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Test: Miscellaneous (NCERT) - NEET MCQ


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10 Questions MCQ Test NCERTs at Fingertips: Textbooks, Tests & Solutions - Test: Miscellaneous (NCERT)

Test: Miscellaneous (NCERT) for NEET 2024 is part of NCERTs at Fingertips: Textbooks, Tests & Solutions preparation. The Test: Miscellaneous (NCERT) questions and answers have been prepared according to the NEET exam syllabus.The Test: Miscellaneous (NCERT) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Miscellaneous (NCERT) below.
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Test: Miscellaneous (NCERT) - Question 1

A giant telescope in an observatory has an objective of focal length 19 m and an eye-piece of focal length 1.0 cm. In normal adjustment, the telescope is used to view the moon. What is the diameter of the image of the moon formed by the objective ? The diameter of the moon is 3.5 × 106 m and the radius of the lunar orbit round the earth is 3.8 × 108 m.

Detailed Solution for Test: Miscellaneous (NCERT) - Question 1

As u ≫ f0 , v = f0 = 19 m.
Now u = -3.8 × 108 m. Therefore, magnification produced by the objective is

∴ Diameter of the image of moon is 3.5 × 106 × 0.5 × 10-7 = 0.175 m = 17.5 cm

Test: Miscellaneous (NCERT) - Question 2

A ray of light travelling in the direction  is incident on a plane mirror. After reflection, it travels along the direction  The angle of incidence is

Detailed Solution for Test: Miscellaneous (NCERT) - Question 2


Let θ be angle between the given rays.

Angle of incidence, 

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Test: Miscellaneous (NCERT) - Question 3

The number of capital letters such as A, B, C, D ..... which are not laterally inverted by a plane mirror?

Detailed Solution for Test: Miscellaneous (NCERT) - Question 3

The number of capital letters which are not laterally inverted by a plane mirror are A, H, I, M, O, T, U, V, W, X, Y.
∴ Total = 11

Test: Miscellaneous (NCERT) - Question 4

Two mirrors at an angle θ produce 5 images of a point. The number of images produced when θ is decreased to θ − 30 is

Detailed Solution for Test: Miscellaneous (NCERT) - Question 4

Number of images = , where θ is in degrees

New angle, θ' = θ - 30 =  60 - 30 = 30 
Number of images = 

Test: Miscellaneous (NCERT) - Question 5

A man stands symmetrically between two large plane mirrors fixed to two adjacent walls of a rectangular room. The number of images formed are

Detailed Solution for Test: Miscellaneous (NCERT) - Question 5

Here, the walls will act as two plane mirrors inclined'to each other at 90(i.e. θ = 90).
The number of images formed is 

Test: Miscellaneous (NCERT) - Question 6

Two plane mirrors M1 and M2 are inclined at angle θ as shown in the figure. A ray of light 1, which is parallel to M1 strikes M2 and after two reflections, the ray 2 becomes parallel to M2​. The angle θ is

Detailed Solution for Test: Miscellaneous (NCERT) - Question 6

Different angles are as shown in figure.

 

In triangle ABC, θ + θ + θ = 180, θ = 60

Test: Miscellaneous (NCERT) - Question 7

Two plane mirrors are placed parallel to each other at a distance L apart. A point object O placed between them, at a distance L/3 from obe mirror. Both mirros form multiple image. The distance between any two images cannot be

Detailed Solution for Test: Miscellaneous (NCERT) - Question 7

Given:
- Two plane mirrors placed parallel to each other at a distance L apart.
- A point object O placed between them, at a distance L/3 from one mirror.
- Both mirrors form multiple images.
We need to find the distance between any two images.
To solve this problem, let's analyze the formation of multiple images:
1. Image Formation:
- When a point object is placed between two parallel mirrors, multiple reflections occur.
- Each mirror produces its own set of images, and the final set of images is formed by the combination of both mirror reflections.
- The number of images formed depends on the distance of the object from each mirror.
2. Distance between Images:
- The distance between any two images formed by the two mirrors can be calculated by considering the path traveled by light rays.
- Let's consider the first mirror reflection and the subsequent reflection from the second mirror.
3. First Mirror Reflection:
- The distance between the object O and the first image formed by the first mirror is L/3.
- The distance between the first image and the second mirror is L - L/3 = 2L/3.
4. Second Mirror Reflection:
- The distance between the second mirror and the first image formed by the first mirror is 2L/3.
- The distance between the second image formed by the second mirror and the second mirror is 2L/3.
5. Total Distance between Images:
- The total distance between any two images formed by the two mirrors is the sum of the distances calculated in the previous steps.
- Total distance = L/3 + 2L/3 + 2L/3 = L + 2L = 3L.
6. Conclusion:
- The distance between any two images formed by the two mirrors is 3L.
- Therefore, the distance between any two images cannot be 3L/2.
- Hence, the answer is A: 3L/2.
Test: Miscellaneous (NCERT) - Question 8

Four identical mirrors are made to stand vertically to form a square arrangement as shown in a top view. A ray starts from the midpoint M of mirror AD and after two reflections reaches corner D. Then, angle θ must be

Detailed Solution for Test: Miscellaneous (NCERT) - Question 8

The ray starting from point M at an angle θ reaches the corner D at the right along a parallel path. Let a be the length of the side.

From figure,

From (i) and (ii), we get

From (ii) and (iii), we get

⇒ 3xy = 2ay (Using (iv))
x = 2a/3
Substituting this value of x in equation (i), we get

or θ = cot−1(0.75)

Test: Miscellaneous (NCERT) - Question 9

Light incident normally on a plane mirror attached to a galvanometer coil reflects backward as shown in figure. A current in the coil produces a deflection of 3.5 of the mirror. The displacement of the reflected spot of light on a screen placed 1.0 m away is

Detailed Solution for Test: Miscellaneous (NCERT) - Question 9

Angle of deflection is θ = 3.5, Distance, between the screen and the mirror is = 2.0m
The reflected rays get deflected by an amount twice the angle of deflection, i.e., 2θ = 7.0 ∴ tan 2θ = d/2
⇒ d = 2 × tan 7
= 2 × 0.1227
= 0.245m
= 24.5cm

Test: Miscellaneous (NCERT) - Question 10

A plane mirror is placed along the x-axis facing negative y-axis. The mirror is fixed. A point object is moving with in front of the plane mirror. The relative velocity of image with respect to its object is

Detailed Solution for Test: Miscellaneous (NCERT) - Question 10

Velocity of object, 
Velocity of image, 

Relative velocity of image with respect to its object


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