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Test: JEE Previous Year Questions- Biomolecules - JEE MCQ


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27 Questions MCQ Test Chemistry for JEE Main & Advanced - Test: JEE Previous Year Questions- Biomolecules

Test: JEE Previous Year Questions- Biomolecules for JEE 2024 is part of Chemistry for JEE Main & Advanced preparation. The Test: JEE Previous Year Questions- Biomolecules questions and answers have been prepared according to the JEE exam syllabus.The Test: JEE Previous Year Questions- Biomolecules MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: JEE Previous Year Questions- Biomolecules below.
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Test: JEE Previous Year Questions- Biomolecules - Question 1

The functional group, which is found in amino acid is - 

[AIEEE-2002]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 1

The answer are option D
The functional group which is found in amino acid is
Amino acids are organic compounds that contain amine (–NH2) and carboxyl (–COOH) functional groups, along with a side chain (R group) specific to each amino acid.

Test: JEE Previous Year Questions- Biomolecules - Question 2

RNA contains -  

[AIEEE-2002]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 2

RNA nucleotides contain ribose sugars while DNA contains deoxyribose and RNA uses predominantly uracil instead of thymine present in DNA.

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Test: JEE Previous Year Questions- Biomolecules - Question 3

Complete hydrolysis of cellulose gives –

[AIEEE-2003]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 3

The correct answer is Option A.
 
Cellulose is a straight chain polysaccharide composed of D-glucose units which are joined by β-glycosidic linkages.
Hence, cellulose on hydrolysis produces only D-glucose units.
 

Test: JEE Previous Year Questions- Biomolecules - Question 4

The reason for double helical structure of DNA is operation of – 

[AIEEE-2003]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 4

The correct answer is option D
The two polynucleotide chains or strands of DNA are linked up by hydrogen bonding between the nitrogenous base molecules of their nucleotide monomers.
 Adenine-Thymine (two hydrogen bonds) and Cytosine-Guanine (three hydrogen bonds).
 

Test: JEE Previous Year Questions- Biomolecules - Question 5

Coordination compounds have great importance in biological systems, In this context which of the following
statements is incorrect ? 

[AIEEE-2004]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 5

Chlorophylls are green pigments in plants and contain magnesium.
They are useful during photosynthesis to store energy in the form of glucose from carbon dioxide and water in presence of sunlight.

Test: JEE Previous Year Questions- Biomolecules - Question 6

Which base is present in RNA but not in DNA ? 

[AIEEE-2004] 

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 6

Uracil is present in RNA and binds to adenine whereas thymine is present in DNA and binds to adenine.

Test: JEE Previous Year Questions- Biomolecules - Question 7

Insulin production and its action in human body are responsible for the level of diabetes. This compound belongs to which of the following categories ?  

[AIEEE-2004]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 7

The correct answer is Option B
A hormone is a class of signaling molecules produced by glands in multicellular organisms that are transported by the circulatory system to target distant organs to regulate physiology and behaviour. Insulin is a hormone which is responsible for the level of sugar in blood and hence maintaining the level of diabetes.

Test: JEE Previous Year Questions- Biomolecules - Question 8

Identify the correct statement regarding enzymes : 

 [AIEEE-2004]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 8

The correct answer is Option D.
 
Enzymes are specific biological catalysts that possess well defined active sites. Enzymes are specific biological catalysts that can normally function at body temperatures (T - 310K).
Enzymes are normally biological catalysts that are very specific in their action.
Enzymes are specific biological catalysts that can be poisoned by using enzyme inhibitors.

Test: JEE Previous Year Questions- Biomolecules - Question 9

In both DNA and RNA, heterocylic base and phosphate ester linkages are at – 

[AIEEE-2005]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 9

Test: JEE Previous Year Questions- Biomolecules - Question 10

The pyrimidine bases present in DNA are –  

[AIEEE 2006]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 10

Pyrimidine is an aromatic heterocyclic organic compound similar to pyridine. In nucleic acids, three types of nucleobases are pyrimidine derivatives: cytosine (C), thymine (T), and uracil (U).

Test: JEE Previous Year Questions- Biomolecules - Question 11

The term anomers of glucose refers to –  

[AIEEE 2006]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 11

The correct answer is option C
Anomers of glucose are cyclic diastereomers (epimers) differing in configuration at C-l, existing in two forms α and β respectively.

Test: JEE Previous Year Questions- Biomolecules - Question 12

The secondary structure of a protein refers to–   

[AIEEE 2007]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 12

The correct answer is option A
 
Secondary structure of proteins involves 
α − helical backbone and β − sheet structures. These structures are formed as a result of H-bonding between different peptide groups.

