Test: Kinetic Theory (October 14) - NEET MCQ

# Test: Kinetic Theory (October 14) - NEET MCQ

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## 10 Questions MCQ Test Daily Test for NEET Preparation - Test: Kinetic Theory (October 14)

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Test: Kinetic Theory (October 14) - Question 1

### The number of degrees of freedom a diatomic molecule is

Detailed Solution for Test: Kinetic Theory (October 14) - Question 1

A diatomic molecule has 5 degrees of freedoms - 3 translational degrees each in one principal axis and 2 rotational degrees of freedom.

Test: Kinetic Theory (October 14) - Question 2

### A 14.5 kg mass, fastened to the end of a steel wire of unstretched length 1.0 m, is whirled in a vertical circle with an angular velocity of 2 rev/s at the bottom of the circle. The cross-sectional area of the wire is 0.065 cm2. Calculate the elongation of the wire when the mass is at the lowest point of its path.

Detailed Solution for Test: Kinetic Theory (October 14) - Question 2

Mass, m = 14.5 kg
Length of the steel wire, l = 1.0 m
Angular velocity, ω = 2 rev/s = 2 × 2π rad/s = 12.56 rad/s
Cross-sectional area of the wire, a = 0.065 cm2 = 0.065 × 10-4 m2
Let Δl be the elongation of the wire when the mass is at the lowest point of its path.
When the mass is placed at the position of the vertical circle, the total force on the mass is:
F = mg + mlω2
= 14.5 × 9.8 + 14.5 × 1 × (12.56)2
= 2429.53 N
Young’s modulus = Strss / Strain
Y = (F/A) / (∆l/l)
∴ ∆l = Fl / AY
Young’s modulus for steel = 2 × 1011 Pa
∆l = 2429.53 × 1 / (0.065 × 10-4 × 2 × 1011)   =   1.87 × 10-3 m
Hence, the elongation of the wire is 1.87 × 10–3 m
Hence 1.87 × 10–3 m

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Test: Kinetic Theory (October 14) - Question 3

### The number of degrees of freedom a monatomic molecule is

Detailed Solution for Test: Kinetic Theory (October 14) - Question 3

Explanation:Degrees of freedom of a system refers to the possible independent motions a system can have.Monoatomic gas molecule can have 3 independent motion and hence have 3 degrees of freedom (all are translational).

Test: Kinetic Theory (October 14) - Question 4

One mole of an ideal monatomic gas is at an initial temperature of 300 K. The gas undergoes an isovolumetric process, acquiring 500 J of energy by heat. It then undergoes an isobaric process, losing this same amount of energy by heat. Determine the work done on the gas.

Detailed Solution for Test: Kinetic Theory (October 14) - Question 4

Explanation:

At const volume,

Q = 500 J

Q=nCPΔT

500=1×2.5×8.31ΔT

ΔT=24.06

W=nRΔT=1×8.31×24.06=200J

Test: Kinetic Theory (October 14) - Question 5

Mean free path is the

Detailed Solution for Test: Kinetic Theory (October 14) - Question 5

Explanation:the mean free path is the average distance traveled by a moving particle (such as an atom, a molecule, a photon) between successive impacts (collisions), which modify its direction or energy or other particle properties.

Test: Kinetic Theory (October 14) - Question 6

1 mole of a monoatomic gas is mixed with 3 moles of a diatomic gas. What is the molecular specific heat of the mixture at constant volume?

Detailed Solution for Test: Kinetic Theory (October 14) - Question 6

Explanation:

for monoatomic gas

from conservation of energy

Test: Kinetic Theory (October 14) - Question 7

In which case are the atoms relatively rigidly fixed?

Detailed Solution for Test: Kinetic Theory (October 14) - Question 7

Explanation:

Atoms in a gas are well separated with no regular arrangement. Atoms vibrate and move freely at high speeds

Atoms in a liquid are close together with no regular arrangement. Atoms vibrate, move about, and slide past each other.

Atoms in a solid are tightly packed, usually in a regular pattern. Atoms vibrate (jiggle) but generally do not move from place to place.

Test: Kinetic Theory (October 14) - Question 8

The average distance a molecule can travel without colliding is called the

Detailed Solution for Test: Kinetic Theory (October 14) - Question 8

Explanation:the mean free path is the average distance traveled by a moving particle (such as an atom, a molecule, a photon) between successive impacts (collisions), which modify its direction or energy or other particle properties

Test: Kinetic Theory (October 14) - Question 9

In dynamic equilibrium, molecules collide and change their speeds during the collision

Detailed Solution for Test: Kinetic Theory (October 14) - Question 9

Explanation:All collisions between molecules among themselves or between molecules and the walls are elastic. So that total kinetic energy and total momentum is conserved. Also the average properties of gas are remains constant.

Test: Kinetic Theory (October 14) - Question 10

Figure shows plot of PV/T versus P for 1.00x10-3 kg of oxygen gas at two different temperatures. What is the value of PV/T where the curves meet on the y-axis?

Detailed Solution for Test: Kinetic Theory (October 14) - Question 10

PV=nRT

Hence the value of PV/T where the curves meet on the y-axis is 0.26 jK-1

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