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This mock test of Test: Perimeter And Area - 2 for Class 7 helps you for every Class 7 entrance exam.
This contains 20 Multiple Choice Questions for Class 7 Test: Perimeter And Area - 2 (mcq) to study with solutions a complete question bank.
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QUESTION: 1

The area of triangle is

Solution:

QUESTION: 2

The height in the area of a triangle

Solution:

QUESTION: 3

Find the area of following traingle:

Solution:

Area of triangle= ½ *base*height

=½*4*3=6cm^{2}

QUESTION: 4

A door frame of dimensions 4m * 5m is fixed on the wall of dimension 11m * 11m. Find the total labour charges for painting the wall if the labour charges for painting 1m^{2} of the wall is Rs 2.50.

Solution:

QUESTION: 5

What is the circumference of a circle of diameter 10 cm?

Solution:

QUESTION: 6

Find the breadth of a rectangular plot of land, if its area is 440 m^{2} and the length is 22 m.

Solution:

QUESTION: 7

The ______ is the distance around a given two-dimensional object.

Solution:

QUESTION: 8

If we cut a square along one of its diagonals, two triangles are obtained. Area of each triangle obtained = __________.

Solution:

QUESTION: 9

Solution:

QUESTION: 10

A rectangular garden is 65 cm long and 50 cm wide. Two cross paths each 2 m wide are to be constructed parallel to the sides. If these paths pass through the centre of the garden, find the cost of constructing the paths at the rate Rs. 69 per m^{2}.

Solution:

The rectangular field is in m and not in cms .

One Path have measurements 65cm and 2cm and its area is 65*2=130m^{2}.

Area of the other path is 50*2=100m^{2}. Total area of the path=130+100=230m^{2}.

Now since the middle square has been counted two times so we will subtract it So, total area to be constructed =230-2*2 =230-4= 226m^{2}.

So Total Cost=226*69=Rs. 15594

QUESTION: 11

The figure given below, shows two circles with the same centre. The radius of the larger circle is 10 cm and the radius of the smaller circle is 4 cm. Find the area of the larger circle.

Solution:

Area of larger circle = πr^{2}=3.14*100=314cm^{2}

QUESTION: 12

The figure given below, shows two circles with the same centre. The radius of the larger circle is 10 cm and the radius of the smaller circle is 4 cm. Find the area of the smaller circle.

Solution:

QUESTION: 13

The figure given below, shows two circles with the same centre. The radius of the larger circle is 10 cm and the radius of the smaller circle is 4 cm. Find the shaded area between the two circles.

Solution:

Area of the larger circle = πR^{2 }= 3.14*100=314cm^{2}

Area of smaller circle=r^{2}=3.14*16=50.24cm^{2}

Area of the shaded region=314-50.24=263.76cm^{2}

QUESTION: 14

A wire is in the shape of a square of side 10 cm. If the wire is bent into a rectangle of length 12 cm, find its breadth. Which encloses more area – the square or the rectangle?

Solution:

Since wire is the boundary which will remain same, we will calculate perimeter of both the shapes

Perimeter of square=4*s=4*10=40cm

Perimeter of rectangle=2(l+b)=2(12+b)

Perimeter of square=Perimeter of rectangle

40cm=24+2b

2b=16

b=8cm

Area of square=10*10=100cm^{2}

Area of rectangle=12*8=96cm^{2}

Therefore, the square has more area.

QUESTION: 15

If the area of the triangle is 36 cm^{2} and the height is 3 cm, the base of the triangle will be

Solution:

Area of triangle= ½ *base*height

36=½*base*3

36*2=base*3

base=36*⅔=24cm

QUESTION: 16

The base in the area of triangle is

Solution:

Area of triangle = 1/2base x height

2*area=base x height

base=2*area/height

QUESTION: 17

The distance around a circular region is known as its

Solution:

QUESTION: 18

The perimeter of square of side 2.5 m is

Solution:

QUESTION: 19

The perimeter of rectangle of length 1.5 cm and breadth 2 cm is

Solution:

QUESTION: 20

The area of parallelogram whose base 6 cm and altitude 7 cm is

Solution:

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