Test: Ohm's Law (NCERT) - NEET MCQ

Test: Ohm's Law (NCERT) - NEET MCQ

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Test: Ohm's Law (NCERT) - Question 1

The electrical resistance of a conductor depends upon

Detailed Solution for Test: Ohm's Law (NCERT) - Question 1

The electrical resistance of a conductor is depend upon all factors i.e., size, temperature and geometry of conductor.

Test: Ohm's Law (NCERT) - Question 2

The voltage V and current. I graphs for a conductor at two different temperatures T1 and T2 are shown in the figure. The relation between T1 and T2 is

Detailed Solution for Test: Ohm's Law (NCERT) - Question 2

The slope of V-I graph gives the resistance of a conductor at a given temperature.

From the graph, it follows that resistance of a conductor at temperature T1 is greater than at temperature T2. As the resistance of a conductor is more at higher temperature and less at lower temperature.
Hence T1 >T2.

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Test: Ohm's Law (NCERT) - Question 3

A wire of resistance 4Ω is used to wind a coil of radius 7cm. The wire has a diameter of  1.4mm  and the specific resistance of its material is 2 × 10−7Ωm. The number of turns in the coil is

Detailed Solution for Test: Ohm's Law (NCERT) - Question 3

Let n be the number of turns in the coil. Then total length of wire used,
l = 2πr × n = 2π × 7 × 10−2 × n
Total resistance, R =
or 4 =
∴ n = 70

Test: Ohm's Law (NCERT) - Question 4

A cylindrical rod is reformed to half of its original length keeping volume constant. If its resistance before this change were R, then the resistance after reformation of rod will be

Detailed Solution for Test: Ohm's Law (NCERT) - Question 4

The resistance of rod before reformation

Now the rod is reformed such that

∴   ( ∴ Volume remains constant)
or
Now the resistance of the rod after reformation

∴
or   (using (i))
∴ R2 = R/4

Test: Ohm's Law (NCERT) - Question 5

A wire with 15 Ω resistance is stretched by one tenth of its original length and volume of wire is kept constant. Then its resistance will be

Detailed Solution for Test: Ohm's Law (NCERT) - Question 5

If the wire is stretched by (1/10)th of its original length then the new length of wire become

As the volume of wire remains constant then
⇒
Now the resistance of stretched wire.

∴
= 18.15Ω

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