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Test: Dual Nature of Matter - NEET MCQ


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Test: Dual Nature of Matter - Question 1

 A photon has energy of 2.6 eV. What is its wavelength?

Detailed Solution for Test: Dual Nature of Matter - Question 1

Given, 2.6 e V = 2.6 X 1.6 X 10-19 J = 4.16 X 10-19 J

Now,by using formula,

Test: Dual Nature of Matter - Question 2

 If uncertainty in the position of an electron is zero, the uncertainity in its momentum would be

Detailed Solution for Test: Dual Nature of Matter - Question 2

Actually, according to uncertainty principle, 

Δx.Δp ≥ h/4π

or Δx.Δp ≈ h/4n 

where, Δx, is uncertainty in position and Δp is uncertainty in momentum. 

So, if Δx = 0 

Hence, uncertainty in momentum Δp = h/4π x 0 = Infinity.

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Test: Dual Nature of Matter - Question 3

Uncertainty in the position of an electron (mass 9.1 x 10-31 kg) moving with a velocity of 300 ms-1, accurate upto 0.001% will be:

Detailed Solution for Test: Dual Nature of Matter - Question 3

Change in position (X),
P= momentum,
P=mv.
X ×P = h/4π.
X× m v = h/4π.
X= h/4πmv.
X=6.625×10-34/4 ×3.14×9.1×10^-31×300.
X=6.625×10-5/342.8.
X=0.0192×10^-5.
X= 19.2× 10-7.
in question it is given to take accurate up to 0.001%.= 1×10-3/100=1 ×10-5.
X= 19.2 ×10-7/10-5.
X=19.2 × 10-2.

Test: Dual Nature of Matter - Question 4

 What experimental result did Albert Einstein cite as evidence that light has particle-like properties?

Detailed Solution for Test: Dual Nature of Matter - Question 4

Einstein's explanation of photoelectric effect using the concept of photons. In 1905, Albert Einstein provided an explanation of the photoelectric effect, an experiment that the wave theory of light failed to explain. He did so by postulating the existence of photons, quanta of light energy with particulate qualities.

Test: Dual Nature of Matter - Question 5

The de Broglie wavelength of a particle is given by.

Detailed Solution for Test: Dual Nature of Matter - Question 5

According to De Broglie, a moving small particle like electron, proton, neutron, dust particle, a small ball etc. has the properties of a wave (Dual nature of matter).

The wave length of a moving particle may be calculated as

λ=h/mv =h/p

De Broglie equation

λ =wave length

h= planck’s constt.

m=mass of particle

v=velocity of particle

p=momentum of the particle

Test: Dual Nature of Matter - Question 6

The de – Broglie wavelength of an electron is 600 nm. The velocity of the electron having the mass 9.1 X 10-31 Kg is

Detailed Solution for Test: Dual Nature of Matter - Question 6

1nm= 10^-9m.
wavelength= 600nm= 600 ×10-9m
wavelength= h/p.
wavelength= h/mv
v= h/ m wavelength
v=6.625×10^-34/9.1×10^-31×600× 10-9.
v= 6.625 × 10+4/9.1 ×6.
v= 6.625× 10+4/9.1×6.
v= 6.625 ×104/54.6.
v= 0.12 × 104.
v= 0.0012 × 10+6 .

Test: Dual Nature of Matter - Question 7

In the relationship ∆x. ∆p =   , ∆p is:

Detailed Solution for Test: Dual Nature of Matter - Question 7

The uncertainty principle is alternatively expressed in terms of a particle’s momentum and position. The momentum of a particle is equal to the product of its mass times its velocity. Thus, the product of the uncertainties in the momentum and the position of a particle equals h/(4π) 

Test: Dual Nature of Matter - Question 8

The uncertainty principle states that

Detailed Solution for Test: Dual Nature of Matter - Question 8

The Heisenberg uncertainty principle states that it is impossible to know simultaneously the exact position and momentum of a particle. That is, the more exactly the position is determined, the less known the momentum, and vice versa. 

Test: Dual Nature of Matter - Question 9

 Whch of the following will have the maximum value of ∆v . ∆x

Detailed Solution for Test: Dual Nature of Matter - Question 9

This is accordance with the Heisenberg's uncertainty principle.It states that it is not possible to accurately determine the position and momentum of a microscopic particle such as electron simultaneously.

Test: Dual Nature of Matter - Question 10

The de Broglie wavelength of an electron is 8.7 x 10-11 m. The mass of an electron is 9.1 x 10-31 kg. The velocity of this electron is:

Detailed Solution for Test: Dual Nature of Matter - Question 10

Wavelength = h/p = h/ mv.
v= h/ m.wavelength
v= 6.625 × 10-34/9.1×10-31 × 8.7 × 10-11
v= 6.625 × 108/ 9.1× 8.7
v= 0.08367 ×108.

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