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Test: Equivalent in Terms of Redox Reactions - NEET MCQ


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23 Questions MCQ Test Topic-wise MCQ Tests for NEET - Test: Equivalent in Terms of Redox Reactions

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Test: Equivalent in Terms of Redox Reactions - Question 1
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Direction (Q. Nos. 1-15) This section contains 15 multiple choice questions. Each question has four
choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. As2S3 (yellow precipitate) is soluble in cone. HNO3 as given in unbalanced equation

Equivalent weight in terms of molar mass M of As2S3 is

Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 1


Increase in oxidation number of As2S3, = 28 - 0 = 28

Test: Equivalent in Terms of Redox Reactions - Question 2
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In the following reaction, 2H2S(g) + SO2(g) → 3S(S) + 2H2O (l) One equivalent of H2S (g)will reduce

Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 2


Change in oxidation number of S of H2S = 2 units
Change in oxidation number of S of SO2 = 4 units
Then one mole H2S = 2 equivalents H2S
One mole SO2 = 4 equivalent SO2
One equivalent H23 one equivalent SO2 = 0.25 mole SO2 

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Test: Equivalent in Terms of Redox Reactions - Question 3
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Which has maximum number of equivalents per mole of the oxidant?

Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 3

Oxidant is the oxidising agent (which has been reduced)



Test: Equivalent in Terms of Redox Reactions - Question 4
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Equivalent weight of H3PO2 in a reaction is found to be half of its molecular weight. It can be due to its
Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 4

(a) It is monobasic acid, hence only oneH+ can be neutralised 



Test: Equivalent in Terms of Redox Reactions - Question 5
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KMnO4 (purple) is reduced to K2MnO4 (green) by in basic medium. 1 mole of KMnO4 is reduced by
Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 5


Multiply by change in oxidation number

Test: Equivalent in Terms of Redox Reactions - Question 6
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Equivalent weight of K2Cr2O7 in the following reaction is

(M = molar mass of K2Cr2O7)
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Test: Equivalent in Terms of Redox Reactions - Question 7
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In the following disproportionation of Cl2 in basic medium Cl2 + 2KOH → KCl + KClO + H2O  equivalent mass of Cl2 is
Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 7

In a disproportionation reaction net, equivalent mass = E (oxidation part) + E (reduction part)

Test: Equivalent in Terms of Redox Reactions - Question 8
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One mole of CaOCI2 is dissolved in water and excess of Kl added. Hypo (Na2S2O3) required to react oxidised part completely is
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Test: Equivalent in Terms of Redox Reactions - Question 9
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Consider conversion of MnCI2 into

      
Increasing order of equivalent weights of MnCI2 in these conversions is
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Test: Equivalent in Terms of Redox Reactions - Question 10
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The equivalent weight of MnSO4 is half of its molecular weight when it converts to
Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 10






Test: Equivalent in Terms of Redox Reactions - Question 11
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The number of moles of KMnO4 that will be needed to react with one mole of ferrous oxalate Fe(C2O4) in acidic solution is
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Test: Equivalent in Terms of Redox Reactions - Question 12
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The number of moles of K2Cr2O7 that will be needed to react completely with one mole of ferric sulphite in acidic medium is
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Test: Equivalent in Terms of Redox Reactions - Question 13
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Photosynthesis of carbohydrates in plants takes place as

6CO2 +12H2O   C6H12O6 + 6O2 + 6H2O

Equivalent weight of CO2 and C6H12O6 respectively are 
Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 13


Change in oxidation number = 24 units

Test: Equivalent in Terms of Redox Reactions - Question 14
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Equivalent weight of C6H5CHO is equal to molar mass in the following reaction.

Thus, species {A) is 
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Test: Equivalent in Terms of Redox Reactions - Question 15
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Equivalent w eight of KMnO4 and its reduced species in different mediums are given
Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 15



 

*Multiple options can be correct
Test: Equivalent in Terms of Redox Reactions - Question 16
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Direction (Q. Nos. 16-18) This section contains 4 multiple choice questions. Each question has four
choices (a), (b), (c) and (d), out of which ONE or  MORE THANT ONE  is correct.

Q. Sulphate (IV) ion reduces chromate (VI) to green coloured salt. Thus,
Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 16



Thus, (a) is correct.


*Multiple options can be correct
Test: Equivalent in Terms of Redox Reactions - Question 17
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In which of the following reactions, equivalent mass of the underlined is equal to molar mass?
Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 17





*Multiple options can be correct
Test: Equivalent in Terms of Redox Reactions - Question 18
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NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in acidic medium). Equivalent weight is related to m olecular w eight (M) of NaHC2O4 in these two reactions as
Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 18



Thus, equivalent weight when reacted with NaOH = M

Test: Equivalent in Terms of Redox Reactions - Question 19
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Direction (Q. Nos. 19-20) This section contains a paragraph, wach describing theory, experiments, data etc. three Questions related to paragraph have been given.Each question have only one correct answer among the four given options (a),(b),(c),(d)

Current fuel cells use the reaction of H2(g) and O2(g) to form H2O (/). Often the H2(g)is obtained by steam reforming of a hydrocarbon, such as

A future possibility is a fuel cell that converts a hydrocarbon such as propane directly to CO2(g) and H2O (/)

Q. Difference in equivalent weights of C3H8 based on I and II is
Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 19


(oxidation number of C taking 3C-atoms together) Change in oxidation number of C = 14 units 

(oxidation number of C taking 3C-atoms together) Change in oxidation number of C = 20 units 



(b) From (a), it is clear that (20) electrons are exchanged. Multiply reduction part by (5) and add

Test: Equivalent in Terms of Redox Reactions - Question 20
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Current fuel cells use the reaction of H2(g) and O2(g) to form H2O (/). Often the H2(g)is obtained by steam reforming of a hydrocarbon, such as

A future possibility is a fuel cell that converts a hydrocarbon such as propane directly to CO2(g) and H2O (/)

Q. Select the correct statements about reaction II taking place in acidic medium.
Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 20


(oxidation number of C taking 3C-atoms together) Change in oxidation number of C = 14 units 

(oxidation number of C taking 3C-atoms together) Change in oxidation number of C = 20 units 



(b) From (a), it is clear that (20) electrons are exchanged. Multiply reduction part by (5) and add

Test: Equivalent in Terms of Redox Reactions - Question 21
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Direction (Q. Nos. 21) Choice the correct combination of elements and column I and coloumn II are given as option (a), (b), (c) and (d), out of which ONE option is correct.

Q. Match the reactions of H3PO3 (m olar mass = M)in Column I with the corresponding equivalent mass of H3PO3 in Column II
Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 21





*Answer can only contain numeric values
Test: Equivalent in Terms of Redox Reactions - Question 22
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Direction (Q. Nos. 22 and 23) This section contains 2 questions. when worked out will result in an integer from 0 to 9 (both inclusive)

Q. How many moles of are formed per mole of Mn2+ reacted in the following reaction?

Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 22


Oxidation number of Mn2+ changes from + 2 to + 7 Thus, Mn2+ is oxidised.

In persulphateion , there is one peroxy linkage which is source of oxidation and reduced to oxide.

*Answer can only contain numeric values
Test: Equivalent in Terms of Redox Reactions - Question 23
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In certain laboratory process, it is necessary to remove ions from solution by heating with HNO3. Calculate the moles of HNO3 required by 1 mole of (NH4)2SO4

Detailed Solution for Test: Equivalent in Terms of Redox Reactions - Question 23

is oxidised to N2 and HNO3 is reduced to NO2

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