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Test: Coordination Compounds - 3 - NEET MCQ


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Test: Coordination Compounds - 3 - Question 1

Which of the following species is not expected to be a ligand?

Detailed Solution for Test: Coordination Compounds - 3 - Question 1

The correct answer is option B
Complexes are formed when ligands donate a pair of electrons to metals. In ammonia, N atom has one lone pair of electrons. Nitrogen donates this lone pair of electrons to protons to form ammonium ion. So NH4+​ ion does not have a lone pair of electrons which it can donate to central metal ions. Hence it cannot behave as a ligand.

Test: Coordination Compounds - 3 - Question 2

A complex cation is formed by Pt(in some oxidation state) with ligands (in proper number so that coordination number of Pt becomes six). Which of the following can be its correct IUPAC name?

Detailed Solution for Test: Coordination Compounds - 3 - Question 2

(A) [Pt(en)(SCN)2 (NH3)2]0 ; it is not ion
(B) [Pt(en)(SCN)2 (NH3)2]2+ ; it should not be platinate
(C) correct name
(D) [Pt(en)2(SCN)2(NH3)2]2+ ; its co-ordination number = 8

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Test: Coordination Compounds - 3 - Question 3

Which of the following is not correctly matched?

Detailed Solution for Test: Coordination Compounds - 3 - Question 3

Sodium(ethylenediaminetetraacetato)chromate(II) and Na2​[Cr(CH3​COO)4​(en)] are not correctly matched.
Sodium(ethylenediaminetetraacetato)chromate(II) is the name of the coordiation compound having formula Na2​[Cr(edta)]
The name of the compound Na2​[Cr(CH3​COO)4​(en)] is sodium tetraacetato(ethylenediamine)chromate(II).

Test: Coordination Compounds - 3 - Question 4

The EAN of metal atoms in [Fe(CO2)(NO+)2] and Co2(CO8) respectively are:

Detailed Solution for Test: Coordination Compounds - 3 - Question 4

Oxidation state of iron in [Fe-2(CO0)2 (NO+)2] = x+2(0) + 2 = 0; x= -2

So EAN = 28 =8=36

Oxidation state of cobalt in Co2(CO)8 = 2x + 8 (-8) = x=0

So Ean = 27 + 1+ 8 = 36

Test: Coordination Compounds - 3 - Question 5

Match the complex ions listed in column-I with the characteristics listed in column-II using the codes given below.

Detailed Solution for Test: Coordination Compounds - 3 - Question 5

Test: Coordination Compounds - 3 - Question 6

Which of the following statements is correct?

Note : NO is three electrons donor

Detailed Solution for Test: Coordination Compounds - 3 - Question 6

Test: Coordination Compounds - 3 - Question 7

All the following complex ions are found to be paramagnetic
P : [FeF6]3- ; Q : [COF6] 3- ; R : [V(H2O)6] 3+ ; S : [Ti(H2O)6]3+
The correct order of their paramagnetic moment (spin only) is

Detailed Solution for Test: Coordination Compounds - 3 - Question 7

Test: Coordination Compounds - 3 - Question 8

Among [NiCl2 (PPh3)2], [Ni(HDMG)2] and [Ni(CO)4] complexes the hybridisation statesof Ni atom are respectively.

Detailed Solution for Test: Coordination Compounds - 3 - Question 8

Test: Coordination Compounds - 3 - Question 9

Amongst [Co(ox)3]3- , [CoF6]3- and [Co(NH3)6]3+

Detailed Solution for Test: Coordination Compounds - 3 - Question 9

Test: Coordination Compounds - 3 - Question 10

All the following complexes show decrease in their weights when placed in a magnetic
balance then the group of complexes having tetrahedral geometry is:
(i) Ni(CO)4

(ii) K[AgF4]

(iii) Na2[Zn(CN)4]

(iv) K2[PlCl4]

( v )[RhCl(PPh3)3]

