hybridisation (NCERT) questions and answers have been prepared according to the NEET exam syllabus.The Test: Hybridisation (NCERT) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Hybridisation (NCERT) below.
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Test: Hybridisation (NCERT) - Question 1

Which of the following statements is true about hybridisation?

Detailed Solution for Test: Hybridisation (NCERT) - Question 1

The number of orbitals which hybridise remains same after the hybridisation also, e.g.,

Test: Hybridisation (NCERT) - Question 2

Which of the following molecules is formed by sp2 hybrid orbitals?

Detailed Solution for Test: Hybridisation (NCERT) - Question 2

Formation of BF3

Excited state of B :

 

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Test: Hybridisation (NCERT) - Question 3

Atomic orbitals of carbon in carbon dioxide are

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In the formation of CO2  molecule, hybridization of orbitals of carbon occurs only to a limited extent involving only one s and one p orbital to give rise SP hybridization.

Test: Hybridisation (NCERT) - Question 4

Which type of hybridisation is shown by carbon atoms from left to right in the given compound;
CH2 = CH — C ≡ N?

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Test: Hybridisation (NCERT) - Question 5

On hybridisation of one s and three p-orbitals, we get

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Four sp3 hybrid orbitals are formed when one sand three p-orbitals hybridise.

Test: Hybridisation (NCERT) - Question 6

The molecules like BrF5 and XeOF4 are square pyramidal in shape.What is the type of hybridisation shown in these molecules?

Detailed Solution for Test: Hybridisation (NCERT) - Question 6

BrF5 and XeOF4 have sp3d2  hybridisation
hence their shape is square pyramidal.

Test: Hybridisation (NCERT) - Question 7

Which of the following shows dsp2 hybridisation and a square planar geometry?

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Test: Hybridisation (NCERT) - Question 8

Which of the following pairs are isostructural?

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SO2-4 and BF-4 have sp3 hybridisation and are tetrahedral in shape.

Test: Hybridisation (NCERT) - Question 9

Hybridisation state of Xe in XeF2, XeF4 and XeF6 respectively are

Detailed Solution for Test: Hybridisation (NCERT) - Question 9

Total no. of valence electrons = 22

22/8 = 2(Q) + 6(R), 6/2 = 3(Q)

X = 2+3 = 5

Hybridisation is sp3d.

Hybridisation is sp3d2.
Total no. of electrons in outermost shells = 8 + 28 = 36

36/8 = 4(Q) + 4(R), 4/2 = 2(Q) + 0(R)

X = 4+2 + 0 = 6
hybridisation is sp3d2.

Total no. of valence electrons = 8 + 42 = 50
50/8 = 6(Q) + 2(R), 2/2 = 1(Q), X = 6+1 = 7
hybridisation is sp3d3.

Test: Hybridisation (NCERT) - Question 10

What is the hybrid state of carbon in ethyne, graphite and diamond?

Detailed Solution for Test: Hybridisation (NCERT) - Question 10

In ethyne, H−C≡C−H, C is sp hybridised.
In graphite, one C atom is attached to 3 other C atoms which are sp2 hybridised.

In diamond, one C atom is attached to 4 other C atoms which are sp3 hybridised.

Test: Hybridisation (NCERT) - Question 11

Given below is the bond angle in various types of hybridisation. Mark the bond angle which is not correctly matched.

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In sp3d, the bond angle is 120 and 90.

Test: Hybridisation (NCERT) - Question 12

Order of size of sp, spand sp3 orbitals is

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The percentage of s-character in sp3,sp2 and sp is 25%, 33% and 50% respectively. Order of size of orbitals is sp<sp2<sp3.

Test: Hybridisation (NCERT) - Question 13

Match the column I with column II and mark the appropriate choice.

Detailed Solution for Test: Hybridisation (NCERT) - Question 13

In C2H2,C undergoes, sp hybridisation.

In SF6, Sundergoes sp3d2 hybridisation.

In SF6,S undergoes sp3d2 hybridisation.

In IF7,I undergoes sp3d3 hybridisation

Test: Hybridisation (NCERT) - Question 14

In formation of ethene, the bond formation between s and p-orbitals takes place in the following manner.

Detailed Solution for Test: Hybridisation (NCERT) - Question 14

Test: Hybridisation (NCERT) - Question 15

The ground state electronic configuration of S is 3s23p4. How does it form the compound SF6?

Detailed Solution for Test: Hybridisation (NCERT) - Question 15

S can go into excited state with 6 unpaired electrons due to presence of vacant 3d-orbitals, which are overlapped by six F electrons.

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