Test: Sulphur Dioxide & Oxoacids of Sulphur - NEET

SO₂​ reacts with O_2​ and H₂​O (water vapour) present in air forming sulphuric acid (H_2​SO₄) causing acid rain.

2SO₂ ​+ O₂​ + 2H₂​O ⟶ 2H₂​SO_4​

In bleaching by SO₂​, H_2​O is important in order to produce nascent hydrogen which is responsible for the bleaching action.

SO₂ ​+ 2H_2​O ⟶ H_2​SO₄​ + 2[H]

The shape of SO₂​  is bent shape  and approximate bond angle is 120 degrees with asymmetric charge distribution on the central atom that is on sulfur. So the given option C is a wrong statement.SO₂​ shape is bent not linear.

Covelency of an atom is the number of covalent bonds that it can form.

While we are finding the maximum covalency of any element  we should check the group of that element in the periodic table.

As sulphur is the element of 16 group elements, so it's maximum covalency is 6 and also in its excited state it has 6 unpaired electrons thus it’s  maximum covalency is 6.EX: In SF_6​ the maximum valency is 6.

The oxyacid of sulphur that contains a lone pair of electrons on sulfur is sulfurous acid H_2​SO_3​ in wich only 4 of ts valence electrons are involved in bonding remaining 2 electrons are remained as a lone pair sulfur(Sulr has six valence electrons).

O.S. of S
Dithionic acid - H₂S₂O₆ = +5
Sulphurous acid - H₂SO₃ = +4
Sulphuric acid - H₂SO₄ = +6
Disulphuric acid - H₂S₂O₇ = +6

Oxidation state of 

2(x)+4(−2) = −2

 2x = 8−2

 2x = 6

x = 3

Oxidation state of

x+3(−2) = −2

 x = 6−2

 x = 4

Oxidation state of 

2(x)+6(−2) = −2

 2x = 12−2

 2x = 10

x = 5

So the oxidation state of sulphur in the anions  follows the order. 

The hybridization of sulfur in H₂​SO_4​ is Sp³ and its shape square planar.

So the given statement H₂​SO_4​−sp² hybridization and V-shaped is wrong shape.