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Test: Instantaneous Velocity & Speed - NEET MCQ


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15 Questions MCQ Test Physics Class 11 - Test: Instantaneous Velocity & Speed

Test: Instantaneous Velocity & Speed for NEET 2024 is part of Physics Class 11 preparation. The Test: Instantaneous Velocity & Speed questions and answers have been prepared according to the NEET exam syllabus.The Test: Instantaneous Velocity & Speed MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Instantaneous Velocity & Speed below.
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Test: Instantaneous Velocity & Speed - Question 1

Speedometer of a car measures

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 1

Speedometer of the car measures the instantaneous speed of the car.

Test: Instantaneous Velocity & Speed - Question 2

Speedometer measures the speed of the car in

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 2

Speedometer measures the speed of the car in km h−1.

Test: Instantaneous Velocity & Speed - Question 3

A particle moves with uniform velocity. Which of the following statements about the motion of the particle is true?

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 3

A particle moving with uniform velocity has zero acceleration.

Test: Instantaneous Velocity & Speed - Question 4

The position of an object moving along x-axis is given by x = a + bt2, where a = 8.5 m and b = 2.5 m s−2 and t is measured in seconds. The instantaneous velocity of the object at t = 2 s

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 4

Here, x = a + bt2

Where, a = 8.5m and b = 2.5ms−2

At t = 2s,
v = 2(2.5ms−2)(2s) = 10ms−1

Test: Instantaneous Velocity & Speed - Question 5

The motion of a particle is described by the equation x = at + bt2  where a = 15 cm and b = 3 cm/sec2. Its instantaneous velocity at time 3 sec will be:

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 5

here, x = at + bt2

Given  a = 15 cm b = 3cm/sec-2

at t = 3 s, v = 15 + 2 x 3 x 3 = 33cm s-1

Test: Instantaneous Velocity & Speed - Question 6

The motion of a particle is described by x = x0(1 − e−kt); t ≥ 0; x0 > 0, k > 0. With what velocity does the particle start?

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 6

Test: Instantaneous Velocity & Speed - Question 7

The velocity of the particle at any time t is given by v = 2t(3 − t)m s−1. At what time is its velocity maximum?

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 7

given v = 2t(3 − t) or v = 6t - 2t2

For V maximum or  minimum

Test: Instantaneous Velocity & Speed - Question 8

The motion of a body is given by the equation dv/dt = 6 − 3v where v is the speed in m s−1 and t is time in s. The body is at rest at t = 0. The speed varies with time as

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 8

Integrating both sides, we get

where C is a constant of integration

At t = 0, v = 0

Test: Instantaneous Velocity & Speed - Question 9

The position x of a particle with respect to time t along x-axis is given by x = 9t2 −t3. where x is in metres and t is in seconds. What will be the position of this particle when it achieves maximum speed along the + x direction?

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 9

Given: x = 9t2 − t3

for Maximum speed, dv/dt
= 0 ⇒ 18 - 6t = 0
∴ t = 3s.
∴ xmax = 81m - 27m
= 54 m. (From x = 9t2 - t3)

Test: Instantaneous Velocity & Speed - Question 10

Figure shows the displacement (x) -time (t) graph of the particle moving on the x-axis.

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 10

The displacement-time graph is a straight line inclined to time axis upto time t0 indicates a uniform velocity. After time t0, the displacement-time graph is a straight line parallel to time axis indicates particle at rest.

Test: Instantaneous Velocity & Speed - Question 11

The figure shows the x−t plot of a particle in one-dimensional motion. Two different equal intervals of time are shown. Let v1 and vbe  speed in time intervals 1 and 2 respectively. Then

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 11

The average speed in a small interval of time is equal to the slope of x-t graph during that interval. As slope of interval 1> slope of interval 2

∴ v1 > v2

Test: Instantaneous Velocity & Speed - Question 12

The position-time (x - t) graphs for two children A and B returning from their school O to their homes P and Q respectively are as shown in the figure. Choose the incorrect statement regarding these graphs.

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 12

As OP < OQ, A lives closer to the school than B.

(b) For x = 0, t = 0 for A; while t has some finite value for B. Therefore,

A starts from the school earlier than B.

(c) Slope of x - t graph is equal to the speed. Since the slope of x-t for B is greater than that for A. Therefore, B walks faster than A.

(d) Corresponding to points P and Q the value of t from x - t graphs for A and B is same. Thus, both A and B reach home at the same time.

Test: Instantaneous Velocity & Speed - Question 13

The displacement-time graph of a moving particle is shown below. The instantaneous velocity of the particle is negative at the point

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 13

The slope of the tangent at any point on the displacement-time graph gives instantaneous velocity at that instant. In the given graph, the slope is negative at point E.

Test: Instantaneous Velocity & Speed - Question 14

In the given v-t graph the distance traveled by the body in 5 seconds will be 

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 14

The distance is equal to total area under v-t graph

Test: Instantaneous Velocity & Speed - Question 15

The speed-time graph of a particle moving along a fixed direction is shown in Fig. Obtain the distance traversed by the particle between time  t = 0 s to 10 s.

Detailed Solution for Test: Instantaneous Velocity & Speed - Question 15

Distance = Area under speed-time graph over a given time interval.

∴ Distance traversed by the particle between t = 0 s to t = 10 s will be 

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