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Multiple Choice Questions (MCQs): Nomenclature of Elements - NEET MCQ


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20 Questions MCQ Test Chemistry Class 11 - Multiple Choice Questions (MCQs): Nomenclature of Elements

Multiple Choice Questions (MCQs): Nomenclature of Elements for NEET 2024 is part of Chemistry Class 11 preparation. The Multiple Choice Questions (MCQs): Nomenclature of Elements questions and answers have been prepared according to the NEET exam syllabus.The Multiple Choice Questions (MCQs): Nomenclature of Elements MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Multiple Choice Questions (MCQs): Nomenclature of Elements below.
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Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 1

Consider the following statements with respect to noble metals:
1. Noble metals are found in pure form in nature.
2. Uranium and lead are examples of noble metal.

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 1

The correct answer is 1 only.

Noble metals

  • These metals have high heat resistancehigh corrosion resistancehigh melting points, and unique catalytic properties.
  • They are usually found in nature in their pure form. (Hence, Statement 1 is correct)
  • Gold (Ag), Silver (Ag), Platinum (Pt) and Platinum metals are Noble metals. (Hence, statement 2 is incorrect)
  • Here, Pt, osmium (Os), iridium (Ir), ruthenium (Ru), rhodium (Rh), and palladium (Pd), are collectively called platinum metals. 
  • Because they are so nonreactive, they don't corrode easily. This makes them ideal for jewelry and coins.
Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 2

The element Y having atomic number 12 is

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 2

The correct answer is a metal

 

  • The atomic number is a fundamental property of an element that defines its chemical behavior.
  • It refers to the number of protons present in the nucleus of an atom of the element.
  • The atomic number is unique to each element and is used as a key identifier.
  • By consulting a periodic table, which organizes elements based on their atomic numbers, we find that the element with atomic number 12 is Magnesium.
  • Magnesium, as an alkaline earth metal, is located in Group 2 of the periodic table.
  • It exhibits the typical properties of metals.
  • it is shiny, a good conductor of heat and electricity, malleable, and ductile.
  • It tends to lose electrons in chemical reactions. 
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Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 3

_______  is also known as ‘Oil of Vitriol’.

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 3

The correct answer is Sulphuric acid.

  • Sulfuric acid is the chemical name of ‘oil of vitriol’.
  • Sulfuric acid is a dense, colourless, oily, corrosive liquid.
  • It is one of the most commercially important of all chemicals. 
  • It is prepared industrially by the reaction of water with sulfur trioxide.
  • Vitriol is any of certain hydrated sulfates or sulfuric acid.
  • Uses of Sulphuric acid (H2SO4):
    • In lead storage battery.
    • In the manufacturing of HCl.
    • In the manufacturing of Alum.
    • In the manufacturing of fertilisers,
      drugs, detergents and explosives.
Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 4

For IUPAC nomenclature of elements with atomic number greater than 100, the abbreviation used for digit zero is:

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 4

For IUPAC nomenclature of elements with atomic number greater than 100, the abbreviation used for digit zero is n and name is nil.

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 5

What is the relationship between the number of elements in each period and the number of atomic orbitals available in the energy level that is being filled?

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 5

The number of elements in each period is twice the number of atomic orbitals available in the energy level that is being filled.

Let's understand it by taking the elements of the 4th period.
In the fourth period, there are 18 elements. The types of subshells used in the 4th period are s, p, and d.
Number of orbitals of s subshell = 1
Number of orbitals of p subshell = 3
Number of orbitals of d subshell = 5
Total number of orbitals = 9
The total number of elements is 18 i.e. twice the total number of orbitals.

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 6

Elements in the same group have same:

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 6
  • Elements in the same group have the same number of valence electrons in their outermost shell, hence, have similar properties.
  • Elements in the same period don't have same number of valence electrons, hence, have different properties. But, elements in the same period have same number of shells. 
Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 7

The electronic configuration of an element with atomic number (Z = 11) is 1s2, 2s2, 2p6, 3s1. The symbol of the element is:​

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 7

The atomic number of sodium (Na) is 11. So its electronic configuration is 1s2, 2s2, 2p6, 3s1.

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 8

The 3d transition series starts from which atomic number?

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 8

Transition elements belong to d block and the first transition elements is scandium(whose atomic no. is 21)

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 9

The lanthanide series starts with:

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 9

The lanthanide series starts from cerium and ends in lutetium

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 10

How many orbitals are filled in second period?

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 10

The 4 orbitals filled in second period are one 2s (with 2 electrons) and three 2p (with 6 electrons).

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 11

What is the principal quantum number for second period?

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 11

Principle quantum no is defined as the no of shells an element possesses. Since every element in the 2nd period has 2 shells, therefore, principle quantum no for 2nd period is 2.

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 12

The first period has how many orbitals?

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 12

1st period contains only 2 elements hydrogen and helium having atomic no. 1 and 2 respectively.

The electronic configuration of hydrogen is 1s1 while that of helium is 1s2. Both contain only s subshell. S subshell that only contains 1 orbital i.e. z.

Thus, 1st period has 1 orbital.

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 13

The elements beyond atomic number (Z = 92) are known as:

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 13

The transuranium elements (also known as transuranic elements) are the chemical elements with atomic numbers greater than 92 (the atomic number of uranium). All of these elements are unstable and decay radioactively into other elements.

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 14

The last element of actinoid series is:

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 14

The last element in the actinoid series is lawrencium, Lr.

► Lawrencium: Atomic number is 103 and its electronic configuration is [Rn]5f146d17s2. The most common oxidation state displayed by it is +3; because after losing 3 electrons, it attains stable f14configuration.

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 15

The maximum number of elements present in seventh period of the modern periodic table is:

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 15

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 16

The Latin word commonly used for the digit 9 is:

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 16

The Latin word commonly used for the digit 9 is “enn”. It is abbreviated as “e”.

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 17

What is the maximum number of electrons that can be filled in 3d subshell?

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 17

There are 5 orbitals in a d subshell and each orbital can accommodate 2 electrons. Hence the maximum number of electrons that can be filled in 3d subshell is 10.

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 18

Elements in the same vertical group of the Modern Periodic Table have same:

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 18

The periodic table also has a special name for its vertical columns. Each column is called a group. The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons.

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 19

The distribution of electrons into orbitals of an atom is called its:

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 19
  • The arrangement of electrons in different shells and sub-shells is known as the electronic configuration of a particular element.
  • The electronic configuration diagram represents an element in its ground state or stable state. There are a set of rules to remember while distributing off electrons in different orbits.

How are Electrons Distributed in Different Orbits?: Electronic Configuration

Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 20

The symbol for element with atomic number 111 and name Unununium  is

Detailed Solution for Multiple Choice Questions (MCQs): Nomenclature of Elements - Question 20
  • The element was to be called unununium (with the corresponding symbol of Uuu),a systematic element name as a placeholder, until the element was discovered (and the discovery then confirmed) and a permanent name was decided on.
  • Although widely used in the chemical community on all levels, from chemistry classrooms to advanced textbooks, the recommendations were mostly ignored among scientists in the field, who called it element 111, with the symbol of E111, (111) or even simply 111.
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