Test: JEE Previous Year Questions- Biomolecules - Question 13

α-D-(+)-glucose and β-D-(+)-glucose are

[AIEEE 2008]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 13

The correct answer is Option B.
α-D-glucose and  β-D-glucose is example of anomers  
 
An Anomer of a saccharide only differs in its structure at the anomeric carbon. Anomeric carbon being the functional group of the carbohydrate, which is usually the carboxyl group attached to it.
 
Epimeres differ at only one chiral center, not the anomeric carbon.

Test: JEE Previous Year Questions- Biomolecules - Question 14

The two functional groups present in a typical carbohydrate are :  

 [AIEEE 2009]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 14

 Carbohydrate is a polyhydroxy aldehyde or polyhydroxy ketone or any compound which give these on hydrolysis.  group includes aldehydic as well as ketonic group.

Test: JEE Previous Year Questions- Biomolecules - Question 15

Which amino acid is achiral ? 

[AIEEE-2009]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 15

Glycine is the only amino acid with no asymmetric (chiral) carbon because it has two hydrogens attached to alpha carbon.

Test: JEE Previous Year Questions- Biomolecules - Question 16

Biuret test is not given by -

[AIEEE 2010]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 16

Biuret test is given my an amide linkage. We know that it is present in urea, polypeptides and proteins (polypeptides themselves). Carbohydrates do not have any amide linkages.

Test: JEE Previous Year Questions- Biomolecules - Question 17

The presence or absence of hydroxy group on which carbon atom of sugar differentiates RNA and DNA ?

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 17

The correct answer is option B
RNA has a hydroxyl group on the second carbon which is not present in DNA.
Thus, hydroxyl groups on a second carbon atom of the sugar differentiate between RNA and DNA.

Test: JEE Previous Year Questions- Biomolecules - Question 18

Which one of the following statements is correct ?  

[AIEEE-2012]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 18

The simplest member of this group is glycine, where the saturated carbon atom is unsubstituted, rendering it optically inactive. The rest of the 20 most common amino acids are optically active existing as both D and L stereoisomer.

Test: JEE Previous Year Questions- Biomolecules - Question 19

Which of the following compounds can be detected by Molisch’s test ?

 [AIEEE-2012]

Test: JEE Previous Year Questions- Biomolecules - Question 20

Monomers are converted to polymer by –  

[AIEEE-2003]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 20

The correct answer is Option B.

On the basis of mode of polymerization, polymers are two types:- Addition and condensation polymers.
Condensation polymers are formed through a condensation reaction, where molecules join together and lose small molecules as by-products such as water or methanol.
An addition polymer is a polymer that forms by simple linking of monomers without the co-generation of other products.
So, monomers are converted to polymer by condensation reaction between monomers.
 

Test: JEE Previous Year Questions- Biomolecules - Question 21

Nylon threads are made of – 

[AIEEE-2003]

Test: JEE Previous Year Questions- Biomolecules - Question 22

Which of the following is a polyamide ? 

[AIEEE-2005]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 22

The correct answer is option A
Nylon-66 is a polyamide.
Terylene is a polymer formed by polymerization of ethyl alcohol and terpthalic acid and is a polyester. Nylon 6, 6 is a polymer formed by polymerization of hexamethylene diamine and adipic acid and is a polyamide. Teflon is a polymer formed by polymerization of tetra flouro ethylene.

Test: JEE Previous Year Questions- Biomolecules - Question 23

Which of the following is fully fluorinated polymer- 

[AIEEE-2005]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 23

The correct answer is option A
Teflon is a polymer of CF2=CF2.

Test: JEE Previous Year Questions- Biomolecules - Question 24

Bakelite is obtained from phenol by reacting with

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 24

Bakelite is obtained from phenol by reacting with formaldehyde HCHO. It is step growth branched thermosetting co-polymer of phenol and formaldehyde.

Test: JEE Previous Year Questions- Biomolecules - Question 25

Buna-N synthetic rubber is a copolymer of - 

  [AIEEE 2009]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 25

The correct answer is option C
Buna - N is a copolymer of acrylonitrile (H2​C= CH– CN ) and  buta-1,3-diene(H2​C= CH – CH=CH2​).

Test: JEE Previous Year Questions- Biomolecules - Question 26

The species which can best serve as an initiator for the cationic polymerization is 

[AIEEE-2012]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 26

The correct answer is option B
Lewis acid can start the cationic polymerization and AlCl3 is a lewis acid which can be used to generate cations.

Test: JEE Previous Year Questions- Biomolecules - Question 27

Synthesis of each molecule of glucose in photosynthesis involves:

  [AIEEE-2013]

Detailed Solution for Test: JEE Previous Year Questions- Biomolecules - Question 27

The correct answer is option B
The chemical reaction that takes place during photosynthesis is given below:
6CO2​+6H2​O→C6​H12​O2​+6O2​+18ATP+12NADPH
Thus, synthesis of each molecule of glucose involves 18 molecules of ATP

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