Detailed Solution for Test: Coordination Compounds - 3 - Question 10

Test: Coordination Compounds - 3 - Question 11

The ‘brown ring’ formed at the junction of two layers in the test of nitrate is due to the formation of a complex ion, [Fe(H2O)5NO]2+. Which of the following statements are correct for this complex [u = 3.87 B.M.)
(i) Oxidation state of Fe is +1 and NO exists as NO+.
(ii) The complex ion is in octahedral geometry as attained by sp3d2 hybridisation.
(iii) The complex is paramagnetic and has three unpaired electrons due to transfer of  electron from NO to Fe2+.
(iv) The complex is in octahedral geometry as attained by d2sp3 hybridisation.
(v) The brown colour of the complex is attributed to d-d transition of electron.

Detailed Solution for Test: Coordination Compounds - 3 - Question 11

Test: Coordination Compounds - 3 - Question 12

Which of the following statements is most likely to be incorrect?

Detailed Solution for Test: Coordination Compounds - 3 - Question 12

Test: Coordination Compounds - 3 - Question 13

Identify the correct order of wavelength of light absorbed for the following complex ions.

Detailed Solution for Test: Coordination Compounds - 3 - Question 13

Test: Coordination Compounds - 3 - Question 14

The possible geometric isomers shown by [Co(en)Br2Cl2]- is:

Detailed Solution for Test: Coordination Compounds - 3 - Question 14

Test: Coordination Compounds - 3 - Question 15

The total number of isomers of the complex, [Co(NH3)4(NO2) 2(NO3) complex is :

Detailed Solution for Test: Coordination Compounds - 3 - Question 15

Test: Coordination Compounds - 3 - Question 16

Which of the following has both face-mer and optical isomers?

Detailed Solution for Test: Coordination Compounds - 3 - Question 16

Test: Coordination Compounds - 3 - Question 17

Statement–1 : In complex [Cr(NH3)4 BrCl]Cl, the ‘spin only’ magnetic moment is close to 1.73 B.M.
Statement–2 : All known mononuclear complexes of chromium(III), irrespective of the strength of the ligand field, must have three unpaired electrons.

Detailed Solution for Test: Coordination Compounds - 3 - Question 17

Test: Coordination Compounds - 3 - Question 18

Statement–1 : The magnitude of for a given ligand increases as the charge on he metal ion increases.
Statement–2 : NH3 is a weak field ligand towards Co2+ but acts as a strong field ligand towards Co3+.

Detailed Solution for Test: Coordination Compounds - 3 - Question 18

As metal ion charge increases the ligands are drawn closer to the metal ion because
of its increased charge density. As the ligands move closer, they cause greater splitting of tghe d-orbital, there by producing a large Δ value.

Test: Coordination Compounds - 3 - Question 19

Statement–1 : tris (ethane-1, 2 – diamine)nickel(II) chloride is homoleptic outer orbital complex
Statement–2 : The geometry of Ni in tris (ethane-1, 2 – diamine)nickel(II) chloride is trigonal bipyramidal

Detailed Solution for Test: Coordination Compounds - 3 - Question 19

Test: Coordination Compounds - 3 - Question 20

Statement–1 : [Ni (H2O)6]2+ is green but a solution of [Ni(CN)4]2- is colourless.
Statement–2 : Energy difference between d levels (i.e. ) for H2 O complex (paramagnetic) is in the visible region and that for the cyano complex (diamagnetic) is in the UV region

Detailed Solution for Test: Coordination Compounds - 3 - Question 20

Cyanide is stronger ligand than water. It causes much higher crystal field splitting. Energy difference between d levels (i.e.)for [Ni(H2O)6]2+ complex (paramagnetic) is in the visible region and that for the [Ni(CN4)]2 complex (diamagnetic) is in the UV region.
Hence, [Ni(H2O)6]2+ forms green color solution whereas [Ni(CN4)]2 forms colorless solution.
 

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