Test: Temperature Dependence of Resistivity (NCERT) - NEET MCQ

# Test: Temperature Dependence of Resistivity (NCERT) - NEET MCQ

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## 5 Questions MCQ Test NCERTs at Fingertips: Textbooks, Tests & Solutions - Test: Temperature Dependence of Resistivity (NCERT)

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Test: Temperature Dependence of Resistivity (NCERT) - Question 1

### The resistance of a heating element is 99Ω at room temperature. What is the temperature of the element if the resistance is found to be 116Ω? (Temperature coefficient of the material of the resistor is 1.7 × 10−4∘C−1)

Detailed Solution for Test: Temperature Dependence of Resistivity (NCERT) - Question 1

Here, R0 = 99Ω, T0 = 27C
RT = 116Ω;
α = 1.710−4∘C−1
∴ R= R[1 + α(T − T0)]
∴ RTR− 1 = α(T − T0)
⇒ 11699 − 1= α(T − T0)

⇒ T = 1010.1 + T0 = 1010.1 + 27

= 1037.1C

Test: Temperature Dependence of Resistivity (NCERT) - Question 2

### The resistance of the wire in the platinum resistance thermometer at ice point is 5Ω and at steam point is 5.25Ω. When the thermometer is inserted in an unknown hot bath its resistance is found to be 5.5Ω. The temperature of the hot bath is

Detailed Solution for Test: Temperature Dependence of Resistivity (NCERT) - Question 2

Here,R0 = 5Ω, R100 = 5.25Ω, Rt = 5.5Ω
As,R1 = R0(1 + αt)
∴R100 = R0(1 + α100)

Equation (i) and (ii), we get

= 200oC

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Test: Temperature Dependence of Resistivity (NCERT) - Question 3

### The resistance of wire in a heater at room temperature is 65Ω. When the heater is connected to a 220V supply the current settles after a few seconds to 2.8A. What is the steady temperature of the wire. (Temperature coefficient of resistance α = 1.70 × 10−4∘C−1)

Detailed Solution for Test: Temperature Dependence of Resistivity (NCERT) - Question 3

Here, T1 = 27C, R1 = 65Ω
R2
= Supply voltage / Steady current
= 220 / 2.8
= 78.6Ω
Now, using the relation
R2 = R1[1 + α(T2 − T1)]
∴

T2 − T1 = 1231
T2 = 1231 + T1 = 1231 + 27
= 1258C

Test: Temperature Dependence of Resistivity (NCERT) - Question 4

A wire has a resistance of 2.5Ω at 28C and a resistance of 2.9Ω at 100C. The temperature coefficient of resistivity of material of the wire is

Detailed Solution for Test: Temperature Dependence of Resistivity (NCERT) - Question 4

Here, R1 = 2.5Ω, T1 = 28C
R2 = 2.9Ω and T= 100C
As R2 = R1[1 + α(T2 − T1)]
∴ 2.9 = 2.5[1 + α(100 − 28)]

= 2.22 × 10−3∘C−1

Test: Temperature Dependence of Resistivity (NCERT) - Question 5

Figure (a) and figure (b) both are showing the variation of resistivity (p) with temperature (T) for some materials. Identify the types of these materials.

Detailed Solution for Test: Temperature Dependence of Resistivity (NCERT) - Question 5

In conductors due to increasein temperature the resistivity increases and in semiconductors if the decreases exponentially.

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