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Test: Speed, Time & Distance - 2 - UPSC MCQ


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10 Questions MCQ Test CSAT Preparation - Test: Speed, Time & Distance - 2

Test: Speed, Time & Distance - 2 for UPSC 2024 is part of CSAT Preparation preparation. The Test: Speed, Time & Distance - 2 questions and answers have been prepared according to the UPSC exam syllabus.The Test: Speed, Time & Distance - 2 MCQs are made for UPSC 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Speed, Time & Distance - 2 below.
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Test: Speed, Time & Distance - 2 - Question 1

A Man travelled a distance of 61 km in 9 hours. He travelled partly on foot at 4 km/hr and partly on bicycle at 9 km/hr. What is the distance travelled on foot?

Detailed Solution for Test: Speed, Time & Distance - 2 - Question 1

Let the time in which he travelled on foot = x hour
Time for travelling on bicycle = (9 - x) hr

Distance = Speed * Time, and Total distance = 61 km
So,
4x + 9(9-x) = 61
=> 5x = 20
=> x = 4

So distance traveled on foot = 4(4) = 16 km

Test: Speed, Time & Distance - 2 - Question 2

Walking 6/7th of his usual speed, a man is 12 minutes too late. What is the usual time taken by him to cover that distance?

Detailed Solution for Test: Speed, Time & Distance - 2 - Question 2

Let the distance be x
Let the original speed be y
Time originally taken = distance / speed
That means = x/y
Now the new speed is (6/7)y
And new time is distance /new speed
x/(6/7)y that can be written as 7x/6y
Now new time - original time = 12 min
7x/6y-x/y=12
After subtracting we get
x/y = 12×6
x/y = 72min

Test: Speed, Time & Distance - 2 - Question 3

A man goes to his office from his house at a speed of 3 km/hr and returns at a speed of 2 km/hr. If he takes 5 hours in going and coming, what is the distance between his house and office?

Detailed Solution for Test: Speed, Time & Distance - 2 - Question 3

If the distance between house and office is d km
Then time taken to go from home to office = d/3 hr (Time = Distance/Speed)
and Time taken to come back from office to home= d/2 hr
So total time taken = (d/3 +d/2) hour
But according to question , time taken = 5 hour
so we have
d/3+d/2=5
or (2d+3d)/6= 5
or 5d/6=5
or, d=5 x6/5= 6km
So distance between home and office = 6km

Test: Speed, Time & Distance - 2 - Question 4

A man rides his bicycle 10 km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr. What is his average speed for the entire trip approximately?

Detailed Solution for Test: Speed, Time & Distance - 2 - Question 4

Total Distance = 10 +12 = 22 km
Total time = 10/12 + 12/10 = 5/6 + 6/5 = 25/30 + 36/30 = 61/30 hours
Average speed = 22 /(61/30) = 660/61 = 10.8 km/ hour

Test: Speed, Time & Distance - 2 - Question 5

A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. What is the speed of the car?

Detailed Solution for Test: Speed, Time & Distance - 2 - Question 5

Let the speed of the car be x km/h

So the speed of the train will be 1.5x km/h

According to the question

⇒ 75/x - 75/1.5x = 12.5/60

⇒ (112.5 - 75)/1.5x = 12.5/60

⇒ 37.5/1.5x = 12.5/60

⇒ 1.5x = 37.5 × (60/12.5)

⇒ x = 180/1.5

⇒ x = 120 km/h

∴ The speed of the car is 120 km/h

Test: Speed, Time & Distance - 2 - Question 6

In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. What is the duration of the flight ?

Detailed Solution for Test: Speed, Time & Distance - 2 - Question 6

option "D"

Test: Speed, Time & Distance - 2 - Question 7

If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. What is the actual distance travelled by him?

Detailed Solution for Test: Speed, Time & Distance - 2 - Question 7

Distance he could travelled/speed diff.
= 20/(14-10)
= 20/4
= 5 hrs
Now his actual speed was 10 km/h
Total distance travelled by him = speed × time
= 10 × 5
= 50 km.
 

Test: Speed, Time & Distance - 2 - Question 8

The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, What is the the speed of the first train?

Test: Speed, Time & Distance - 2 - Question 9

It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. What is the ratio of the speed of the train to that of the car?

Test: Speed, Time & Distance - 2 - Question 10

It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. What is the ratio of the speed of the train to that of the car?

Detailed Solution for Test: Speed, Time & Distance - 2 - Question 10

Let the speed of the train be x km/hr and that of the car be y km/hr.
It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car.
120/x + 480/y = 8 or 1/x + 4/y = 1/15
If 200 km is done by train and the rest by car, then 20 minutes more time is taken.
200/x + 400/y = 25/3 or 1/x + 2/y  = 1/24
Solving both the equations,
x = 60 and y = 80
Ratio is 3 : 4

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