Test: Forces between Multiple Charges and Electric Field (October 25) - NEET MCQ

# Test: Forces between Multiple Charges and Electric Field (October 25) - NEET MCQ

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## 10 Questions MCQ Test Daily Test for NEET Preparation - Test: Forces between Multiple Charges and Electric Field (October 25)

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Test: Forces between Multiple Charges and Electric Field (October 25) - Question 1

### A force of 2.25 N acts on a charge of 15 x 10-4 C. The intensity of electric field at that point is

Detailed Solution for Test: Forces between Multiple Charges and Electric Field (October 25) - Question 1

Test: Forces between Multiple Charges and Electric Field (October 25) - Question 2

### The dimensional formula of electric intensity is

Detailed Solution for Test: Forces between Multiple Charges and Electric Field (October 25) - Question 2

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Test: Forces between Multiple Charges and Electric Field (October 25) - Question 3

### Three charges of equal magnitude q is placed at the vertices of an equilateral triangle of side l.The force on charge Q placed at the centroid of the triangle is

Detailed Solution for Test: Forces between Multiple Charges and Electric Field (October 25) - Question 3

As shown in figured raw AD ⊥ BC.

Distance AO of the centroid O from A

∴ Force on Q at O due to charge q1 = q at A,

Similarly, force on O due to charge q2 = q at B
along BO and force on Q due to charge q3 = q at c

Angle between forces F2 and F3 = 120°
By parallelogram law, resultant of  along OA
∴ Total force on Q =

Test: Forces between Multiple Charges and Electric Field (October 25) - Question 4

Four point charges are placed at the corners of a square ABCD of side 10 cm, as shown in figure. The force on a charge of 1μC placed at the centre of square is

Detailed Solution for Test: Forces between Multiple Charges and Electric Field (October 25) - Question 4

Forces of repulsion on 1μC charge at O due to 3 μC charge, at A and C are equal and opposite. So they cancel each other.
Similarly, forces of attraction of 1μC charge at O due to -4μC charges at B and D are also equal and opposite. So they also cancel each other.
Hence the net force on the charge of 1μC at O is zero.

Test: Forces between Multiple Charges and Electric Field (October 25) - Question 5

A conducting sphere of radius 10 cm has unknown charge. If the electric field at a distance 20 cm from the centre of the sphere is 1.2 x 103N C-1 and points radially inwards. The net charge on the sphere is

Detailed Solution for Test: Forces between Multiple Charges and Electric Field (October 25) - Question 5

Here, distance of point from the centre of the sphere, r = 20 cm = 0.2m
Electric field, E =  -1.2 x 103 N C-1

Test: Forces between Multiple Charges and Electric Field (October 25) - Question 6

A charge Q is placed at the centre of the line joining two point charges +q and +q as shown in figure. The ratio of charges Q and q is

Detailed Solution for Test: Forces between Multiple Charges and Electric Field (October 25) - Question 6

For the system to be in equilibrium, net force on q = 0 or
or Q = (-q)/4 or Q/q = -(1/4)

Test: Forces between Multiple Charges and Electric Field (October 25) - Question 7

Two charges q and -3q are fixed on x-axis separated by distance d. Where should a third charge 2q be placed from A such that it will not experience any force?

Detailed Solution for Test: Forces between Multiple Charges and Electric Field (October 25) - Question 7

Let a charge 2q be placed at P, at a distance l from A where charge q is placed, as shown in figure.
The charge 2q will not experience any force, when  force of repulsion on it due to q is balanced by force of attraction on it due to -3q at B where AB = d
or
(l + d)2 = 3l2 or 2l2 - 2ld - d2 = 0

If charge 2q is placed between A and B then

Test: Forces between Multiple Charges and Electric Field (October 25) - Question 8

A particle of mass 10-3kg and charge 5μC is thrown at a speed of 20m s-1 against a uniform electric field of strength 2 x 105 N C-1. The distance travelled by particle before coming to rest is

Detailed Solution for Test: Forces between Multiple Charges and Electric Field (October 25) - Question 8

F = qE = 5 x 10-6 x 2 x 105 = 1 N
Since, the particle is thrown against the field
∴ a = -F/m = -(1/10-3) = 103ms-2
As v2 - u2 = 2as
∴ 02 - (20)2 = 2 x (-103) x s or s = 0.2 m

Test: Forces between Multiple Charges and Electric Field (October 25) - Question 9

If the charge on an object is doubled then electric field becomes

Detailed Solution for Test: Forces between Multiple Charges and Electric Field (October 25) - Question 9

As
If q ' = 2q, then E' =  E' = 2E
So electric field is doubled.

Test: Forces between Multiple Charges and Electric Field (October 25) - Question 10

Consider the charges q, q and -q placed at the vertices of an equilateral triangle of each side l. The sum of forces acting on each charge is

Detailed Solution for Test: Forces between Multiple Charges and Electric Field (October 25) - Question 10

From diagram, force on q1(= q) at A,

where  is the unit vector along BC
Force on
(where   is the unit vector along AC)
Force on q3(= -q) at C,

where  unit vector along the direction bisecting ∠BCA

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