Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - NEET MCQ

# Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - NEET MCQ

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## 10 Questions MCQ Test Daily Test for NEET Preparation - Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27)

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Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 1

### Kinetic energy of a rolling object is the

Detailed Solution for Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 1

If an object is rolling without slipping, then its kinetic energy can be expressed as the sum of the translational kinetic energy of its center of mass plus the rotational kinetic energy about the center of mass.

Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 2

### If we apply Newton’s First Law to torque then the statement will be

Detailed Solution for Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 2

Newton's First Law for Rotation: an object at rest tends to remain at rest, and an object that is spinning tends to spin with a constant angular velocity, unless it is acted on by a nonzero net torque or there is a change in the way the object's mass is distributed.

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Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 3

### A torque of 20 Nm is applied to a flywheel of mass 10 kg and radius of gyration 50 cm. The resulting angular acceleration is:

Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 4

A rigid body is rotating about an axis. Different particles are at different distances from the axis. Which of the following is true?

Detailed Solution for Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 4

In the fixed axis rotation we see that every point on the body has two components of velocity, one in the radial direction and one in the tangential direction. The resultant of these velocities is not the same for any two points lying in the plane of the body.
Any two points on the radial line have the radial acceleration directed towards the center of equal magnitude and the tangential acceleration of equal magnitude as well. Thus option B is correct.
All the particles lying on the curved surface of a cylinder whose axis coincides with the axis of rotation have the same speed but different velocities.

Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 5

A ball is under the effect of circular motion about a perpendicular axis with respect to the reference direction. The angular position (in radians) is given by the following function θ = t2 - 0.4t + 2 .The angular position when angular velocity is zero is

Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 6

The angular position of a particle (in radians), along a circle of radius 0.8 m is given by the function in time (seconds) by . The linear velocity of the particle

Detailed Solution for Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 6

So, as we know,
After differentiating angular velocity with respect to t,
Linear velocity=2t+2.3=ω
Now,
Velocity=r x ω(where r is 0.8m)
=0.8x2.3
=1.84m/s

Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 7

Which of the following is not a unit of angular displacement?

Detailed Solution for Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 7

Angular displacement is measured in units of radians. 2 pi radians equals 360 degrees. The angular displacement is not a length (i.e. not measured in meters or feet), so an angular displacement is different than a linear displacement.

Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 8

A boy is playing with a tire of radius 0.5m. He accelerates it from 5rpm to 25 rpm in 15 seconds. The linear acceleration of tire is

Detailed Solution for Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 8

r=0.5m, t=15s
n1=5rpm=5/60 rps
n2=25rpm=25/60rps
As,
a=r∝          [∝=ω2- ω1/t]
so, a=0.5[2π(n2-n1)/t]
a=0.5x6.28x20/60x15
a=6.28x2/60x3
a=6.28/90
a=0.697 m/s2
a≈0.7 m/s2

Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 9

A demo CD, 8 cm in diameter, spins 200 rev/min. Determine its linear velocity in cm/s for a point 3 cm from the center.

Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 10

A wheel rotates with a constant acceleration of 2.0 rad/s2 . If the wheel starts from rest, the number of revolutions it makes in the first ten seconds will be approximately:

Detailed Solution for Test: Kinematics and Dynamics of Rotational Motion about a Fixed Axis (July 27) - Question 10

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