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Test: Sulphur Dioxide & Oxoacids of Sulphur - NEET MCQ


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10 Questions MCQ Test Topic-wise MCQ Tests for NEET - Test: Sulphur Dioxide & Oxoacids of Sulphur

Test: Sulphur Dioxide & Oxoacids of Sulphur for NEET 2024 is part of Topic-wise MCQ Tests for NEET preparation. The Test: Sulphur Dioxide & Oxoacids of Sulphur questions and answers have been prepared according to the NEET exam syllabus.The Test: Sulphur Dioxide & Oxoacids of Sulphur MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Sulphur Dioxide & Oxoacids of Sulphur below.
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Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 1

Which of the following is correct representation of reaction of acidified permanganate solution with sulphur dioxide?

Detailed Solution for Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 1

Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 2

Why is sulphur dioxide considered as an air pollutant?

Detailed Solution for Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 2

SO2​ reacts with O2​ and H2​O (water vapour) present in air forming sulphuric acid (H2​SO4) causing acid rain.

2SO2 ​+ O2​ + 2H2​O ⟶ 2H2​SO4​

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Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 3

Dry SO2​ does not bleach dry flowers because:

Detailed Solution for Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 3

In bleaching by SO2​, H2​O is important in order to produce nascent hydrogen which is responsible for the bleaching action.

SO2 ​+ 2H2​O ⟶ H2​SO4​ + 2[H]

Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 4

Which of the following statements is not correct for SO2​ gas?

Detailed Solution for Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 4

The shape of SO2​  is bent shape  and approximate bond angle is 120 degrees with asymmetric charge distribution on the central atom that is on sulfur. So the given option C is a wrong statement.SO2​ shape is bent not linear.

Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 5

Which of the following statements is not correct?

Detailed Solution for Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 5

Covelency of an atom is the number of covalent bonds that it can form.

While we are finding the maximum covalency of any element  we should check the group of that element in the periodic table.

As sulphur is the element of 16 group elements, so it's maximum covalency is 6 and also in its excited state it has 6 unpaired electrons thus it’s  maximum covalency is 6.EX: In SF6​ the maximum valency is 6.

Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 6

The oxyacid of sulphur that contains a lone pair of electrons on sulphur is:

Detailed Solution for Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 6

The oxyacid of sulphur that contains a lone pair of electrons on sulfur is sulfurous acid H2​SO3​ in wich only 4 of ts valence electrons are involved in bonding remaining 2 electrons are remained as a lone pair sulfur(Sulr has six valence electrons).

Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 7

In which of the following sulphur is present in +5 oxidation state?

Detailed Solution for Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 7

O.S. of S
Dithionic acid - H2S2O6 = +5
Sulphurous acid - H2SO3 = +4
Sulphuric acid - H2SO4 = +6
Disulphuric acid - H2S2O7 = +6

Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 8

The oxidation state of sulphur in the anions  follows the order:

Detailed Solution for Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 8

Oxidation state of 

2(x)+4(−2) = −2

 2x = 8−2

 2x = 6

x = 3

Oxidation state of

x+3(−2) = −2

 x = 6−2

 x = 4

Oxidation state of 

2(x)+6(−2) = −2

 2x = 12−2

 2x = 10

x = 5

So the oxidation state of sulphur in the anions  follows the order. 

Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 9

The hybridisation state of the central atom and shape of the molecules is given below. Mark the incorrect combination.

Detailed Solution for Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 9

The hybridization of sulfur in H2​SO4​ is Sp3 and its shape square planar.

So the given statement H2​SO4​−sp2 hybridization and V-shaped is wrong shape.

Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 10

Match the column I with column II and mark the appropriate choice.

Detailed Solution for Test: Sulphur Dioxide & Oxoacids of Sulphur - Question 10

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