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Test: Combination of Cells - NEET MCQ


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10 Questions MCQ Test Physics Class 12 - Test: Combination of Cells

Test: Combination of Cells for NEET 2024 is part of Physics Class 12 preparation. The Test: Combination of Cells questions and answers have been prepared according to the NEET exam syllabus.The Test: Combination of Cells MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Combination of Cells below.
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Test: Combination of Cells - Question 1

If cells are joined in parallel, they have _______.

Detailed Solution for Test: Combination of Cells - Question 1

Components connected in parallel provide alternative pathways for current flow. When cells are connected in parallel, the total voltages that they provide does not change. For example, when two or more 2 V cells are connected in parallel, they still provide a total voltage of 2 V.

Test: Combination of Cells - Question 2

If the internal resistance of a cell is 20 ohm and resistance of the circuit is also 20 ohm. Will the current remain same whether the given n identical cells are in series or in parallel?

Detailed Solution for Test: Combination of Cells - Question 2

In series connection of cells total internal resistance=nr total resistance of circuit=nR current is same potential difference is different so,I=nv/nR+nr I=V/R+r current is same as before in parallel connection of cells total internal resistance=r/n total resistance of circuit=R/n total current=nI potential difference is same nI=V/r/n+R/n I=V/R+r current is same as before.

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Test: Combination of Cells - Question 3

Three identical cells, each of 4 V and internal resistance r, are connected in series to a 6 ohm resistor. If the current flowing in the circuit is 2 A. The internal resistance of each cell is​

Detailed Solution for Test: Combination of Cells - Question 3

Total emf = 3 x 4 = 12 V
Total resistance = 6 + 3r
Current in the circuit = 2 A
Using ohm's law
2 = 12/ (6+3r)
2(6+3r)=12
12+6r=12
6r = 12-12 = 0
r = 0/6 = 0

Test: Combination of Cells - Question 4

When number of identical cells, in parallel combination are increased, the voltage of the circuit will

Detailed Solution for Test: Combination of Cells - Question 4

The voltage developed by the cells in parallel connection cannot be increased by increasing the number of cells present in the circuit. It is because they do not have the same circular path. In parallel connection the connection provides power based on one cell.
The voltage will remain the same.

Test: Combination of Cells - Question 5

In a circuit resistors are connected in series, the value of current through the circuit is

Detailed Solution for Test: Combination of Cells - Question 5

When resistors are connected in series, the current through each resistor
remains the same.
The total voltage across all the resistors is equal to the sum of the
voltages across each resistor.

Test: Combination of Cells - Question 6

If there are n cells of emf E1, E2, …En and of internal resistances r1, r2 …rn , connected in parallel, the combination is equivalent to a cell of emf Eeq such that

Detailed Solution for Test: Combination of Cells - Question 6

Test: Combination of Cells - Question 7

The equivalent emf of two cells (with ε1 > ε2) in series if we connect two negative electrodes of adjacent cells is

Detailed Solution for Test: Combination of Cells - Question 7

When we connect cells to form a battery, we join opposite ends(+ve with -ve and vice versa) to get supporting emf, i.e. net emf get added, but when we join the same polarities(-ve with -ve, like in the question), they oppose each other, hence net emf is the difference b/w them.
The expression for equivalent emf when two cells of emf’s
εeq = ε1 - ε21> ε2)

Test: Combination of Cells - Question 8

The internal resistance of two identical cells, with same current whether joined in series or parallel to a 1Ω resistor is​

Detailed Solution for Test: Combination of Cells - Question 8

1st case[series]
I=E+E/r+r+1-----1
2nd case[parallel]
I=E[E will be same in parallel]/(1/r)+(1/r)+(1/1)----2
Current in both cases are the same.
1=2
2E/2r+1=E/(2/r)+1
R=1 Ω

Test: Combination of Cells - Question 9

If cells are joined in series, they have ________.

Detailed Solution for Test: Combination of Cells - Question 9

In series, cells are joined end to end so that the same current flows through each cell.  In case if the cells are connected in series the emf of the battery is connected to the sum of the emf of the individual cells. Suppose we have multiple cells and they are arranged in such a way that the positive terminal of one cell is connected to the negative terminal of the other and then again the negative terminal is connected to the positive terminal and so on, then we can that the cell is connected in series.

Test: Combination of Cells - Question 10

Three identical cells, each of 2V and internal resistance of 0.2 ohm are connected in series to an external resistance of 7.4 ohm. The current in the circuit will be​

Detailed Solution for Test: Combination of Cells - Question 10

From the Question,

  • Emf (E) = 2 V

  • Internal Resistance (r) = 0.2 Ω

  • Resistance (R) = 7.4 Ω

Three cells of 2V and 0.2 each are connected in series.

Consider two cells connected to each other.

The total potential difference would be :

Total Potential Difference in a cell is given as :

V=E-IR

Thus,

⇒E-Ir=E1-Ir1+E2+Ir2

⇒Eeq=E1+E2 and req=r1+r2

Therefore,

For three cells each of emf 2V,

E=2+2+2=6V

For three cells with internal resistance 0.2 Ω,

R=.02+.02+.02=0.6 Ω

We know that,

I=E/r+R

Implies,

 I=6/0.6+7.4

I=6/8

 I=0.75A

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