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Test: Refraction (NCERT) - NEET MCQ


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10 Questions MCQ Test NCERTs at Fingertips: Textbooks, Tests & Solutions - Test: Refraction (NCERT)

Test: Refraction (NCERT) for NEET 2024 is part of NCERTs at Fingertips: Textbooks, Tests & Solutions preparation. The Test: Refraction (NCERT) questions and answers have been prepared according to the NEET exam syllabus.The Test: Refraction (NCERT) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Refraction (NCERT) below.
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Test: Refraction (NCERT) - Question 1

Which of the following is correct for the beam which enters the medium? 

Detailed Solution for Test: Refraction (NCERT) - Question 1

Since the refractive index is less at beam boundary, the ray at the edges of the beam move faster compared to the axis of beam. Hence the beam converges.

Test: Refraction (NCERT) - Question 2

Refraction of light from air to glass and from air to water are shown in figure (i) and figure (ii) below. The value of the angle θ in the case of refraction as shown in figure (iii) will be

Detailed Solution for Test: Refraction (NCERT) - Question 2

Using Snells law,


⇒ sinθ = sin35 or
θ = 35

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Test: Refraction (NCERT) - Question 3

A ray of light strikes a transparent rectangular slab of refractive index √2 at an angle of incidence of 45°. The angle between the reflected and refracted rays is:

Detailed Solution for Test: Refraction (NCERT) - Question 3

Applying Snell's law at air-glass surface, we get




From figure,
i + θ + 30 = 180 (∵ i = r = 45)
45 + θ + 30 = 180 or
θ = 180 − 75 = 105 
Hence, the angle between reflected and refracted rays is 105

Test: Refraction (NCERT) - Question 4

A ray of light is incident on a thick slab of glass of thickness t as shown in the figure. The emergent ray is parallel to the incident ray but displaced sideways by a distance d. If the angles are small then d is

Detailed Solution for Test: Refraction (NCERT) - Question 4

Lateral shift, 

For small angles
sin(i − r) ≈ i − r; cosr ≈ 1

Test: Refraction (NCERT) - Question 5

A ray incident at a point at an angle of incidence of 60 enters a glass sphere of refractive index √3 and is reflected and refracted at the farther surface of the sphere. The angle between the reflected and refracted rays at this surface is

Detailed Solution for Test: Refraction (NCERT) - Question 5




∴ α = 180o -  (r2′ + i2) = 180o −(30o + 60o) = 90o

Test: Refraction (NCERT) - Question 6

The apparent depth of a needle lying at the bottom of the tank, which is filled with water of refractive index 1.33 to a height of 12.5cm is measured by a microscope to be 9.4cm. If water is replaced by a liquid of refractive index 1.63 upto the same height. What distance would the microscope have to be moved to focus on the needle again?

Detailed Solution for Test: Refraction (NCERT) - Question 6


Here, Real depth = 12.5cm and 

∴ Apparent depth = 12.5/1.63 = 7.67 cm

Now the microscope will have to shift from its initial position to focus 9.4 cm depth object to focus 7.67 cm depth object.
Shift distance = 9.4−7.67
= 1.73 cm

Test: Refraction (NCERT) - Question 7

A point luminous object (O) is at a distance h from the front face of a glass slab of width d and of refractive index μ. On the back face of a slab is a reflecting plane mirror. An observer sees the image of an object in the mirror as shown in the figure. Distance of image from front face as seen by observer will be :

Detailed Solution for Test: Refraction (NCERT) - Question 7


As shown in figure glass slab will form the image of bottom i.e.y mirror MM′ at a depth (d/μ) from its front face. So the distance of object O from virtual mirror mm′ will be h + (d/μ).
Now as a plane mirror forms image behind the mirror at the same distance as the object is in front of it, the distance of image I from mm will be h + (d/μ) and as the distance of virtual mirror from the front face of slab is (d/μ), the distance of image I from front face as seen by

Test: Refraction (NCERT) - Question 8

A vessel of depth x is half filled with oil of refractive index μ1 and the other half is filled with water of refractive index μ2 The apparent depth of the vessel when viewed from above is

Detailed Solution for Test: Refraction (NCERT) - Question 8


∴ Apparent depth of the vessel when viewed from above is

Test: Refraction (NCERT) - Question 9

Three immiscible liquids of densities d1 > d2 > d3 and refractive indices μ1 > μ2 > μ3 are put in a beaker. The height of each liquid column is h/3. A dot is made at the bottom of the beaker. For near normal vision, find the apparent depth of the dot.

Detailed Solution for Test: Refraction (NCERT) - Question 9

Apparent depth of the dot 

Test: Refraction (NCERT) - Question 10

A tank is filled with water to a height of 15.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 upto the same height, by what distance would the microscope have to be moved to focus on the needle again ?

Detailed Solution for Test: Refraction (NCERT) - Question 10

Actual depth of the needle in water
h1 = 15.5cm
Apparent depth of needle in water h2 = 8.5cm
For another liquid with μ' = 1.94
Apparent depth, H = 15.5/1.94 = 7.99cm
Here, H is less than h2. Thus to focus the needle again, the microscope should be moved up by the distance 8.5 − 7.99 = 0.51cm

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