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Test: Potentiometer (NCERT) - NEET MCQ


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5 Questions MCQ Test NCERTs at Fingertips: Textbooks, Tests & Solutions - Test: Potentiometer (NCERT)

Test: Potentiometer (NCERT) for NEET 2024 is part of NCERTs at Fingertips: Textbooks, Tests & Solutions preparation. The Test: Potentiometer (NCERT) questions and answers have been prepared according to the NEET exam syllabus.The Test: Potentiometer (NCERT) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Potentiometer (NCERT) below.
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Test: Potentiometer (NCERT) - Question 1

In a potentiometer of 10 wires, the balance point is obtained on the 7th wire. To shift the balance point to 9th wire, we should

Detailed Solution for Test: Potentiometer (NCERT) - Question 1

To shift the balance point on higher length, the potential gradient of the wire is to be decreased. The same can be obtained by decreasing the current of the main circuit, which is possible by increasing the resistance in series of potentiometer wire.

Test: Potentiometer (NCERT) - Question 2

AB is a wire of potentiometer with the increase in the value of resistance R, the shift in the balance point J will be

Detailed Solution for Test: Potentiometer (NCERT) - Question 2

Due to increase in resistance R the current through the wire will decrease and hence the potential gradient also decreases, which results in increase in balancing length. So / will shift towards B.

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Test: Potentiometer (NCERT) - Question 3

In a potentiometer a cell of emf 1.5 V gives a balanced point at 32 cm length of the wire. If the cell is replaced by another cell then the balance point shifts to 65.0 cm then the emf of second cell is

Detailed Solution for Test: Potentiometer (NCERT) - Question 3

Here, in the balance condition of potentiometer
ε12 = l1/l2
or  ε= 1.5V , l= 32cm, l2  = 65cm
∴ ε2 = ε1  × l2/l1
= 1.5 × 65/32 = 3.05V

Test: Potentiometer (NCERT) - Question 4

3V poteniometer used for the determination of internal resistance of a 2.4V cell. The balanced point of the cell in open circuit is 75.8cm. When a resistor of 10.2Ω is used in the external circuit of the cell the balance point shifts to 68.3cm length of the potentiometer wire. The internal resistance of the cell is

Detailed Solution for Test: Potentiometer (NCERT) - Question 4

Internal resistance of cell

= 3.05 V
l2 = 68.3cm or 
= 1.12Ω

Test: Potentiometer (NCERT) - Question 5

In a potentiometer the balancing with a cell is at length of 220cm. On shunting the cell with a resistance of 3Ω balance length becomes 130cm. What is the internal resistance of this cell?

Detailed Solution for Test: Potentiometer (NCERT) - Question 5

Here, l1 = 220cm, l2 = 130cm, R = 3Ω
∴ Internal resistance,
r = 
= 2.08Ω

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